HELP!!!! Divide. Write your answer in lowest terms as a proper or improper fraction (not a mixed number). 11/21 divided by 22/7

Answers

Answer 1

Answer: My answer is 1/6. Here's How I worked it out:

11/21 / 22/7 is the same as or = to 11/21 * 7/22 which = 77/462 and then divide both the numerator and denominator by 77 and you get 1/6. (In other words simplify 77/462). Hope this helped :)

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WILL GIVE BRAINLIESTHannah and Han are each trying to solve the equation x² – 8x + 26 = 0. They know that
x = -1 are i& - i, but they are not sure how to use this information to solve for x in their
equation.
Part 1- Here is Hannah's work:
x? - 8x + 26 = 0
X? – 8x = -26
Show Hannah how
to finish her work using completing the square and complex numbers.
Part 2- Han decides to solve the equation using the quadratic
formula. Here is the beginning of his
work
-b+V62-4ac
-(-8)+7-8)2–401|(26)
Finish using the quadratic formula. Simplify the final answer as much as possible.

Answers

The solutions are:-

$x=4+√(10i)\n\nx=4-√(10i)$

What is the equation?

The definition of an equation is a mathematical statement that shows that two mathematical expressions are equal.

Here given equation is

$x^2- 8x + 26 = 0\n\nx^2-8x=-26\n\n(x-4)^2=-10\n\n$

$(x-4)=$ ± $√(-10)$

$x=√(10)i+4\n\nx=-√(10)i+4$

So,

$x=(-b+-√(b^2-4ac))/(2a)\n\nx=(8+-√((-8)^2-4(1)(26)))/(2(1))\n\nx=(8+-√((-8)^2-4(1)(26)))/(2(1))\n\nx=(8+-√(64-104))/(2)\n\nx=(8+-2√(10i))/(2)\n\nx=(2(4+-√(10i)))/(2)\n\nx=4+√(10i)\n\nx=4-√(10i)$

Hence, the solutions are:-

$x=4+√(10i)\n\nx=4-√(10i)$

To know more about the equation

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Part one:

$x^2-8x=-26$

Rewrite in the form $(x+a)^(2) =b$

$\left(x-4\right)^2=-10$

$\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=√(a),\:-√(a)$

Solve $x-4=√(-10) : x=√(10) i+4$

Solve $x-4=√(-10) : x=-√(10) i+4$

$x=√(10)i+4,\:x=-√(10)i+4$

Part two:

$x=(-\left(-8\right)\pm √(\left(-8\right)^2-4\cdot \:1\cdot \:26))/(2\cdot \:1)$

Simplify $√(\left(-8\right)^2-4\cdot \:1\cdot \:26)}: 2√(10) i$

$=(-\left(-8\right)\pm \:2√(10)i)/(2\cdot \:1)$

Separate solutions

$x_1=(-\left(-8\right)+2√(10)i)/(2\cdot \:1),\:x_2=(-\left(-8\right)-2√(10)i)/(2\cdot \:1)$

$(-(-8)+2√(10)i )/(2*1) :4+√(10)i$

$(-(-8)+2√(10)i )/(2*1) :4-√(10)i$

$x=4+√(10)i,\:x=4-√(10)i$

When you complete a job, but use more time and effort than is truly necessary, how have you worked?a. Effectively, but not efficiently
b. Neither effectively nor efficiently
c. Efficiently, but not effectively
d. Both effectively and efficiently

Answers

a. effectively, but not efficiently
You completed the job, which means it was effective, however since it took so much time and effort, it could have possibly been done more efficiently.

A circle is centered at the point (-3, 2) and passes through the point (1, 5). The radius of the circle is ______ units. The point (-7, ______) lies on this circle.How would I do this?

Answers

circle formula
(x-h)^2+(y-k)^2=r^2 where (h,k) is the center
and r=radius

to find the radius
we are given one of the points and the center
distnace from them is the radius
distance formula
D= $\sqrt{(x2-x1)^(2)+(y2-y1)^(2)}$
points (-3,2) and (1,5)
D= $\sqrt{(1-(-3))^(2)+(5-2)^(2)}$
D= $\sqrt{(4)^(2)+(3)^(2)}$
D= $√(16+9)$
D= $√(25)$
D=5

center is -3,2
r=5
input
(x-(-3))^2+(y-2)^2=5^2
(x+3)^2+(y-2)^2=25 is equation
radius =5
input -7 for x and solve for y
(-7+3)^2+(y-2)^2=25
(-4)^2+(y-2)^2=25
16+(y-2)^2=25
minus 16
(y-2)^2=9
sqqrt
y-2=+/-3
add 2
y=2+/-3
y=5 or -1

the point (-7,5) and (7,-1) lie on this circle

radius=5 units
the points (-7,5) and (-7,1) lie on this circle

Help and plz explain for i can understand and will remember how to do it and DC for i can put on my notes

Answers

Answer in the document below.

$(3)/(14):(7)/(10)= (3)/(14)\cdot(10)/(7)= (3)/(7)\cdot(5)/(7)=(15)/(49)$

What is the lcd for the factor 1/3 and 2/9?

Answers

The LCD is 9 for the factor 1/3 and 2/9.

Form an equation to help you solve this problem.A school bus is full as it sets off. At the first stop 3 children get off and at the next stop a third
of the remaining children get off, leaving the bus only half full.
How many children were on the bus at the start?

Answers

Answer:

Step-by-step explanation:

If there are x children on the bus at the start, after the first stop, there are (x-3) remaining. After two stops, the number on the bus is ...

x/2 = x -3 -(1/3)(x -3)

Multiplying by 6, we have ...

3x = 6x -18 -2(x -3)

3x = 4x -12 . . . . simplify

12 = x . . . . . . . . add 12-3x

There were 12 children on the bus at the start.

_____

Check

After 3 got off at the first stop, there were 12-3 = 9 remaining. 1/3 of those, or 9/3=3 got off at the second stop, so 9 -3 = 6 remained. This is half the original number, as required.

Final answer:

Let X represent the number of children on the bus originally. The equation formed is 2/3*(X - 3) = X/2, and when we solve it, we find that X equals 12 which indicates that there were 12 children on the bus at the start.

Explanation:

Let's denote the number of children on the bus at the start as X. After the first stop, the number of children on the bus became X - 3, because 3 children got off. After the second stop, a third of the remaining children got off, so the number of children on the bus became 2/3*(X - 3). According to the problem, after all the stops, the bus was half full. Therefore, we can set up an equation: 2/3*(X - 3) = X/2.

To solve the equation, we can multiply all terms by 6 to clear out the fractions and obtain the equation: 4*(X - 3) = 3X. This simplifies to 4X - 12 = 3X which simplifies further to X = 12, meaning there were initially 12 children on the bus.

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