A rectangular prism has a length of 1 1/4 centimeters, a width of 4 cm, and a height of 3 1/4 cm. What is the volume of the prism

Answers

Answer 1

Answer: the equation to find the volume of a prism is volume=basexheight
*convert the lengths into decimals
first, you have to find the base (area=lengthxwidth)
a=1.25x4
a=5
now fill in the volume equation with the information you have.
v=5x3.25
v=16.25
the volume of the rectangular prism is 16.25 cm or 16 1/4 cm.
Hope I helped...

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What is the quotient of 75,120 ÷ 16?

A grandfather is ten times older than his granddaughter. He is also 54 years older than her. Find their present ages.

Answers

He is 60 and she is 6

In circle F what is the measure of arc CB?

17.5
35
70
60

Answers

Multiply by 2 to get that the measure of arc CB is 70.

Answer:

measure of arc CB is 70°

Step-by-step explanation:

Draw segment FC.

Measure of arc CB = ∠CFB

∠CFB is complementary to ∠CFA

∠CFB = 180° - ∠CFA

Δ CFA is isosceles

∠ FAC = ∠ FCA = 35°

∠CFA +∠ FAC + ∠ FCA = 180°

∠CFA = 180° - 70°

∠CFB = 180° - (180° - 70°) = 70°

∴ Measure of arc CB is 70°

The ratio of cats to dogs at the shelter is 3 to 2 if there are 15 cats at the shelter how many dogs are there

Answers

Answer:

3/2=15/x

Step-by-step explanation:

Solve that and you’ll get x, which is your answer

A rectangular block has a length of 8 inches, a width of 3.5 inches, and a height of 2 inches. Four blocks are stacked to create a tower. What is the volume of the tower? O A. 56 in 3 O B. 140 in 3 O C. 280 in O D. 336 in

Answers

The volume of the tower is 224 in³, which is not listed among the given options.

To find the volume of the rectangular block, we need to multiply its length, width, and height. Therefore, the volume of the single block is:
8 x 3.5 x 2 = 56 cubic inches.
Since we are stacking four blocks to create a tower, we need to multiply the volume of a single block by 4.

Thus, the volume of the tower is:
56 x 4 = 224 cubic inches.
The volume of a rectangular block can be found using the formula,

V = length × width × height.

In this case, the length is 8 inches, the width is 3.5 inches, and the height is 2 inches.

V = 8 × 3.5 × 2 V

= 28 × 2 V

= 56 in³

Now that we know the volume of one block, we can find the volume of the tower created by stacking four blocks. Tower volume = block volume × number of blocks Tower volume = 56 in³ × 4 Tower volume = 224 in³

For similar question on volume:

brainly.com/question/1578538

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Solve this differential Equation by using power series
y''-x^2y=o

Answers

We're looking for a solution

$y=\displaystyle\sum_(n=0)^\infty a_nx^n$

which has second derivative

$y''=\displaystyle\sum_(n=2)^\infty n(n-1)a_nx^(n-2)=\sum_(n=0)^\infty(n+2)(n+1)a_(n+2)x^n$

Substituting these into the ODE gives

$\displaystyle\sum_(n=0)^\infty(n+2)(n+1)a_(n+2)x^n-\sum_(n=0)^\infty a_nx^(n+2)=0$

$\displaystyle\sum_(n=0)^\infty(n+2)(n+1)a_(n+2)x^n-\sum_(n=2)^\infty a_(n-2)x^n=0$

$\displaystyle2a_2+6a_3x+\sum_(n=2)^\infty(n+2)(n+1)a_(n+2)x^n-\sum_(n=2)^\infty a_(n-2)x^n=0$

$\displaystyle2a_2+6a_3x+\sum_(n=2)^\infty\bigg((n+2)(n+1)a_(n+2)-a_(n-2)\bigg)x^n=0$

Right away we see $a_2=a_3=0$ , and the coefficients are given according to the recurrence

$\begin{cases}a_0=y(0)\na_1=y'(0)\na_2=0\na_3=0\nn(n-1)a_n=a_(n-4)&\text{for }n\ge4\end{cases}$

There's a dependency between terms in the sequence that are 4 indices apart, so we consider 4 different cases.

If $n=4k$ , where $k\ge0$ is an integer, then

$k=0\implies n=0\implies a_0=a_0$

$k=1\implies n=4\implies a_4=(a_0)/(4\cdot3)=\frac2{4!}a_0$

$k=2\implies n=8\implies a_8=(a_4)/(8\cdot7)=(6\cdot5\cdot2)/(8!)a_0$

$k=3\implies n=12\implies a_(12)=(a_8)/(12\cdot11)=(10\cdot9\cdot6\cdot5\cdot2)/(12!)a_0$

and so on, with the general pattern

$a_(4k)=(a_0)/((4k)!)\displaystyle\prod_(i=1)^k(4i-2)(4i-3)$

If $n=4k+1$ , then

$k=0\implies n=1\implies a_1=a_1$

$k=1\implies n=5\implies a_5=(a_1)/(5\cdot4)=(3\cdot2)/(5!)a_1$

$k=2\implies n=9\implies a_9=(a_5)/(9\cdot8)=(7\cdot6\cdot3\cdot2)/(9!)a_1$

$k=3\implies n=13\implies a_(13)=(a_9)/(13\cdot12)=(11\cdot10\cdot7\cdot6\cdot3\cdot2)/(13!)a_1$

and so on, with

$a_(4k+1)=(a_1)/((4k+1)!)\displaystyle\prod_(i=1)^k(4i-1)(4i-2)$

If $n=4k+2$ or $n=4k+3$ , then

$a_2=0\implies a_6=a_(10)=\cdots=a_(4k+2)=0$

$a_3=0\implies a_7=a_(11)=\cdots=a_(4k+3)=0$

Then the solution to this ODE is

$\boxed{y(x)=\displaystyle\sum_(k=0)^\infty a_(4k)x^(4k)+\sum_(k=0)^\infty a_(4k+1)x^(4k+1)}$

Which equation represents the line that passesthrough the point (1,5) and has a slope of -2?
1) y = -2x + 7
2) y = -2x + 11
3) y = 2x-9
4) y = 2x + 3

Answers

Answer:

Step-by-step explanation:

y - 5 = -2(x - 1)

y - 5 = -2x + 2

y = -2x + 7

Option 1 is the answer

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