which power can you write to represent the volume of a cube that is 1/3 inches. write the power as an expression with a base and an exponent

Answers

Answer 1
Answer:

Answer: The volume of a cube that is 1/3 inches is represented by ((1)/(3))^3 .


Step-by-step explanation:

Given: The side length of cube =(1)/(3) inches

The volume of cube with side length 'a' is given by :-

Volume=a^3, where base=a and power =3

Therefore, the volume of cube with side length (1)/(3) inches is given by :-

Volume=((1)/(3))^3

Here, Base= (1)/(3)

Power=3


Answer 2
Answer: base: 1/3
Exponent: 3
Hope this helped


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An object moves backwards from where it starts 100 meters in 20 seconds. What is the velocity of the object? Select one:

5 m/s2


-5 m/s


5 m/s


- 5 m/s2

Answers

5m/s

The formula to find the velocity is distance/time.

So 100/20 is 5m/s.
It’s not 5m/s2 because this is the unit for acceleration.
And it’s not negative because it is not possible for the velocity to be negative.

Hope this helped. Mark me Brainliest please:)

workers at the botanical gardens are building a new triangular pond as shown. They need to fill the bottom with pebbles. One bag of pebbles fills 1 m sqaure. How many bags of pebbles will they need?

Answers

A = bh/2
A = 2.4 x 3 / 2
A = 7.2 / 2
A = 3.6 m²

They will need 4 bags of pebbles.

What is the value of (16^3/2)^1/2

Answers

Lets see,

16^{{3/2}^(1/2)}=16^(3/2 \cdot 1/2)=16^(3/4)=2^(3)=8.

Hope this helps.

How can you use algebraic expressions to solve problems?

Answers

Final answer:

Algebraic expressions can be used to solve problems in mathematics by representing unknown quantities with variables, setting up equations based on given information, and using algebraic manipulation to find the values of the variables.

Explanation:

Algebraic expressions can be used to solve problems in mathematics by representing unknown quantities with variables, setting up equations based on given information, and using algebraic manipulation to find the values of the variables. Here is a step-by-step process to solve problems using algebraic expressions:

  1. Read the problem carefully and identify the quantities involved.
  2. Choose variables to represent the unknown quantities.
  3. Write down the information given in the problem as equations using the variables.
  4. Simplify and manipulate the equations using algebraic operations, such as addition, subtraction, multiplication, and division.
  5. Solve the equations to find the values of the variables.
  6. Check your solution by substituting the values back into the original equations.

Learn more about algebraic expressions here:

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Final answer:

Algebraic expressions can be used to solve problems by representing unknown quantities with variables and using equations to find their values. It is important to read the problem carefully, identify the unknowns, and set up equations to solve for the variables.

Explanation:

Algebraic expressions can be used to solve problems in mathematics by representing unknown quantities with variables and using equations to find the values of those variables. When faced with a problem, you can set up an algebraic equation using the given information and solve for the unknown variable. For example, if you are asked to find the value of a number when it is multiplied by 5 and added to 10, you can write the equation as 5x + 10 = unknown value, where x represents the unknown number. By solving this equation, you can determine the value of the unknown number.

When using algebraic expressions to solve problems, it is important to carefully read and understand the problem, identify the unknowns, and define variables to represent them. Once the unknowns are identified, you can use the given information to set up equations and solve for the variables. It is also important to check the solution to ensure that it makes sense in the context of the problem.

Learn more about Algebraic expressions here:

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A sporting goods store sold 2.5 times as many footballs as basketballs last year. Which statement is true?1.The ratio of footballs to basketballs is 2:5
2.If a total of 35 footballs and basketballs were sold, 10 of them were footballs.
3.There were 5 footballs sold for every 2 basketballs.
4.The ratio of basketballs to footballs is 5:2.

Answers

Answer:

3. There were 5 footballs sold for every 2 basketballs.

Step-by-step explanation:

Let the number of basketball = x and the number of football = y.

It is given that, 'the number of footballs were 2.5 times the number of basketballs last year'.

That is, y= 2.5x

That is, (y)/(x)=(2.5)/(1)

That is, (y)/(x)=(5)/(2)

That is, the ratio of football to basket ball is 5 : 2.

Which means, 'For every 2 basketballs, 5 footballs were sold'.

So, option 3 is true but options 1 and 4 are not true.

Moreover, 'if there were total 35 balls sold', we have,

x+y=35

i.e. x+2.5x=35

i.e. 3.5x=35

i.e. x= 10

So, y= 2.5x implies y= 2.5* 10 i.e. y= 25.

Thus, for total 35 balls sold, 10 were basketballs and 25 were footballs.

So, option 2 is not true.

Hence, the correct answer is option D.

THE ANWSER IS 2 CAUSE U HAVE TO DIVIDE


a spinner marked with four sections blue, green, yellow, and red was spun 100 times. find the experimental probability of landing on blue

Answers

25 because onehundred divided by four is 25