MATHEMATICS HIGH SCHOOL

A notebook costs $4.50 plus sales tax.after sales tax,the notebook is $4.86 what is the sales tax rate

Answers

Answer 1

Answer:

The Rate of Notebook Sales Tax is 8%.

What is sales Tax?

Sales Tax is a "consumption tax imposed by the Government on the sales of Goods and Services".

According to the question,

Cost of Notebook before tax = $ 4.50

Cost of Notebook after tax = $4.86

Formula for Rate of sales tax = (Cost of Notebook before tax -Cost of Notebook after tax ) divided by Cost of Notebook before tax.

Rate of sales tax = (4.50 - 4.86) ÷ 4.50

= 0.08.

converting into Percentage, multiply 0.08 into 100

= 0.08 × 100

= 8%.

Hence, rate of sales tax of note book is 8%.

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Answer 2

Answer: The sales tax rate would be 8%.

To find how much you spent on tax in the total, you'd begin by subtracting the pre-tax notebook from the after tax notebook.

4.86 - 4.50 = 0.36

So now we know that you spent 36 cents on tax. From there, we'd divide our money spent on tax by our pre-tax total.

0.36 ÷ 4.50 = 0.08

This means that the sales tax is 8%.

Hope I could help!

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If 3n + 2 = 14, what must 3n be equal to?
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Solve the equation 3x + 6y = 18 for y

How would i solve 4x-3y=8
5x-2y=-11

using the elimination method?
i'm in algebra 1 and we had a sub the day we were doing this and he was terrible explaining the situations on the worksheet. please explain

Answers

To use the elimination method, the coefficient of one variable in one equation must be the opposite number of the coefficient of the same variable in the second equation.

$4x-3y=8 \n5x-2y=-11$

Here you can multiply the first equation by 2, and the second equation by -3.

$4x-3y=8 \ \ |\cdot 2 \n5x-2y=-11 \ \ |\cdot (-3) \n \n8x-6y=16 \n-15x+6y=33$

Now you just add the equations by sides and solve for one variable.

$8x-6y=16 \n \underline{-15x+6y=33 } \n8x-6y-15x+6y=16+33 \n8x-15x=16+33 \n-7x=49 \nx=-7$

Now you solve for the other variable by substituting -7 for x in one of the equations.

$4x-3y=8 \n4 \cdot (-7)-3y=8 \n-28-3y=8 \n-3y=8+28 \n-3y=36 \ny=-12$

You could choose x at the beginning as well. Then you'd have:
$4x-3y=8 \ \ |\cdot (-5)\n5x-2y=-11 \ \ |\cdot 4 \n \n-20x+15y=-40 \n\underline{20x-8y=-44 \ \ \ \ \ \ } \n-20x+15y+20x-8y=-40-44 \n15y-8y=-40-44 \n7y=-84 \ny=-12 \n \n4x-3y=8 \n4x-3 \cdot (-12)=8 \n4x+36=8 \n4x=8-36 \n4x=-28 \nx=-7$

So the answer is:
$x=-7 \n y=-12$

Answer:

x=-7 and y=-12

Step-by-step explanation:

The hardcover version of a book weighs twice as much as its paperback version. The hardcover book and the paperback together weigh 4.2 pounds. Which system of equations can be used to find h, the weight of the hardcover book, and p, the weight of the paperback?

Answers

If the weight of hardcover version is double the weight of paperback version then weight of hardcover version is 2.8 pounds and the weight of paperback version is 1.4 pounds.

What is equation?

An equation is a relationship between variables in equal to form. It is evaluated to find the values of variables.

How to solve an equation?

The weight of hardcover book is h

The weight of paperback version is p.

According to question:

h=2p (weight of hardcover version is double the weight of paperback version)

h+ p= 4.2 (weight of hardcover version and weight of paperback version is equal to 4.2 pounds)

Put the value of h=2p in h+ p=4.2

2p+p=4.2

3p=4.2

p=1.4

Put the value of p=1.4 in h=2p to get the value of h

h=2p

=2*1.4

=2.8

Hence the weight of hardcover version is 2.8 pounds and the weight of paperback version is 1.4 pounds.

