We have been given that Catherine's employer matches 25% of her 401(k) contributions or a maximum of $2000. Further we are given that Catherine's salary is $50,000 and she contributed $10,000 to her 401(k) plan.
Let the contribution form her employer be $x. We are given that her employer matches 25% of Catherine's contribution under 401(k) plan. Therefore, contribution made by employer would be either 25% of 10,000 or 2000, whichever is lesser.
Let us find 25% of 10,000.
Since 25% of 10,000 is more than 2000, therefore, Catherine's employer would make a contribution of $2000.
please help me
Answer:
x=8
Step-by-step explanation:
We can use the Pythagorean theorem to solve
a^2+b^2 = c^2 where a and b are the legs and c is the hypotenuse
6^2 + x^2 = 10^2
36 + x^2 = 100
Subtract 36 from each side
36-36 +x^2 = 100-36
x^2 = 64
Take the square root of each side
sqrt(x^2) = sqrt(64)
x = 8
Answer:
x = 8
Step-by-step explanation:
According to Pythagorean Theorem
here
Now,
AB =x =8
is so that AP:BP=1:3 and point M is the midpoint of segment
CP
. Find the area of △ABC if the area of △BMP is equal to 21m2.
56 m²
A diagram can be helpful.
Triangles with the same altitude will have areas proportional to the length of their bases.
The altitude from B to PC is the same for triangles BMP and BMC, so they have areas that are in the same proportion as MP : MC. Since M is the midpoint of CP, MP = MC and ABMP = ABMC = 21 m². Then ...
... ACPB = 21 m² + 21 m² = 42 m²
The altitude from C to AB is the same for triangles CPA and CPB, so those triangles have areas in the sampe proportion as AP : BP = 1 : 3. Then ...
... ACPA : ACPB = PA : PB = 1 : 3
... ACPA : 42 m² = 1 : 3
So, the area of ∆CPA is 1/3 of 42 m², or 14 m². The area of ABC is the sum of the areas of CPA and CPB, so is ...
... AABC = ACPA + ACPB = 14 m² + 42 m²
... AABC = 56 m²
Simplify your answer as much as possible.
Answer:
49
Step-by-step explanation:
Answer:
it is 49 for sure
Step-by-step explanation:
it worked for me on khan
-geometry
Answer:
32
Step-by-step explanation:
JL = LG/2 -->
16 = LG/2 -->
32 = LG