MATHEMATICS HIGH SCHOOL

Rewrite the fraction in simplest form.
10/50

Answers

Answer 1
Answer:

Answer:

(1)/(5)

Step-by-step explanation:

we have

(10)/(50)

Simplify, divide numerator and denominator by 10

((10/10))/((50/10))=(1)/(5)
Answer 2
Answer:

Simplest form of the fraction is 1/5.

Given,

Fraction : 10/50

Now,

Greatest common factor of 10, 50:

Greatest number which is a factor of 10 and 50 is 10.

So,

Divide numerator and denominator by 10 to simplify the fraction,

⇒(10/10)/(50/10)

⇒ 1/5

Thus the simplified form is 1/5.

Know more about fraction,

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1.Four less than half a number is equal to 37 less than twice the number. a.Translate the sentence into an equation. b.Solve the equation. Show your work.

If f(x)=x^2+3x-10, then f(10)=?

Answers

Answer:

f(10) = 120

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Algebra I

  • Function Notation

Step-by-step explanation:

Step 1: Define

f(x) = x² + 3x - 10

f(10) is x = 10

Step 2: Evaluate

  1. Substitute:                     f(10) = 10² + 3(10) - 10
  2. Exponents:                    f(10) = 100 + 3(10) - 10
  3. Multiply:                         f(10) = 100 + 30 - 10
  4. Add:                               f(10) = 130 - 10
  5. Subtract:                        f(10) = 120

How much greater is the 5 in the hundreds place than the 5 in the tens place

Answers

the five in the hundreds place is 10 times grater than the five in the tenths place 

Find the slope of the line that passes through the two points
(2, 8) and (3, 14)

Answers

The equation of the line that passes through (2, 8) and (3, 14) will be y = 6x - 4.

What is a linear equation?

A connection between a number of variables results in a linear model when a graph is displayed. The variable will have a degree of one.

Let the equation of the line pass through (x₁, y₁) and (x₂, y₂).

Then the equation of the line is given as,

\rm (y - y_2) = \left ((y_2 - y_1)/(x_2 - x_1) \right ) (x - x_2)

The points are given below.

(2, 8) and (3, 14)

The equation of the line that passes through (2, 8) and (3, 14) will be given as,

(y - 8) = [(14 - 8) / (3 - 2)](x - 2)

y - 8 = 6x - 12

y = 6x - 4

The condition of the line that goes through (2, 8) and (3, 14) will be y = 6x - 4.

More about the line passing through two points link is given below.

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Answer:

6

Step-by-step explanation:

The slope is calculated by finding the change in y-coordinates and dividing that by the change in x-coordinates.

The change in y:

8-14=-6

The change in x:

2-3=-1

The slope:

slope=(-6)/(-1) =6

Someone help please someone who is good at geometry!!!!!

Answers

Answer:

22

Step-by-step explanation:

5x-22 and 88 are the same angle so 5x-22=88.

You simply solve from there.

5x=88+22

5x=110

x=110÷5

x=22

Calculate one tenth of an income of $12,347 by dividing by 10. 12.35 123.47 1,234.70 123,470

Answers

Answer: 1,234.70

Step-by-step explanation:

The given amount of income = $12,347

To find :  One tenth of an income of $12,347  

To calculate one tenth of an income of $12,347, we need to divide $12,347 by 10 ,we get

12,347/10\n\n=(12,347 )/(10)\n\n=1,234.7

On dividing a number by ten , we put decimal just before the first digit from the right.

Hence, One tenth of an income of $12,347 = 1,234.70
1,234.70. Hope this helps

1. Find the Least Common Multiple of these two monomials:
See picture

Answers

Answer:

The last choice is correct

LCM=120a^4b^7c^5

Step-by-step explanation:

Least Common Multiple (LCM)

To find the LCM we can follow this procedure:

List the prime factors of each monomial.

Multiply each factor the greatest number of times it occurs in either factor.

We have two monomials:

12a^4b^2c^5

40a^3b^7c^1

The prime factors of the first monomial are:

2^2,3,a^4,b^2,c^5

The prime factors of the second monomial are:

2^3,5,a^3b^7c^1

LCM = Multiply 2^3*3*5*a^4*b^7*c^5

These are all the factors the greatest number of times they occur.

Operating:

LCM=8*15*a^4*b^7*c^5

\boxed{LCM=120a^4b^7c^5}

The last choice is correct
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