We need to write 0.3125 in fraction form
First we remove the decimal
WE have 4 numbers after the decimal so we divide by 10000
Both numerator and denominator ends at 0 and 5
so we divide both top and bottom by 5
Again divide both numerator and denominator by 5
Again divide by 5
Again divide by 5
First, let's find how many cups the bird feeder uses 24 times.
24 x 6 = (20 x 6) + (4 x 6) = 120 + 24 = 148 cups.
Now, let's divide 148 by 32.
148 ÷ 32 = 4.625 bags of seed.
I hope this helped!
B. 21.3
C. 14.9
D. 26.8
Answer:
37.1
Step-by-step explanation:
The rectangle has a length of 3√5 and a width of 2√7. The perimeter is calculated as 23.9 approximately.
Use the concept of a rectangle defined as:
Rectangles are four-sided polygons with all internal angles equal to 90 degrees. At each corner or vertex, two sides meet at right angles. The rectangle differs from a square in that its opposite sides are equal in length.
Given that,
Length of the rectangle: 3√5
Width of the rectangle: 2√7
To find the perimeter of a rectangle,
Use the formula P = 2(length + width).
In this case,
The length is 3√5 and the width is 2√7.
Applying the formula, we get:
P = 2(3√5 + 2√7)
To simplify this expression, distribute the 2:
P = 6√5 + 4√7
p ≈ 23.9
Hence,
The perimeter of the rectangle is approximately 23.9.
To learn more about rectangles visit:
#SPJ3
Answer:
Step-by-step explanation:
Area=Length times width
A=3*2
A=6
Answer:
y' = 2x + 1
y'' = 2
Step-by-step explanation:
y = x² + x + 8
y' = 2x + 1
y'' = 2
5/37
27/100
27/200
Either of (2,2) or (2,3) should be removed to get the relation as a function.
We know that a relation is a function if each element of the first set is mapped to a unique element of the other set.
i.e. corresponding to each x value we have a single y-value.
We are given a relation as:
{(–1, 0), (1, 3), (2, 2), (2, 3), (3, 1)}
As we could observe that there are two images corresponding to '2' i.e. 2 is mapped to 2 and 3 both as could be seen from the ordered pair (2,2) and (2,3).
Hence, if any one of (2,2) and (2,3) will be removed we will get our relation as a function.