In order for an object to accelerate, a forcegravityfrictiona swing must be applied.

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Answer 1
Answer: In order foran object to accelerate, a force must be applied. It follows Newton’s secondlaw of motion where it states that a body at rest remains at rest unless aforce is acted upon it. When you move an object, you are exerting a force ontoit. By exerting a force on the object, you are actually displacing it from itsinitial position. You cannot apply force to the object without altering itsposition. Keep in mind that when you exert work, you are exerting energy too. 

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Which of these objects would show the greatest parallax?a. the Sun
b. Mars
c. the Moon
d. Polaris
What is the distance an object would be from Earth if its parallax were one arcsecond?
a. a parsec
b. a light-year
c. an arcminute
d. an angular diameter

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The sun's parallax would be 180 degrees, greater than which you can't get.

If an object exhibits a parallax of 1 arc second, then its distance from us
is called one 'parsec'.  That distance is about  3.26 light-years.

Animals in cold climates often depend on two layers of insulation: a layer of body fat [of thermal conductivity 0.200W/(m⋅K) ] surrounded by a layer of air trapped inside fur or down. We can model a black bear (Ursus americanus) as a sphere 1.60m in diameter having a layer of fat 3.90cm thick. (Actually, the thickness varies with the season, but we are interested in hibernation, when the fat layer is thickest.) In studies of bear hibernation, it was found that the outer surface layer of the fur is at 2.80∘C during hibernation, while the inner surface of the fat layer is at 30.9∘C a) What should the temperature at the fat-inner fur boundary be so that the bear loses heat at a rate of 51.4W ? b) How thick should the air layer (contained within the fur) be so that the bear loses heat at a rate of 51.4W ?

Answers

A) The temperature at the fat-inner fur boundary be so that the bear loses heat at a rate of 51.4W is; T_i = 38.52°C

B) The thickness of the layer contained within the fur so that the bear loses heat at a rate of 51.4 W is; t = 13.41 cm

We are given;

Diameter of sphere; d = 1.6 m

Radius of sphere; r = d/2

r = 1.6/2

r = 0.8 m

Thickness of bear; t = 3.9 cm cm = 0.039 m

Outer surface Temperature of fur; T_h = 2.8 ∘C

Inner surface Temperature of fat;T_f = 30.9 ∘C

Thermal conductivity of fat; K_f = 0.2 W/m⋅k

Thermal conductivity of air; K_a = 0.024 W/m⋅k

A) To find the temperature at the fat-inner fur boundary when heat loss is 51.4 W, we will use the heat current formula;

H = K_f•A(T_f - T_i)/t

Where;

A is area = 4πr²

A = 4π × 0.8²

A = 8.04 m²

T_i is the temperature we are looking for

H is heat loss = 51.4

t is thickness

Making T_i the subject gives;

T_i = (T_f × H × t)/(K_f × A)

T_i = (30.9 × 51.4 × 0.039)/(0.2 × 8.04)

T_i = 38.52°C

B) We want to find the thickness of the layer contained within the fur. Thus, we will use K_a instead of K_f. Let us make t the subject in the heat current formula to get;

t = (K_a•A(T_i - T_h)/H

t = (0.024 × 8.04 × (38.52 - 2.8))/51.4

t = 0.1341 m

t = 13.41 cm

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Answer:

Explanation:

Using the equation

H = Q/t = k A ( T hot - T cold) / L

where H is the rate of heat loss = 51.4 W, T cold be temperature of the outer surface, A is the surface area of the fat layer which is a model of sphere ( surface area of a sphere ) = 4πr² where diameter = 1.60 m

radius = 1.60 m / 2 = 0.80 m

A = 4 × 3.142 × ( 0.8²) = 8.04352 m²

making T cold subject of the formula

T cold =  T hot -   (HL)/(KA)  = 30.9° C - ( 51.4 W × 3.9 × 10⁻² m) / ( 0.2 W/mK × 8.04352 m² ) =  30.9° C - 1.25 ° C = 29.65° C

b) The thickness of air layer for the bear to lose heat t a rate of 51.4 W

thermal conductivity of air is 0.024 W/mK and rearranging the earlier formula

L = \frac{kA( T HOT - T COLD )}H} = (0.024 W/ m K × 8.04352 m²) ( 29.65° C - 2.8°C) / 51.4 W = 0.101 m = 10.1 m

What is the period and frequency of a water wave if 4.0 complete waves pass a fixed point in 10 seconds

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The correct answer for this question is this one: C) 2.5s. The period and frequency of a water wave if 4.0 complete waves pass a fixed point in 10 seconds is that 2.5 s

Here are the following choices:
A) 0.25s 
B) 0.40s 
C) 2.5s 
D) 4.0s

using kepler's 3rd law and newton's law of universal gravitation, find the period of revolution p of the planet as it moves around the sun. assume that the mass of the planet is much smaller than the mass of the sun.

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As we all know that Kepler's third law states the square of the period is proportional to the cube of the average distance. Some of the part of the equation are just mere constants, and they are very vital.

After deriving the equation, we can get the formula.

T = sqrt { 4 * PI^2 /(GM) * [(R1 + R2)/2]^3 } 

A substance can be classified by its physical properties which are properties that

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Hello :)
Physical properties are properties that you can see, feel and measure, they do not change the matter of the substance. Some examples of physical properties are Mass, Color, Shape, Hardness and Boiling point.

Physical properties are properties that you can see, feel and measure, they do not change the matter of the substance. Some examples of physical properties are Mass, Color, Shape, Hardness and Boiling point.



When two electron in a chemical bond are equally shared between two different atoms, what is the bond

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When two electron in a chemical bond are equally shared between two different atoms, the bond is covalent bond.

What is covalent bond?

A chemical bond known as a covalent bond includes the exchanging of electrons between atoms to create electron pairs.

These electron couples are referred to as bonding pairs or sharing pairs. Covalent bonding is the stable equilibrium of attracting and repulsive forces that exists when two atoms share an electron.

The ability of each atom to reach the equivalent of a full valence shell, which corresponds to a stable electronic state, is made possible for many molecules by the sharing of electrons. Hence, when two electron in a chemical bond are equally shared between two different atoms, the bond is covalent bond.

Learn more about covalent bond here:

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When two electrons are equally shared between two atoms it is a molecular compound using a single non polar covalent bond.