a school store has 1200 pencils in stock and sells an average of 24 pencils per day the manager reorders when the number of pencils in stock is 500. in how many days will the manager have to reorder

Answers

Answer 1
Answer: Number of pencils in stock = 1200
Average number of pencils sold by the manager per day = 24
Number of pencils that would be sold before reordering = 1200 - 500
                                                                                         = 700
Then
The number of days after which the manager will reorder = 700/24
                                                                                             = 29.16
So the manager has to reorder after about 30 days. Since the answer comes in fraction of more than 29 days, so it has to be 30 days. I hope the procedure is clear for your understanding.
Answer 2
Answer:

Answer:

29.16

Step-by-step explanation:


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This is like so hard to me i do not get it at all!

Answers

If u don't get it, go back and do some practice problems they have in the lesson. (I am in K12 too, that's wat I do. Sometimes I even do practice problems in the middle of the test.)

Jacob reads a number of books in July and 8 books in August. During these same months, Marcus reads 3 times as many books as Jacob reads. Write an expression that could be used to find the number of books Marcus reads in July and August combined. Let b represent the number of books Jacob reads in July.

Answers

8 = 3 / x , this is your equation , 8 and 3 where the only numbers , your question is kinda hard to comprehend 

Answer:

8 = 3 / x

Step-by-step explanation:

Length of a school bus??

Answers

45 feet is the lenth of a school bus
Forty-five is the answer (:

How many eyes does my dog have?

Answers

I'm pretty sure it's two xD
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Move the decimal point in 250,000 to the left as many places as necessary to find a number that is greater than or equal to 1 and less to 10.

Answers

0.250
It's greater then 1 and 10. I don't think it's possible for it to be less then 10, but it can be.
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Jay and Blair went fishing together they caught 27 fish. Jay caught 2 times as many fish as Blair. How many fish did Jay and Blair each catch? write an equation and solve. Explain your work

Answers

Blair caught 9 fish, and Jay caught 18 fish out of 27 fish. By using the two equations.

Let's assume the number of fish Blair caught is represented by the variable "B". Since Jay caught 2 times as many fish as Blair, the number of fish Jay caught can be represented by the variable "J" as 2B.

According to the given information, Jay and Blair caught a total of 27 fish. We can write this as an equation:

B + J = 27

Substituting the values for J and B in terms of each other:

B + 2B = 27

Combining like terms:

3B = 27

Now, we can solve the equation for B by dividing both sides by 3:

B = 27 / 3

B = 9

So, Blair caught 9 fish.

To find the number of fish Jay caught, we substitute the value of B back into the equation:

J = 2B

J = 2(9)

J = 18

Therefore, Jay caught 18 fish. In conclusion, Blair caught 9 fish, and Jay caught 18 fish.

To know more about an expression follow

brainly.com/question/1959166

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the answer is 18 because 27 minus 18 is 9 and 9 is 2x less