A system of equations is shown below:y = 3x − 7
y = 2x + 1

What is the solution to the system of equations?
(8, 17) (−8, 17) (−8, −17) (8, −17)
x

Answers

Answer 1
Answer:

Hi Brainiac


y=3x-7

y=2x+1

We need to solve y=3x-7 for y

Now let's start by substitute 3x-7 for y in y=2x+1

y=2x+1

3x-7=2x=1

Now add -2x

3x-7-2x=2x+1-2x

x-7=1

Add 7

x-7+7=1+7

x=8

Our last step is to substitute 8 for x in y=3x-7

y=3x-7

y=(3)(8)-7

y= 24-7

y= 17

Answer : A


I hope that's help:)

Answer 2
Answer:

Answer: The answer is A

I took the test and got it right.


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In ∆MNP, m∠N = 90º, NH – altitude, m∠P = 21º, PM = 4 cm. Find MH.

Answers

Answer:

0.51 cm

Step-by-step explanation:

In right triangle MNP, MP = 4 cm, m∠N = 90°, m∠P = 21°

By the sine definition,

\sin \angle P=\frac{\text{Opposite leg}}{\text{Hypotenuse}}=(MN)/(MP)\n \nMN=MP\sin \angle P\n \nMN=4\sin 21^(\circ)\approx 1.43\ cm

Now, consider right triangle HMN (it is right because NH is an altitude). By the cosine definition,

\cos \angle M=\frac{\text{Adjacent leg}}{\text{Hypotenuse}}=(MH)/(MN)\n \nMH=MN\cos \angle M

In the right triangle, two acute angles are always complementary, so

m\angle M=90^(\circ)-m\angle P=90^(\circ)-21^(\circ)=69^(\circ)

Thus,

MH=1.43\cos 69^(\circ)\approx 0.51\ cm

Evaluate the expressions when a = 10, b = -2, and c = -5: (a) a * b (b) 10 * b² (c) -a * b² + (-c) (d) (a * c + a) / b

Answers

(a) ab
(10)(-2)
-20

(b) 10bsquared
10(-2)squared
10(4)
40

(c) -absquared
-(10)(-2)squared
-10(4)
-40

(d) ((10)(-5)+(10))/(-2)
(-50+10)/-2
(-40)/-2
20

Express 7.4 x 10² in standard form.


MATH​

Answers

10^2 = 100

7.4 × 10^2 = 7.4 × 100 = 740

Answer: 740

Answer:

7.4 x 10²

7.4 *100

740

Step-by-step explanation:

What is the LCD between these fractions 4/9 and 2/3

Answers

The least common multiple that is divisible by both a and b is the smallest positive integer. The LCD between these two fractions 4/9 and 2/3 is 9.

What is LCM?

The least common multiple that is divisible by both a and b is the smallest positive integer, lowest common multiple, or smallest common multiple of two numbers a and b, generally indicated by LCM.

The LCD of two fractions is the LCM of the denominator of the fractions.

Since the denominator of the two fractions is 3 and 9. Therefore, the LCM of the two denominators are,

LCM = 9

Hence, the LCD between these two fractions 4/9 and 2/3 is 9.

Learn more about Least Common Multiple here:

brainly.com/question/20739723

#SPJ2

Answer: Least common denominator  = 9

Step-by-step explanation:

The LCD is the lowest multiple of the denominators

9 is a multiple of 1 × 9 or 3 × 3.  So since 3 is the denominator of 2/3,  9 is the LCD.

2/3 is equivalent to 6/9.  

5. A car uses 10 litres of petrol in 75 km. How far will it go on 8 litres?​

Answers

Answer:

60km

Step-by-step explanation:

75/10=x/8

Solve For X

75*8=600,   600/10=60

THEREFORE

75/10=60/8

You could ALSO Divide 75 by 10, get 7.5, and multiply THAT by 8, as the car is assumed to have constant gas usage

Answer:

60km

Step-by-step explanation:

Let x represent the required distance.

Since the quantity of petrol is directly proportional to the distance:

x : 75 = 8 : 10

i.e.      (x)/(75) = (8)/(10)

           x = (75 * 8)/(10)

           x = 60

∴ The distance is 60 km.

Hope this helps!!!

Suppose there is a pile of quarters dimes and pennies with a total value of $1.07 how much of each coin can be present without being able to make change for a dollar? Of there are multiple selections of the coins that will work choose the selection with the largest total numbers of coins.

Answers

Hello,

Very nice as problem.

2 solutions:
1 quater,8 dimes, 2 pennies
and
3 quaters,3 dimes, 2 pennies

since
107=( 0, 0, 107) but : 100= 0*25+ 0*10+ 100
107=( 0, 1, 97) but : 100= 0*25+ 1*10+ 90
107=( 0, 2, 87) but : 100= 0*25+ 2*10+ 80
107=( 0, 3, 77) but : 100= 0*25+ 3*10+ 70
107=( 0, 4, 67) but : 100= 0*25+ 4*10+ 60
107=( 0, 5, 57) but : 100= 0*25+ 5*10+ 50
107=( 0, 6, 47) but : 100= 0*25+ 6*10+ 40
107=( 0, 7, 37) but : 100= 0*25+ 7*10+ 30
107=( 0, 8, 27) but : 100= 0*25+ 8*10+ 20
107=( 0, 9, 17) but : 100= 0*25+ 9*10+ 10
107=( 0, 10, 7) but : 100= 0*25+ 10*10+ 0
107=( 1, 0, 82) but : 100= 1*25+ 0*10+ 75
107=( 1, 1, 72) but : 100= 1*25+ 1*10+ 65
107=( 1, 2, 62) but : 100= 1*25+ 2*10+ 55
107=( 1, 3, 52) but : 100= 1*25+ 3*10+ 45
107=( 1, 4, 42) but : 100= 1*25+ 4*10+ 35
107=( 1, 5, 32) but : 100= 1*25+ 5*10+ 25
107=( 1, 6, 22) but : 100= 1*25+ 6*10+ 15
107=( 1, 7, 12) but : 100= 1*25+ 7*10+ 5
107=( 1, 8, 2) is good
107=( 2, 0, 57) but : 100= 2*25+ 0*10+ 50
107=( 2, 1, 47) but : 100= 2*25+ 1*10+ 40
107=( 2, 2, 37) but : 100= 2*25+ 2*10+ 30
107=( 2, 3, 27) but : 100= 2*25+ 3*10+ 20
107=( 2, 4, 17) but : 100= 2*25+ 4*10+ 10
107=( 2, 5, 7) but : 100= 2*25+ 5*10+ 0
107=( 3, 0, 32) but : 100= 3*25+ 0*10+ 25
107=( 3, 1, 22) but : 100= 3*25+ 1*10+ 15
107=( 3, 2, 12) but : 100= 3*25+ 2*10+ 5
107=( 3, 3, 2) is good
107=( 4, 0, 7) but : 100= 4*25+ 0*10+ 0