3y + 20 = 3 + 2y
3y- 2y = 3-20
y = -17
this as a ratio in its simplest form.*
1:1/3
O 1:2
O 1:3
O 14
The area of the sector with a central angle of 210° and a diameter of 4.6units is 2.6π square units.
Area is a collection of two - dimensional points enclosed by a single dimensional line. Mathematically, we can write -
V = ∫∫F(x, y) dx dy
Given is a sector with a central angle of 210° and a diameter of 4.6 units.
The area of a sector can be calculated using the formula -
A{Sector} = θ/360° x 2πr
For the sector given, we have -
θ = 210°
r = 4.6 units
Substituting the values, we get the area of the sector as -
A{Sector} = 210°/360° x 2πr
A{Sector} = 7/12 x 2πr
A{Sector} = 7πr/6
A{Sector} = 7πd/12
A{Sector} = 7π x 4.6/12
A{Sector} = 7π x 0.38
A{Sector} = 2.6π square units
Therefore, the area of the sector with a central angle of 210° and a diameter of 4.6units is 2.6π square units.
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