Put in order from least to greatest. 0.08, -0.38, - 3/5, - 0.04

Answers

Answer 1

Answer: -.38, -0.08 , -.6 or -3/5 ,0.04

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Find the equation of a line containing the points (5,1) and (5,−4).

Answers

Answer:

The equation is x = 5

Answer:

x = 5

Step-by-step explanation:

It is important that face masks used by firefighters be able to withstand high temperatures because firefighters commonly work in temperatures of 200-500 degrees. In a test of one type of mask, 24 of 55 were found to have their lenses pop out at 325 degrees. Construct and interpret a 93% confidence interval for the true proportion of masks of this type whose lenses would pop out at 325 degrees.

Answers

Answer:

The 93% confidence interval for the true proportion of masks of this type whose lenses would pop out at 325 degrees is (0.3154, 0.5574). This means that we are 93% sure that the true proportion of masks of this type whose lenses would pop out at 325 degrees is (0.3154, 0.5574).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{(\pi(1-\pi))/(n)}$

In which

z is the zscore that has a pvalue of $1 - (\alpha)/(2)$ .

For this problem, we have that:

$n = 55, \pi = (24)/(55) = 0.4364$

93% confidence level

So $\alpha = 0.07$ , z is the value of Z that has a pvalue of $1 - (0.07)/(2) = 0.965$ , so $Z = 1.81$ .

The lower limit of this interval is:

$\pi - z\sqrt{(\pi(1-\pi))/(n)} = 0.4364 - 1.81\sqrt{(0.4364*0.5636)/(55)} = 0.3154$

The upper limit of this interval is:

$\pi + z\sqrt{(\pi(1-\pi))/(n)} = 0.4364 + 1.81\sqrt{(0.4364*0.5636)/(55)} = 0.5574$

An object weighs 1 pound on earth weighs about 1/15 pounds on Pluto. If a man weighs 240 pounds on earth how many pounds would he weigh on Pluto?

Answers

Answer:

16 I believe. 240 divided by 15 is 16.

Use Polya's four-step problem-solving strategy and the problem-solving procedures presented in this lesson to solve the following exercise. Find the following sums without using a calculator or a formula. Hint: Apply the procedure used by Gauss. (See the Math Matters on page 31.) (a) 1 + 2 + 3 + 4 + . . . + 397 + 398 + 399 + 400 (b) 1 + 2 + 3 + 4 + . . . + 542 + 543 + 544 + 545 (c) 2 + 4 + 6 + 8 + . . . + 72 + 74 + 76 + 78

Answers

these question give me headache

Final answer:

This answer uses Gauss's method to effectively find the sum of arithmetic series without a calculator or formula. By pairing numbers at the start and end of the series, a constant sum is found which can be easily multiplied by the number of pairs, providing the total sum of series. The sums are 80200, 149238, and 1560 respectively for the given scenarios.

Explanation:

To solve a series of summations without the use of a calculator or formula, we can apply a method used by Gauss. This problem relates to the concept of arithmetic series in mathematics.

Step 1: Understand the problem. We're asked to find the sum of certain series. This involves adding all the numbers in the series together.
Step 2: Devise a plan. The strategy that Gauss used was to pair numbers at the start and end of an arithmetic series. This way, each pair totals the same sum, making it easier to solve.
Step 3: Carry out the plan.
1. (a) Sum of 1 to 400: Pair numbers (1+400, 2+399, 3+398, etc.), every pair equals 401. There're 200 pairs, so 401*200 = 80200.
2. (b) Sum of 1 to 545: Same strategy. Each pair (1 + 545, 2 + 544, 3 + 543, etc.) equals 546. There're 273 pairs, so the sum is 546*273 = 149238.
3. (c) Sum of even numbers from 2 to 78: Notice it is an arithmetic series (2, 4, ...78). The first term a = 2 and last term l = 78. There're 39 terms. By using formula for arithmetic series (n/2)*(a + l), we have (39/2) * (2 + 78) = 1560.
Step 4: Look back. Confirm the plan was executed correctly by reviewing the steps taken.