Answer:
Comets are composed of ice, dust and frozen gases. The core of the comet is known as nucleus which is formed of rocks and frozen gases. Coma is the atmosphere of the comet. As the comet enters the inner solar system, the coma expands due to sublimation of frozen gases. As it nears the sun, the coma extends backwards and forms a long tail. It extends backwards due to the solar wind. The charged particles from the sun take away the evaporated material and dust of the comet backwards forming tail.
As a comet approaches the Sun, it starts to heat up. The ice transforms directly from a solid to a vapor, releasing the dust particles embedded inside. Sunlight and the stream of charged particles flowing from the Sun – the solar wind – sweeps the evaporated material and dust back in a long tail.
What is the percent yield of NH3 if the reaction of 26.3 g of H2 produces 79.0 g of NH3?
The balanced chemical reaction is:
N2 + 3H2 = 2NH3
We are given the amount of H2 being reacted. This will be our starting point.
26.3 g H2 (1 mol H2 / 2.02 g H2) 2 mol O2/3 mol H2) ( 17.04 g NH3 / 1mol NH3) = 147.90 g O2
Percent yield = actual yield / theoretical yield x 100
Percent yield = 79.0 g / 147.90 g x 100
Percent yield = 53.4%
Answer:
3.6*105g CH4
Explanation:
The detailed solution is shown on the image. From the detailed chemical reaction, we calculate the mass of methane required in the standard combustion reaction of methane and use it to estimate the mass required to produce the quantity of heat required in the question.
To supply the energy needed for an average home in Colorado, approximately 3.58 x 10^8 grams of natural gas (methane) must be burned.
To calculate the amount of natural gas (methane) required to supply the energy needed for an average home in Colorado, we can use the balanced chemical equation for the combustion of methane:
CH4(g) + 2O2(g) → CO2(g) + 2H2O(l)
The molar enthalpy change for this reaction (ΔH°rxn) is -890.4 kJ/mol. First, we need to convert the energy requirement from kilojoules to joules:
2.00 x 107 kJ = 2.00 x 1010 J
Next, we can use the molar enthalpy change to calculate the number of moles of methane required:
moles of CH4 = energy requirement / mlar enthalpy change
moles of CH4 = 2.00 x 1010 J / (-890.4 kJ/mol)
Finally, we can convert the number of moles of methane to grams using the molar mass of methane:
molar mass of CH4 = 12.01 g/mol + 4(1.008 g/mol) = 16.04 g/mol
grams of CH4 = moles of CH4 * molar mass of CH4
Therefore, the number of grams of natural gas (methane) that must be burned to supply this energy is approximately:
grams of CH4 = (2.00 x 1010 J / (-890.4 kJ/mol)) * 16.04 g/mol
Simplifying the calculation:
grams of CH4 ≈ 3.58 x 108 g
#SPJ3
2) C6H12O6
3) N2
4) O2
Answer:
Explanation:
We have to keep in mind that a good conductor would be a substance that has the ability to produce ions (charged species). These species are responsible for the electricity conduction on water.
Therefore, we have to check which ones of these compounds will produce ions in water. For and we have diatomic molecules (also gases) this type of molecules don't have the ability to produce ions due to his simplicity, they already are very stable.
In the sugar molecule we have a covalent compound. The ions are produced by ionic compounds. So, this molecule can be discarded too.
For we have an ionic compound that have the ability to produce ions:
So, this is the compound that would be a good conductor due to the and the ions.
Answer:
11.0L of carbon dioxide is produced
Explanation:
Balanced equation:
According to balanced equation, 1 mol of produces 1 mol of
So, 0.489 mol of produces 0.489 mol of
Let's assume behaves ideally.
So,
where P is pressure, V is volume , n is number of moles, R is gas constant and T is temperature in kelvin
Plug-in all the values in the above equation-
or,
So, 11.0L of carbon dioxide is produced
B.Exocytosis
C.Osmosis
D.Endocytosis
Answer:
A. Diffusion
Explanation:
A.Diffusion - this is correct. Diffusion is the process where small molecules enter the cell by moving from a high concentration to a low concentration through a semi-permeable membrane.
B.Exocytosis - this is incorrect. Exocytosis is a cell transport mechanism where the cell uses a system of vesicles to transport cargo outside of the cell. The vesicles fuse to the cell membrane and deliver the cargo outside.
C.Osmosis - this is incorrect, osmosis is a type of diffusion specific to water molecules
D.Endocytosis - this is incorrect. Endoocytosis is a cell transport mechanism where the cell uses a system of vesicles to transport cargo into the cell. The cell membrane engulfs the molecules and brings them into the cell via the vesicle