I work at a hotel and my time is 5:30 am to9:30am. I have to put out the breakfast for 6:30 and break down at 9:30 am. How many hours are they giving me to wash dishes and clean up? I also do housekeeping and my time is 9:00 am to 3:00pm. I had 12 check out and 4 stay over . How many minutes are they giving me to clean each room?

Answers

Answer 1

Answer: So, with 12 check outs and 4 stays over you will have to clean up 16 rooms ( I assume that the hotel has the habit of cleaning up the room even if people stay overnight)

so the time between 9 am and 3 pm is 4 hours, that is 4*60=240 minutes.

This means it's 240/16=120/8=60/40=15, 15 minutes per room.

About the first part of the sentence: I assume that you can start washing the dishes alrady at 6:30 (dishes you used for preparation,etc) - so you can clean up from 6:30 till 9:30 - that is three hours!

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Deanna collected data on the favorite sports of the students of two grades. The table shows the relative frequencies of rows for the data collected:Favorite Sport
Swimming Running Volleyball Row totals
Grade 8 0.14 0.18 0.22 0.54
Grade 9 0.17 0.24 0.05 0.46
Column totals 0.31 0.42 0.27 1

Based on the data, which statement is most likely correct?
In Grade 8, 14 students liked swimming.
In Grade 9, 31% of students liked swimming.
In Grade 8, 22% of students liked volleyball.
In Grade 9, 5 students liked volleyball.

Answers

Answer:

In Grade 8, 22% of students liked volleyball.

Step-by-step explanation:

Given:

The table representing the relative frequencies of different sports in different grades among the students.

Swimming Running Volleyball Row totals

Grade 8 0.14 0.18 0.22 0.54

Grade 9 0.17 0.24 0.05 0.46

Column totals 0.31 0.42 0.27 1

Relative frequency givesthe ratio of the number of quantities of a particular kind and the total number of quantities.

$\textrm{Relative frequency}=\frac{\textrm{Number of students in a particular sport}}{\textrm{Total students}}$

From the above table, we can conclude the following points:

Grade 8:

14% liked swimming, 18% liked running and 22% liked volleyball. So, a total of 54% students liked playing sports.

Grade 9:

17% liked swimming, 24% liked running and 5% liked volleyball. So, a total of 46% students liked playing sports.

Combining students of grade 8 and 9:

31% liked swimming, 42% liked running and 27% liked volleyball.

From all the options available, we observe that, third option is only correct.

In Grade 8, 22% of students liked volleyball.

(4,? is on the line below. Find the other half of the coordinate

y=2/7x-3

Answers

(x,y)
we are given (4,?)
basically,
if x=4, then what is y equal to ?
subsitute 4 for x
y=2/7(4)-3
y=8/7-3
y=8/7-21/7
y=-13/7=-1 and 6/7

(4,-13/7)

Prove that 1 - cosx / sinx = sinx / 1 + cosx
how?

Answers

Answer:

see explanation

Step-by-step explanation:

using the identity

cos²x = 1 - sin²x

consider the left side

$(1-cosx)/(sinx)$

multiply numerator/ denominator by (1 + cosx)

= $((1-cosx)(1+cosx))/(sinx(1+cosx))$ ← expand numerator

= $(1-cos^2x)/(sinx(1+cosx))$

= $(sin^2x)/(sinx(1+cosx))$ ← cancel sinx on numerator/ denominator

= $(sinx)/(1+cosx)$

= right side , thus proven

If f(x) is 4x-3 what is (f^-1of) (10)

Answers

$f(x)=4x-3\n y=4x-3\n 4x=y+3\n x=(1)/(4)y+(3)/(4)\n f^(-1)(x)=(1)/(4)x+(3)/(4)\n\n f^(-1) \circ f=(1)/(4)(4x-3)+(3)/(4)\n f^(-1) \circ f=(4x)/(4)-(3)/(4)+(3)/(4)\n f^(-1) \circ f=x$

$f(x)=4x-3\ \ \ \ and\ \ \ D_f=R\n\ny=4x-3\ \ \ \Rightarrow\ \ \ y+3=4x\ /:4\ \ \ \Rightarrow\ \ \ (1)/(4)y+ (3)/(4)=x\n\nf^(-1)(x)= (1)/(4)x+ (3)/(4) \ \ \ \ and\ \ \ \ D_(f^(-1))=R\n\n (f^(-1)\circ f) (10)=f^(-1)\bigg( f (10)\bigg)=\n=f^(-1)\bigg( 4\cdot10-3\bigg)=f^(-1)(37)=(1)/(4)\cdot37+ (3)/(4) =(37)/(4) +(3)/(4) = (40)/(4) =10$