Simplify. square root (108 x^5 y^6)

Answers

Answer 1
Answer: \bf √(108x^5y^6)\qquad \begin{cases}108=2\cdot 2\cdot 3\cdot 3\cdot 3\n\qquad 2^2\cdot 3^2\cdot 3\n\qquad (2\cdot 3)^2\cdot 3\n\qquad 6^2\cdot 3\nx^5=x^(4+1)\n\qquad x^4\cdot  x^1\n\qquad x^(2\cdot 2)\cdot x\n\qquad (x^2)^2\cdot x\ny^6=y^(3\cdot 2)\n\qquad (y^3)^2\end{cases}\implies √(6^2\cdot 3\cdot (x^2)^2\cdot x\cdot (y^3)^2)\n\n\n6x^2y^3√(3x)

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Find the slope of the line that contains the points (4,2) and (7,-4)*

Of the last 24 balloons sold at a party store 6 were white. Find the experimental probability that the next balloon sold will be white.

Answers

Answer: 1 out of 4

Step-by-step explanation:

If you divided the total amount of balloons that were sold by the amount of white balloons, it would be 4. The 1 comes from 1 in 4 being the probability of them being white. You can check this by multiplying the 1 and 4 by 6 and it would be 6 out of 24, which shows our answer is correct.

Answer:4/15 i'm doing it and that was the answer

Step-by-step explanation:

I need help ASAP !!!

Answers

Answer:

x = 7.5

Step-by-step explanation:

take 20 degree as reference angle

using cos rule

cos 20 = adjacent / hypotenuse

0.93 = 7/x

x = 7/0.93

x = 7.5

Danielle put 4.902 gallons of gasoline in a gas tank. What is 4.902 written in expanded form?

Answers

4.902

4= ones
9= tenths
0= hundredths
2= thousandths

(SUPER EASY ANSWER QUICK 30 POINTS!)A fish was swimming 3 1/2 feet below the water's surface at 7:00 a.m. Four hours later, the fish was at depth that is 5 1/4 feet below where it was at 7:00 a.m. What rational number represents the position of the fish with respect to the water's surface at 11:00 a.m.?

Answers

(35)/(4) feet below the surface

adding the 2 quantities

3 (1)/(2) + 5 (1)/(4)

= (3 + 5 ) + ((1)/(2) + (1)/(4))

= 8 + ((2)/(4) + (1)/(4))

= 8 + (3)/(4) = 8 (3)/(4) = (35)/(4)


An attacker at the base of a castle wall 4 m high throws a rock straight up with speed 7.5 m/s from a height of 1.5 mabove the ground.
(a) Will the rock exceed the top of the wall?
(b) If so, what is its speed when it reaches the top of the wall?
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(c) If we don’t want the stone to exceed the top of the wall (we want the top of the wall to be the maximum height)
what the initial speed that the stone must have?

Answers

Answer:

a) Yes, b)v\approx 2.686\,(m)/(s), c)v_(o) \approx 7.002\,(m)/(s)

Step-by-step explanation:

a) The maximum height reached by the rock is:

\Delta y = (\left(0\,(m)/(s) \right)^(2)-\left(7.5\,(m)/(s) \right)^(2))/(2\cdot \left(-9.807\,(m)/(s^(2)) \right))

\Delta y = 2.868\,m

y = 1.5\,m + 2.868\,m

y = 4.368\,m

Yes, the rock will exceed the top of the wall.

b) The speed when the rock reaches the top of the wall:

v = \sqrt{\left(7.5\,(m)/(s) \right)^(2)+2\cdot \left(-9.807\,(m)/(s^(2)) \right)\cdot (4\,m-1.5\,m)}

v\approx 2.686\,(m)/(s)

c) The initial speed required so that stone does not exceed the top of the wall is:

v_(o) = \sqrt{\left(0\,(m)/(s) \right)^(2)-2\cdot \left(-9.807\,(m)/(s^(2)) \right)\cdot (4\,m-1.5\,m) }

v_(o) \approx 7.002\,(m)/(s)

In the first quadrant you start at (7,4) and move 4 units left and 3 units up.

Answers

Answer:

(3,7)

Step-by-step explanation:

(7,4)

Moving left and right relates to x

Moving up and down relates to y

When you move to the left, you subtract

When you move to the right, you add

When moving up, you add

When moving down you subtract

X= 7-4 = 3

x=3

Y= 4+3 = 7

y = 7

(3,7)