MATHEMATICS HIGH SCHOOL

Subtract (3 + 2i) from (–9 – 8i).a. –17 – 5i

b. –6 – 6i

c. –12 – 10i

d. 12 + 10i

Answers

Answer 1

Answer:

The answer is -12-10i

Given two complex numbers

First complex number = 3+2i ....(1)

Second Complex number = -9-8i..... (2)

Subtracting equation (1) from equation (2)

As this is a subtraction between complex numbers hence the Real part gets subtracted from the real part and the imaginary part gets subtracted from the imaginary part

( -9- 8i ) - ( 3 +2i )

= -9 -3 -8i - 2i

= -12 -10i

For more information please refer to the link given below

brainly.com/question/10516341

Answer 2

Answer: (-9-8i)-(3+2i)
= -9-8i-3-2i
Separate i and the numbers
= (-9-3)+(-8i-2i)
= -12-10i

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Answers

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Answers

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