To solve this, we re using the standard exponential equation:
Also, remember that
We know that our exponential function goes through the points (1, 6) and (2, 12), so we are going to replace the points in our stander exponential equation and solve for and
:
For (1, 6)
and
, so:
equation (1)
For (2, 12)
and
, so:
equation (2)
Replace equation (1) in equation (2) and solve for b
equation (3)
Replace equation (3) in equation (1) to find a
Now we can complete our exponential function:
We can conclude that the exponential function that goes through the points (1, 6) and (2, 12) is
B.10/35 and 7/35
C.7/35 and 5/35
D.24/35 and 12/35
28 m/s is the velocity , when it is going after 4.0 seconds.
When a point or an object moving in a straight line , the acceleration is the rate at which velocity changes with time, in terms of both speed and direction.
Here, given that,
A car is moving at a constant acceleration of 7.0 m/s/s
Now, we have,
Velocity = acceleration * time
After 4 sec. = 7*4 = 28 m/s
Hence, 28 m/s is the velocity , when it is going after 4.0 seconds.
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multiply or divide and then simplify (x+1)^2/(x-5)*(x-3)/(x+1) 3x+3/2 divided by 4/9x+9 4a/3a-3*3(a-1)/16a x+2/x-1 divided by 5x+10/x-2