A rectangle has a perimeter of 18 cm.its length is 5 cm greater than its width.find the dimensions.

Answers

Answer 1

Answer: p=18
l=5 cm greater than the width
w=5 less than the length

USE YOUR NUMBER SENSE!!! - just plug in different number below 4 to figure out the width

3=w 3+5=8 8+8=16+6=22 WILL NOT WORK

2=w 2+5=7 7+7=14 14+2+2= 18 WE HAVE A WINNER!!!!

FInal Answer: width: 2 cm and length: 7 cm

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Write 987% in decimal form

Answers

The decimal would be 9.87

it would be 9.87 good luck

Helene spends 12% of her budget on transportation expenses. Write this percent as a fraction and as a decimal.

Answers

The decimal representation of 12% is 0.12 obtained by dividing the percentage amount by a hundred.

What is the percentage?

A percentage is a value per hundredth. Percentages can be converted into decimals and fractions by dividing the percentage value by a hundred.

We know, 10% is equivalent to (10/100) = 0.1 in terms of decimal representation.

Given, Helene spends 12% of her budget on transportation expenses.

Therefore, The decimal representation of 12% is (12/100) = 0.12.

learn more about percentages here :

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3/25 is the fraction .12 is the decimal

the bbookstore has 60 womrns magazines and 20 other magazin. what percentage of the magazines at the bookstore are womans magazines

Answers

Hi,

Equation for this problem;

$((60 + 20) / 100) * 60 \n (80 / 100) * 60 \n 0.8 * 60 = 48$

Answer: 48%

Hope this helps.
r3t40

Find the product. A.
–16

B.
–4

C.
4

D.
16

Answers

-1/2*-8=4=) Enjoy! (Becuase a negative* a negative equals a positive and 1/2 times a number is half that number.) So it would be C

When you multiply a negative to a negative, you get a positive, so -1/2 x (-8) = 4. :)

What is greater 2yd or 6ft and the other question is 3 ft or 30in

Answers

They are the same. Neither of them is greater than the other.

2yd = 6ft

3ft > 30 in

2 yards is equal to 6 ft

3 feet is greated than 30 inches

For what values of a does the equation a+x= 1+xa^2 have no solution?

Answers

Answer:

We have the equation

$a+x= 1+xa^2$

we leave the terms with x on the left side of the equation and the independent terms on the right side.

$x-xa^2=1-a\n(1-a^2)x=1-a\n$

resolving for x we have that

$x=(1-a)/(1-a^2)$

Since we need that the equation doesn't have solution, then it is necessary that the denominator of x be 0 and this occur when $1-a^2=0\n1=a^2\na=\pm1$

Then, for $a=\pm1$ the equation hasn't solution

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