Using the formula q = mcΔT, and substituting the values for mass, specific heat capacity of iron, and temperature change, it is calculated that it takes approximately 3.058 KJ to warm 125 g of iron from 23.5 °C to 78.0 °C.
To calculate the amount of heatneeded to warm 125 g of iron from 23.5 °C to 78.0 °C, we use the formula q = mcΔT, where 'm' is the mass in kilograms, 'c' is the specific heat capacity, and 'ΔT' is the temperature change. In this case, the mass 'm' is 0.125 kg (since 1 g = 10^-3 kg), the specific heat capacity 'c' of iron is 0.449 J/g°C (or 449 J/kg°C), and 'ΔT' is 78.0 °C - 23.5 °C = 54.5 °C.
Substituting these values into the formula, we get q = (0.125 kg) * (449 J/kg°C) * (54.5 °C), which gives a result of approximately 3.058 KJ.
Therefore, it would take approximately 3,058 KJ to warm 125 g of iron from 23.5 °C to 78.0 °C.
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To warm 125 g of iron from 23.5 °C to 78.0 °C, it requires approximately 3.93 kilojoules of energy.
To calculate the number of kilojoules required to warm 125 g of iron from 23.5 °C to 78.0 °C, we can use the formula:
q = m * c * ΔT
Where:
Using the given values:
Substituting the values into the formula:
q = 125 g * 0.450 J/g°C * (78.0 °C - 23.5 °C)
Simplifying the equation:
q = 125 * 0.450 * (78.0 - 23.5)
q ≈ 3933.75 J ≈ 3.93 kJ
Therefore, it requires approximately 3.93 kilojoules of energy to warm 125 grams of iron from 23.5 °C to 78.0 °C.
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Answer:
C. It is a negative ion that has one more valence electron than a neutral bromine atom.
Explanation:
took test
B. Higher
Lower Temperature
The boiling point is defined as the temperature at which the vapor pressure of a given liquid becomes equal to the external pressure or atmospheric pressure. Boiling point is mainly effected by following factors:
1) Inter-Molecular Interactions:
Greater the intermolecular interactions greater will be the boiling point because more energy is required to overcome these intermolecular interactions.
Example:
Water = 100 °C
Diethyl ether = 34.5 °C
Water requires more energy because it contains hydrogen bond interactions which are considered the strongest intermolecular interactions. While, Diethyl ether lacks Hydrogen bondings.
2) External Pressure:
The boiling point also varies with changing the external pressure for the same solvent. Greater the external pressure greater will be the boiling points and vice versa.
Example:
Water:
External Pressure Boiling Point
1 atm 100 °C
0.921 atm 98 °C
0.425 atm 72 °C
B) neutralization
C) deposition
D) reduction
B) KBr
C) CH3CH2OH
D) HCl
E) C6H6
How is this determined?