The percentage of coach passengers who did not check their bags will be 43.82 %.
percentage, a relative value indicating hundredth parts of any quantity.
It is given that the total number of passengers is, 162 of which 71 bags didn't check while 91 bags got checked.
We have to find the percentage of coach passengers who did not check their bags.
It is found by dividing the total number of passenger bags not checked by the total number of passengers.
=71 / 162 × 100
=43.82 %
The percentage of coach passengers who did not check their bags will be 43.82 %.
Hence, the percentage of coachpassengers who did not check their bags will be 43.82 %.
To learn more on Percentage click:
#SPJ6
The two-way table below displays information about passengers on a commercial flight.
Passenger Data
First Class
Coach
Checked Bags
10
81
Did Not Check Bags
14
57
What percentage of coach passengers did not check bags? Round to the nearest tenth.
35.2%
41.3%
70.4%
80.3%
To find the % of something simply turn your % to a decimal, then times it by the number you want for ex. .5 * 78 = 39
B. $289.29
C. $140.79
D. $278.29
Answer:
Step-by-step explanation:
13per mile×1080 mile =140.79
Answer:
B
Step-by-step explanation:
if you at $24.74 * 6 = 148.5
then you take 1083 * .13 = 140.79
then add the two number to get 289.29
Answer:
Step-by-step explanation:
Correct option is C)
There are 15 boys and 10 girls in a class
We have to select 3 students such that there should be 1 girl and 2 boys
The number of ways we can select 3 students is
25C3=2300
The number of ways we can select 3 students such that there is 1 girl and 2 boys is 15×7×10=1050
The probability is 1050/2300 =21/46
Therefore the correct option is C
finding the number of combinations for the desired scenario and the total possible combinations, we find that the probability is 21/46.
In order to solve this problem, we need to apply the principles of combinatorics and probability. The total number of students in the class is 25 (10 boys and 15 girls). Firstly, let's calculate the combinations for the scenario of selecting 1 boy out of 10. This can be done by 10C1 resulting in 10 possibilities. Secondly, let's calculate the combinations of selecting 2 girls out of 15, which is 15C2 and gives us 105 possibilities.
Multiply those together to find the total scenario we're interested in, which is 1,050. The total possible combinations of selecting 3 students out of 25 irrelevant of gender would be 25C3, resulting in 2,300 possible combinations.
Therefore, the probability that the selected students are 1 boy and 2 girls is 1,050/2,300. Simplifying this fraction gives us 21/46.
#SPJ11
Answer:
the answer would be it costs $30 for 20 bags of rice
Step-by-step explanation:
divide $3 by 2 to get $1.50 and then multiply $1.50 by 20 to get $30
Answer:
30 dollars
Step-by-step explanation:
2 x 10 equals 20, so multiply 10 by 3 and you get 30.