Direct Linear Variation, anyone?
Direct Linear Variation, anyone? - 1

Answers

Answer 1
Answer: All answers are correct

Similar situation as you have before, let's starts from the easiest one which is D

2y = x

solve for y and you have y =x/2 which will show you on graph straight line

3/4y = 6x 

multiply by 4/3
y = [(6*4)/3]x
y=(24/3)x
y=8x

also straight line :)

y=2/5x-2/5 is same as y=0.4x-0.4 also will result as straight line graph :)

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What times what equals 41

Answers

1x41=41. That is the answer of your problem


1 X 41
102.5×0.4
410 X 1/10
82 X 1/2

What is straight part of a line and has two end points

Answers

This is called a line segment
It could be ling segments or just lines. Line segments have two end points and lines have two arrows

Help me pls sry for asking many questions

Answers

4x-10y=-20 /*(-3)

6x-15y=-30 /*2

-12x+30y=60

12x-30y=-60

+-------

0=0

C.

Answer:

infinitely many solution

Greatest common factor or common factor for 27 and 63

Answers

The greatest common factor is 3 for both 27 and 63

What is 0 tims 0 plus 3 times 12 divided by 14

Answers

P:Parentheses \n E: Exponents \n M: Multiplication \n D: Division \n A: Addition \n S: Subtraction

In this problem we're doing: Multiplication ,Addition, and lastly Division

Step^1: 0(0) = 0 + 3 = 3 \n Step^2: 3(12) = 36\n Step^3: (36)/(14) = 2.57 \n Step^4: Answer (maybe): 2.57

good \n luck \n on \n your \n assignment

\n \n MeIsKaitlyn
Enjoy \n your \n day :)


Inverse variation?When a constant force acts upon an object, the acceleration of the object varies inversely with it’s mass. When a certain constant force acts upon an object with mass 4kg, the acceleration of the object is 14m/s^2. If the same force upon another object whose mass is 7kg. What is this objects acceleration?

Answers

Answer:

An Inverse variation states that a relationship between two variables in which the product is always constant.

If one of the variable increases then the other decreases in proportion so that the product is unchanged.

if y is inversely proportional to x, then the equation is of the form

y = (k)/(x) , where k is constant.

As per the given condition, A constant force acts upon an object, the acceleration of the object varies inversely with it's mass.

i.e, a \propto (1)/(m)

By definition of inverse variation;

a = (F)/(m) . ......[1]  ,where F is the constant force.

It is given that an object has mass(m)= 4kg and the acceleration of an object(a) = 14 m/s^2

Substitute these in [1] to find the constant force F;

14 = (F)/(4)

or

F =14 * 4 = 56 kg m/s^2

Now, if the same force acts upon the another object whose mass (m) = 7 kg then calculate acceleration.

[1]⇒  a = (56)/(7) = 8 m/s^2

therefore, the acceleration of an another object is, 8 m/s^2


Final answer:

Inverse variation or inverse proportionality represents that one value increases as the other decreases. In the context of physics, it indicates that with a constant force, the acceleration of an object is inversely proportional to its mass. If a 4 kg object has an acceleration of 14 m/s^2, a 7 kg object will have an acceleration of 8 m/s^2.

Explanation:

The concept raised here is related to the law of inverse variation, also known as the inverse proportionality concept found in Physics. This law states that when a constant force acts upon an object, the acceleration of the object is inversely proportional to its mass. Essentially, the more mass an object has, the less it accelerates. We can write this rule as a = F/m, where 'a' is acceleration, 'F' is the applied force, and 'm' is the mass of the object. From the given data, the force 'F' could be calculated from the first scenario where the mass, m = 4 kg and acceleration, a = 14 m/s^2. We have, F = a*m which is 14*4 = 56 N (Newtons). To find the acceleration of the second object with a mass 7 kg and under the same force, we apply the formula a = F/m, leading to a = 56 / 7 = 8 m/s^2. So, the acceleration of the object with 7 kg mass would be 8 m/s^2 under the same force.

Learn more about Inverse Variation here:

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