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Answer:

Step-by-step explanation:

on edge 2023

Water coming out from a fountain is modeled by the function f(x) = −x2 + 8x + 2 where f(x) represents the height, in feet, of the water from the fountain at different times x, in seconds.What does the average rate of change of f(x) from x = 1 to x = 4 represent, options AWhat does the average rate of change of f(x) from x = 1 to x = 4 represent?
options: The water travels an average distance of 3 feet from 1 second to 4 seconds.
The water travels an average distance of 2 feet from 1 second to 4 seconds.
The water rises up with an average speed of 3 feet per second from 1 second to 4 seconds.
The water rises up with an average speed of 2 feet per second from 1 second to 4 seconds.

Answers

$f(x)=-x^(2) +8x+2$
Average rate of change from x = 1 to x = 4 = $(f(4)-f(1))/(4-1)= (( -4^(2)+8(4)+2)-(- 1^(2)+8(1)+2))/(3)= ((-16+32+2)-(-1+8+2))/(3)= (18-9)/(3)=$ $(9)/(3)=3$

This means that the water rises up with an average speed of 3 feet per second from 1 second to 4 seconds

Answer:

C. The water rises an average of 3 feet per second from 1 to 4 seconds

Step-by-step explanation:

I got it correct on the test

Its r9ght here just look at ut

Answers

Answer:

its 400 . 1200 divided by 3 in 400.

Step-by-step explanation:

What is the solution to this problem?
5x-3y=6 and 2x-5y=10

Answers

5x-3y=6
2x-5y=10
Make a reduction. Multiply the first by 2, the second by 5:
10x-6y=12
10x-25y=50
--------
-19y=38
y=-2
5x-3(-2)=6
5x+6=6
5x=0
x=0
The solution is (x;y)=(0;-2)

The solution to the system of equations 5x-3y=6 and 2x-5y=10 is x = 0 and y = -2.

To find the solution to the system of equations:

5x - 3y = 6 ...(1)

2x - 5y = 10....(2)

Use the elimination method to find the solution:

Multiply both sides of equation (1) by 2 to make the coefficients of 'x' in both equations equal:

2(5x - 3y) = 2(6)

10x - 6y = 12

Now, we have the following two equations:

10x - 6y = 12

2x - 5y = 10

Multiply both sides of equation (2) by 5 to make the coefficients of 'y' in both equations equal:

5(2x - 5y) = 5(10)

10x - 25y = 50

Now, we have the following two equations:

10x - 6y = 12...(3)

10x - 25y = 50...(4)

Subtract equation (3) from equation (4) to eliminate 'x':

(10x - 25y) - (10x - 6y) = 50 - 12

-19y = 38

Divide both sides by -19 to solve for 'y':

y = 38 / -19

y = -2

Now that we have the value of 'y', substitute it back into either equation (1) or (2) to find 'x'.

Use equation (1):

10x - 6(-2) = 12

10x + 12 = 12

Subtract 12 from both sides:

10x = 0

x = 0

So, the solution to the system of equations is x = 0 and y = -2.

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3) Solve this system of linear equations by elimination.y=x-1
2x-y=0

*x=-1,y=-2
*x=1,y=2
*x=2,y=1
*x=-2,y=-1

Answers

Answer:

Solving this system of linear equations by elimination we get x=-1 and y=-2

Option 1 is correct option.

Step-by-step explanation:

We are given equations:

$y=x-1---eq(1)\n2x-y=0---eq(2)$

We need to solve by Elimination method.

Elimination method: Add or subtract the equations to get an equation in one variable.

Rearranging the equation 1 we get

$-x+y=-1---eq(1)\n2x-y=0---eq(2)$

Add eq(1) and eq(2)

$-x+y=-1\n2x-y=0\n------\nx=-1$

So, after eliminating y we get x=-1

Now finding y by putting x in eq(1)

$y=x-1\ny=-1-1\ny=-2$

We get y=-2

So, solving this system of linear equations by elimination we get x=-1 and y=-2

Option 1 is correct option.

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