jenna''s sixth-grade class is taking a bus to the zoo. the zoo is 156 miles from the school. if the bus travels an average of 55 mi/h, how many seconds will it take to get to the zoo?

Answers

Answer 1

Answer: $V=(s)/(t),\ \ \ \ \ \ \ V-speed,\ s-distance,\ t-time\nt=(s)/(V)\n\nt=(156)/(55)=2,84h=170,4s$

Answer 2

Answer: it will take Jenna's class about 3 hours to arrive to the zoo

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Describe four real-life situations in which you might need to add or subtract decimals.

Answers

If youre a cashier
if youre a mathematician
if you have to pay taxes and bills
if your have to loan something

1. If you're shopping and your total becomes 12.98
2. Calculating measures for your job
3. Measuring for cooking 2.5 (2/5) sugar.
4. If you were a teacher teaching a class :D

Help me find the degree of this polynomial

Answers

Answer:

polynomial of degree 8

Step-by-step explanation:

the degree of a polynomial is the value of the exponent of the term with the largest exponent

given

6 $s^(8)$ + 2 $s^(6)$ - 5s

the term with the largest exponent is 6 $s^(8)$ , with exponent of 8

then the polynomial is of degree 8

Suppose it is found that a certain model of car sells y= -1.6(x-2)^2 + 4.8(x-2) + 16 cars per week, where x is the number of shops selling the car. Make a graph and estimate the best number of shops at which the car should be sold, from the point of view of the manufacturer.

Answers

Answer:

Approximately 4 shops would be the best number of shops which the car is sold, and the number of cars is 20.

Step-by-step explanation:

This is a quadratic function. Therefore, the first thing you need to do is assume some values for x, and then, calculate the value of y, (which would be the number of cars sold). In this way, you can do the graph.

Watch the following attachment, which is a document of excel, showing the graph and some values of x, that I assume

Now, even if you don't have the graph you can estimate the number of shops with the following expression of the summit:

X = -b / 2a

Where:

a: number that goes along with the x elevated.

b: number that goes along with the x, but without being elevated.

In this equation, the first thing we need to do, is rearrange it, that's because we have a (x-2) in the equation, and this could be really annoying.

First let's solve the (x-2)^2

(x-2)^2 = (x-2)(x-2) = x^2 - 2*2x + 2^2 = x^2 - 4x + 4

This is now multiplied by -1.6:

-1.6x^2 + 6.4x - 6.4

Now, multiply 4.8 by x-2:

4.8x - 9.6

Finally, let's arrange this:

-1.6x^2 + 6.4x - 6.4 + 4.8x - 9.6 + 16

-1.6x^2 + 11.2x - 6.4 - 9.6 + 16 = -1.6x^2 + 11.2x

This means that the graph do not have a "y" intercept, and the values of a and b are -1.6 and 11.2, therefore, we can estimate the best number of shops, calculating the summit of the graph (This is because s a quadratic function, and the graph is a parable, and the minimum or maximum point of the graph is reached in the summit)

Summit has X and Y values, the x value is (see formula above):

X = -11.2 / 2 * -1.6 = 3.5

and for the y value, just replace the X value in the equation:

Y = -1.6(3.5)^2 + 11.2(3.5) = -19.6 + 39.2 = 19.6

With this we can conclude that the best number of shops that sells this model of car, is 4 (rounded) and they all sell 20 cars (also rounded). See the graph below in the attachment.

Answer:

The best number of shops at which the car should be sold is 3, from the point of view of the manufacturer.

Step-by-step explanation:

Below we can observe a graph of the function $y = -1.6(x-2)^2 + 4.8(x-2) + 16$ . We have that for x = 3 (blue vertical line) and x = 4 (green vertical line) shops, the manufacturer sells the same number of cars per week y(3) = 19.2 and y(4) = 19.2, and this is the maximum number of car per week that can be sold. Because of operation costs (the less the number of shops, the cheaper the costs), the best number of shops at which the car should be sold from the point of view of the manufacturer is 3.