The probability that Jonas will win the race is 0.6 and the probability that he will not win is 0.5.The statement does not make sense because the sum of the probabilities of Jonas winning and not winning the race must equal to 1.

Answers

Answer 1

Answer:

Option B) The statement does not make sense because the sum of the probabilities of Jonas winning and not winning the race must equal = 1

Since the above question says that the probability of Jonas winning the race is = 0.6

And the question says that the probability of Jonas losing the race is = 0.5

If we sum up the probabilities of winning and losing,

Probability = 0.4 + 0.5

= 0.9

Hence, the above situation is not possible because the probability must be = 1.

According to the phenomenon of Probability,

Let us consider two probabilities that are

The winning probability is given = x

The Losing probability is given = y

So, x + y = 1 ( must be 1 )

Therefore, Option B) The statement does not make sense because the sum of the probabilities of Jonas winning and not winning the race must equal = 1

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Decide whether the following statement makes sense (or clearly true) or does not make sense (or is clearly false). Explain your reasoning. The probability that Jonas will win the race is 0.6 and the probability that he will not win is 0.5. Choose the correct answer below.

A. The statement makes sense because it is true that the probability of Jonas not winning the race is

B. The statement does not make sense because the sum of the probabilities of Jonas winning and not winning the race must equal to 1.

C. The statement makes sense because the probability of Jonas winning the race will always be between 0 and 1.

D. The statement does not make sense because the probability of Jonas winning the race cannot be greater than the probability of him not winning the race.

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I need help with my homework

Answers

The value of X=37

hope this helps :)

X= 12^2 + 35^2

= √1369

= 37

Answer:

Step-by-step explanation:

Pythagorean Theorem: a²+b²=c², with a and b being the 2 shortest sides of the triangle, and c being the longest.

a² b² c²

12² + 35² = 1369

Once you have c², you need to find the square root of c² to get c.

The square root of 1369 is 37. c=37

Anyone know this? that box is just when I get the answr

Answers

$\huge\textsf{Hey there!}$

$\mathsf{(1)/(5)*(1)/(2)}$

$= \mathsf{(1*1)/(5*2)}$

$\mathsf{1 * 1 = \boxed{\bold{1}} \leftarrow NUMERATOR\ (TOP\ number)}$

$\mathsf{5*2 = \boxed{\bold{10}} \leftarrow DENOMINATOR\ (BOTTOM \ number) }$

$\mathsf{= (1)/(10)}$

$\boxed{\boxed{\large\textsf{Answer: }\mathsf{\bf (1)/(10)}}}\huge\checkmark$

$\large\textsf{Good luck on your assignment and enjoy your day!}$

~ $\frak{Amphitrite1040:)}$

Answer:

1/10

Step-by-step explanation:

1/5 x 1/2

1/10

Bye , hope this helps!

Give brainliest !

In tilapia, an important freshwater food fish from Africa, the males actively court females. They have more incentive to court a female who has already laid all of her eggs, but can they tell the difference? an experiment was done to measure the male tilapia's response to the smell of female fish. Water containing feces from females that were either pre-ovulatory (they still had eggs) or post-ovulatory (they had already laid their eggs) was washed over the gills of males hooked up to an electro-olfactogram machine which measured when the senses of the males were excited. The amplitude of the electro-olfactogram was used as a measure of the excitability of the males in the two different circumstances. Six males were exposed to the scent of pre-ovulatory females; their readings average 1.51 with a standard deviation of .25. Six different males were exposed to post-ovulatory females; their average readings of 0.87 with standard deviation is .31. Assume that the electro-olfactogram readings were approximately normally distributed within the groups.(A) test for a difference in the excitability of the males with exposure to these two types of females
(B) what is the estimated average difference in electro-olfactogram readings between the two groups? What is the 95% confidnece limit for the difference between population means?

Answers

Answer:

a) $t=\frac{1.51-0.87}{\sqrt{(0.25^2)/(6)+(0.31^2)/(6)}}=3.936$

"=T.INV(1-0.025,10)", and we got $t_(critical)=\pm 2.28$

Statistical decision

Since our calculated value is higher than our critical value, $z_(calc)=3.936>2.28=t_(critical)$ , we have enough evidence to reject the null hypothesis at 5% of significance.

b) $(\bar X_1 -\bar X_2) \pm t_(\alpha/2)\sqrt{(s^2_(1))/(n_(1))+(s^2_(2))/(n_(2))}$

The degrees of freedom are given:

$df = n_1 + n_2 -2 = 6+6-2 = 10$

$(1.51 -0.87) - 2.28\sqrt{(0.25^2)/(6)+(0.31^2)/(6)}= 0.269$

$(1.51 -0.87) + 2.28\sqrt{(0.25^2)/(6)+(0.31^2)/(6)}= 1.010$

Step-by-step explanation:

Part a

Data given and notation

$\bar X_(1)=1.51$ represent the mean for scent of pre ovulatory

$\bar X_(2)=0.87$ represent the mean for post ovolatory

$s_(1)=0.25$ represent the sample standard deviation for preovulatory

$s_(2)=0.31$ represent the sample standard deviation for postovulatory

$n_(1)=6$ sample size for the group preovulatory

$n_(2)=6$ sample size for the group postovulatory

z would represent the statistic (variable of interest)

$p_v$ represent the p value

Concepts and formulas to use

We need to conduct a hypothesis in order to check if the mean's are different, the system of hypothesis would be:

H0: $\mu_(1) = \mu_(2)$

H1: $\mu_(1) \neq \mu_(2)$

If we analyze the size for the samples both are lower than 30, so for this case is better apply a t test to compare means, and the statistic is given by:

