Which two elements did he leave out by mistake?
(H, 1) and (T, 6)
(H, 6) and (T, 1)
(H, 2) and (T, 6)
(T, 1) and (T, 6)
Answer: The correct option is (A) (H, 1) and (T, 6).
Step-by-step explanation: Given that Jack is playing a game where he flips a coin and rolls a number cube labeled 1 through 6.
Jack listed the possible outcomes in the sample space 'S'' as follows:
S' = {(H, 2), (H, 3), (H, 4), (H, 5), (H, 6), (T, 1), (T, 2), (T, 3), (T, 4), (T, 5)}
We are given to select the correct option that contains the two elements Jack left out by mistake.
The sample space for the event of flipping a coin is {H, T}
and
the sample space for the event of rolling a number cube labeled 1 through 6 is {1, 2, 3, 4, 5, 6}.
Let, 'S' represents the actual sample space for the event.
Then, we get
S = {(H, 1), (H, 2), (H, 3), (H, 4), (H, 5), (H, 6), (T, 1), (T, 2), (T, 3), (T, 4), (T, 5), (T, 6)}.
Comparing S with S', the two missing elements were (H, 1) and (T, 6).
Thus, the correct option is (A).
Answer:
80%
Step-by-step explanation:
Since 4 of those 5 numbers are odd, the probability that the ID's first 4 numbers being odd is 4/5 which is 80%
Answer:
Answer will be :
Y= -15/2x