Start with the equation 4·0=0to explain why 4·−10
must equal −40
. Drag descriptions and equations to the table to complete the explanation.
Start with the equation 4·0=0 to explain why 4·−10 must - 1

Answers

Answer 1
Answer: Step 1 Given. The problem is telling us to start with the equation 4·0=0

Step 2 
Substitute. Any number plus its opposite is zero. Since the opposite of 10 is -10, 10+(-10)= 0:  4(10+-10)=0

Step 3 Use the distributive propertyIn other words multiply 4 by 10 and 4 by -10: 4
·10+4·-10=0

Step 4 Multiply. perform the first multiplication of step 3: 4·10=40, so: 40+4·-10=0

Step 5 Subtract 40 from both sides. 
40-40+4·-10=0-40; simplify the left side: 0+4·-10=0-40 
4·-10=0-40

Step 5 Simplify to solve for 4·-10. Simplify the right side: 4·-10=-40

We can conclude that you should fill your table as follows:
Step 1 Given.  4·0=0
Step 2 Substitute. Any number plus its opposite is zero.   4(10+-10)=0
Step 3 Use the distributive property.    4·10+4·-10=0
Step 4 Multiply. 40+4·-10=0
Step 5 Subtract 40 from both sides.    4·-10=0-40
Step 5 Simplify to solve for 4·-10.        4·-10=-40
Answer 2
Answer:

Answer:

Step 1 Given.  4·0=0

Step 2 Substitute. Any number plus its opposite is zero.   4(10+-10)=0

Step 3 Use the distributive property.    4·10+4·-10=0

Step 4 Multiply. 40+4·-10=0

Step 5 Subtract 40 from both sides.    4·-10=0-40

Step 5 Simplify to solve for 4·-10.        4·-10=-40


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Choose the kind or kinds of symmetry the following figure

Answers

Answer:

i) Line

ii) point

Step-by-step explanation:


Given is a number 3.  We have to find the kind or kinds of symmetry

On seeing 3, we find that no vertical line can divide 3 into exactly two symmetrical figures.

But if we draw a horizontal line in the middle of 3, we get two symmetrical figures up and down the line.

Hence i) symmetric about a line

Next is imaging the middle of 3 end point.

At that point we find that the figure is symmetrical on all sides of the point

Hence there is also a point symmetry

Kinds of symmetry are

i) Line

ii) point

Two parallel lines are graphed on a coordinate plane. How many of the lines could represent proportional relationships?

Answers


Not more than one of them could possibly represent a
proportional relationship. 

A line that graphs a proportional relationship must go through
the origin (0, 0).

Either none or one of the parallel lines can go through the origin. 

The only way that they can both go through the origin is
if they're both actually the same line.

Someone help me on this

Answers

remember you can do antying to an equaitn as long as you do it to both sides
treat as equaiton, but flip sign when dividng or muliplying by negaitve

isolate x
first distribute
7+3x<8(3+x)
7+3x<24+8x
minus 3x both sides
7<24+5x
minus 24 both sides
-17<5x
divide both sides by 5
-17/5<x

A cylindrical pitcher has a volume of 60 cubic inches. Andrea pours lemonade into conical glasses with a diameter of 3 inches and a height of 6 inches. How many glasses of lemonade can be filled by the pitcher?

Answers

Answer:

the answer is 4

Step-by-step explanation:

ok so first find the volume of a cone

the equation for that is 1/3π r²h

so filling in the blanks youd get 1/3π(1.5)²(6)

then I used 3.14 for pi but i got 14.13

then i divided 60 by 14.13 and got 4. something which i then got 4 because its asking for full cups

hope this helped someone!

List the following instruments in order from lowest sound to highest.Tuba bassoon trumpet flute

Answers

Answer:

Tuba, bassoon, trumpet, flute

Step-by-step explanation:

I know this because I was in a junior symphony!

I hope this helps!

p.s. any other questions? Post the question and comment the link below!

♥, Sadie

14/20 minus 3/5 equals

Answers

(14)/(20)-(3)/(5)=(14:2)/(20:2)-(3)/(5)=(7)/(10)-(3)/(5)=(7)/(10)-(3\cdot2)/(5\cdot2)=(7)/(10)-(6)/(10)=(7-6)/(10)=(1)/(10)



(14)/(20)=(14:2)/(20:2)=(7)/(10)=0.7\n\n(3)/(5)=(3\cdot2)/(5\cdot2)=(6)/(10)=0.6\n\n(14)/(20)-(3)/(5)=0.7-0.6=0.1
the answer for this question is 0.1
but as fraction is 14/20 - 3/5 = 1/4 or as a decimal .1