MATHEMATICS COLLEGE

What is the following product 3 sqrt 5 * sqrt 2

Answers

Answer 1

Answer: the answer is 3 sqrt 10

Answer 2

Answer:

The answer is B

^6 sqrt 200

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If the distance from C to C’ is 8 and the scale factor is 5. What is the distance from A to C? A. 8/5
B. 5/8
C. 10
D. 2

Answers

Answer : B

Explanation:

Use any method to multiply (-14ab)(a + 3b - 4c).

Answers

Answer:

-14a^2b-42ab^2+56abc

Step-by-step explanation:

You can use the FOIL method

multiply the first numbers

then inner

then outer

then last

Is the relationship shown in the table at the right proportional? If so, use it to complete a proportions web. If not, explain why it is not40 Points to whover answers them all

Answers

yes it would be proportional because it goes through the origin

Answer:

yes it would be proportional because it goes through the origin

Step-by-step explanation:

Find the exact values of the six trigonometric functions of given the point (-4, 5) on the terminal side of in standard position.

Answers

Answer:

$\sin(\theta)=5√(41)/41\text{ and } \csc(\theta)=√(41)/5\n\cos(\theta)=-4√(41)/41\text{ and } \sec(\theta)=-√(41)/4\n\tan(\theta)=-5/4\text{ and } \cot(\theta)=-4/5$

Step-by-step explanation:

Please refer to the attached figure.

So, we can see that our angle θ is in QII.

Recall All Students Take Calculus. Since this is QII, we use the Students. In other words, only sine (and cosecant) is positive. So, cosine and tangent are negative.

Now, we also know that a point is (-4,5). Referring to our figure, this means that our adjacent side is 4 (technically -4, but we can ignore this) and our opposite side is 5. So, to find the other ratios, let's find the hypotenuse.

Use the Pythagorean Theorem:

$a^2+b^2=c^2$

Substitute 4 for a and b for 5. Solve for c. So:

$4^2+5^2=c^2$

Square:

$16+25=c^2$

Add:

$c^2=41$

Take the square root:

$c=√(41)$

So, our side lengths are: Opposite=5; Adjacent=4; and Hypotenuse=√41.

Now, we can find our side lengths.

Sine and Cosecant:

$\sin(\theta)=opp/hyp$

Substitute 5 for Opp and √41 for Hyp. So:

$\sin(\theta)=5/√(41)$

Rationalize:

$\sin(\theta)=5√(41)/41$

Since our angle is in QII, sine stays positive.

Cosecant is the reciprocal of sine. So:

$\csc(\theta)=√(41)/5$

Cosine and Secant:

$\cos(\theta)=adj/hyp$

Substitute 4 for Adj and √41 for Hyp:

$\cos(\theta)=4/√(41)$

Rationalize:

$\cos(\theta)=4√(41)/41$

Since our angle is in QII, cosine is negative. So:

$\cos(\theta)=-4√(41)/41$

Secant is the reciprocal of cosine. So:

$\sec(\theta)=-√(41)/4$

Tangent and Cotangent:

$\tan(\theta)=opp/adj$

Substitute 5 for Opp and 4 for Adj. So:

$\tan(\theta)=5/4$

Since our angle is in QII, tangent is negative. So:

$\tan(\theta)=-5/4$

Cotangent is the reciprocal of tangent:

$\cot(\theta)=-4/5$

And we are finished!

Final answer:

Using the given point (-4,5) in standard position, first calculate the radius using the Pythagorean theorem. Then, calculate each of the six trigonometric functions using the coordinates and the calculated radius.

Explanation:

The given point is (-4,5). In the standard position, the x-coordinate represents the cosine of the angle, while the y-coordinate represents the sin of the angle. However, we need to find the radius (r), which can be found using Pythagorean theorem:

r = sqrt(x

+ y

)

meaning, r = sqrt((-4)

+ 5

) = sqrt(41).

Now, each of the six trigonometric functions can be calculated as follows:

Sine (Sin θ = y/r): Sin θ = 5/sqrt(41),
Cosine (Cos θ = x/r): Cos θ = -4/sqrt(41),
Tangent (Tan θ = y/x): Tan θ = -5/4,
Cosecant (Csc θ = r/y): Csc θ = sqrt(41)/5,
Secant (Sec θ = r/x): Sec θ = -sqrt(41)/4,
Cotangent (Cot θ = x/y): Cot θ = 4/5.

Learn more about Trigonometric Functions here:

brainly.com/question/31540769

#SPJ3

Consider the following system of equations:Equation 1: 82 + 2y = 30
Equation 2: 70 + 2y = 24
Which variable pair should we try to eliminate?
The x's because the coefficients are the same.
The y's because the coefficients are the same.
The x's because the coefficients are different?
The y's because the coefficients are different?

Answers

The correct answer is: "The y's because the coefficients are the same."

Further explanation:

we always try to eliminate the variable from the system of equations which involves lesser calculations and complexity.

Assuming that Given equations are:

Equation 1: 82x + 2y = 30

Equation 2: 70x + 2y = 24

we can see that the coefficients of x are very large and different. While the coefficients of y are same. We can only subtract the equations to eliminate y.

Hence,

The correct answer is: "The y's because the coefficients are the same."

Keywords: Linear equations, variables

Learn more about linear equations at:

#LearnwithBrainly

What percent of 68 is 34

Answers

Answer:

Step-by-step explanation:

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