$t=\frac{\bar X_(1)-\bar X_(2)}{\sqrt{(s^2_(1))/(n_(1))+(s^2_(2))/(n_(2))}}$ (1)

z-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

Calculate the statistic

We have all in order to replace in formula (1) like this:

$t=\frac{1.51-0.87}{\sqrt{(0.25^2)/(6)+(0.31^2)/(6)}}=3.936$

Find the critical value

We find the degrees of freedom:

$df = n_1 + n_2 -2 = 6+6-2 = 10$

In order to find the critical value we need to take in count that we are conducting a two tailed test, so we are looking for thwo values on the t distribution with df =10 that accumulates 0.025 of the area on each tail. We can us excel or a table to find it, for example the code in Excel is:

"=T.INV(1-0.025,10)", and we got $t_(critical)=\pm 2.28$

Statistical decision

Since our calculated value is higher than our critical value, $z_(calc)=3.936>2.28=t_(critical)$ , we have enough evidence to reject the null hypothesis at 5% of significance.

Part b

For this case the confidence interval is given by:

$(\bar X_1 -\bar X_2) \pm t_(\alpha/2)\sqrt{(s^2_(1))/(n_(1))+(s^2_(2))/(n_(2))}$

The degrees of freedom are given:

$df = n_1 + n_2 -2 = 6+6-2 = 10$

$(1.51 -0.87) - 2.28\sqrt{(0.25^2)/(6)+(0.31^2)/(6)}= 0.269$

$(1.51 -0.87) + 2.28\sqrt{(0.25^2)/(6)+(0.31^2)/(6)}= 1.010$

Help please I don’t get this

Answers

Answer:

$2.35 for one video

Step-by-step explanation:

You set up two equations:

$7.50= p + 2v

$12.20= p + 4v

You then set both equal to p

p=-4v+12.20 and p=-2v+7.50

So you can set them equal to each other and solve for v (the cost of one video)

v= $2.35

PLEASE HELP!!!!!!!!! I NEED IT The angle of elevation from a point on the ground to the top of a tower is 18°. The base of the tower is 100 feet from the point on the ground. Find the height of the tower. Round to the nearest tenth of a foot.

Answers

Answer:

32.5 feet

Step-by-step explanation:

This situation forms a right triangle. We are given the distance from the base of the tower (long leg of the triangle) and are asked to find the height (short leg of the triangle).

With this information, we can use the tan ratio, opposite over adjacent, to find the height of the tower.

tan 18 = $(x)/(100)$

Multiply each side by 100:

(100) tan 18 = x

Simplify and round to the nearest tenth:

32.49 = x

32.5 = x

So, the height of the tower is approximately 32.5 feet

Let a, b, and c be integers. Consider the following conditional statement: If a divides bc, then a divides b or a divides c
Which of the following statements have the same meaning as this conditional statement, which ones are the negations, and which ones are not neither? Justify your answers using logical equivalences or truth tables.
A) If a does not divide b or a does not divide c, then a does not divide bc.
B) If a does not divide b and a does not divide c, then a does not divide bc.
C) If a divides bc and a does not divide c, then a divides b.
D) If a divides bc or a does not divide b, then a divides c. (e) a divides bc, a does not divide b, and a does not divide c.

Answers

Step-by-step explanation:

Given that the logical statement is

"If a divides bc, then a divides b or a divides c"

we can see that a must divide one either b or c from the statement above

A) If a does not divide b or a does not divide c, then a does not divide bc.

This is False because a can divide b or c

B) If a does not divide b and a does not divide c, then a does not divide bc.

this is True for a to divide bc it must divide b or c (either b or c)

C) If a divides bc and a does not divide c, then a divides b.

This is True since a can divide bc and it cannot divide c, it must definitely divide b

D) If a divides bc or a does not divide b, then a divides c.

This is True since a can divide bc and it cannot divide b, it must definitely divide c

E) a divides bc, a does not divide b, and a does not divide c.

This is False for a to divide bc it must divide one of b or c

Statement A is not the same as the original statement.

Statement B is the negation of the original statement.

Statement C is the same as the original statement.

Statement D is not the same as the original statement.

Condition E is not a statement, but a set of conditions without any logical implications.

Given that;

The conditional statement:

If a divides bc, then a divides b or a divides c

A) If a does not divide b or a does not divide c, then a does not divide bc.

This statement is not the same as the original conditional statement.

The original statement states that if a divides bc, then a divides b or a divides c.

However, statement A states the opposite - if a does not divide b or a does not divide c, then a does not divide bc.

So, this is not the same as the original statement.

B) If a does not divide b and a does not divide c, then a does not divide bc.

This statement is actually the negation of the original conditional statement.

The original statement states that if a divides bc, then a divides b or a divides c.

The negation of this statement would be that if a does not divide b and a does not divide c, then a does not divide bc.

So, statement B is the negation of the original statement.

C) If a divides bc and a does not divide c, then a divides b.

This statement is the same as the original conditional statement. It states that if a divides bc and a does not divide c, then a divides b.

This is equivalent to the original statement, which states that if a divides bc, then a divides b or a divides c.

D) If a divides bc or a does not divide b, then a divides c.

This statement is not the same as the original conditional statement.

The original statement states that if a divides bc, then a divides b or a divides c.

However, statement D states that if a divides bc or a does not divide b, then a divides c.

This is a different condition altogether, so it is not equivalent to the original statement.

E) a divides bc, a does not divide b, and a does not divide c.

This is not a statement but rather an additional condition specified.

It describes a scenario where a divides bc, a does not divide b, and a does not divide c.

However, it doesn't provide any logical implications or conclusions like the conditional statements we have been discussing.

Therefore, we get;

Statement A is not the same as the original statement.

Statement B is the negation of the original statement.

Statement C is the same as the original statement.

Statement D is not the same as the original statement.

Condition E is not a statement, but a set of conditions without any logical implications.

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