Answer:
C. a rotation 180° clockwise about the origin followed by a reflection across the line y = x
Step-by-step explanation:
Let us assume that the coordinate of A in triangle ABC is A(x, y)
A) If there is a reflection across line y = x, the new coordinate is at A'(y, x).
If a reflection across the line y = -x is then followed, the new coordinate is at A"(-x, -y)
B) If there is a reflection across line x axis, the new coordinate is at A'(x, -y).
If a reflection across the line y axis is then done, the new coordinate is at
A"(-x, -y)
C) If there is a rotation 180° clockwise about the origin, the new coordinate is at A'(-x, -y).
If a reflection across the line y = x is then followed, the new coordinate is at A"(-y, -x)
D) B) If there is a reflection across line y axis, the new coordinate is at A'(-x, y).
If a reflection across the line x axis is then done, the new coordinate is at
A"(-x, -y)
Since only option C has a different result from the remaining options, hence option C would not five triangle A'B'C'
Answer:
C. a rotation 180° clockwise about the origin followed by a reflection across the line y = x
Step-by-step explanation:
Let us assume that the coordinate of A in triangle ABC is A(x, y)
A) If there is a reflection across line y = x, the new coordinate is at A'(y, x).
If a reflection across the line y = -x is then followed, the new coordinate is at A"(-x, -y)
B) If there is a reflection across line x axis, the new coordinate is at A'(x, -y).
If a reflection across the line y axis is then done, the new coordinate is at
A"(-x, -y)
C) If there is a rotation 180° clockwise about the origin, the new coordinate is at A'(-x, -y).
If a reflection across the line y = x is then followed, the new coordinate is at A"(-y, -x)
D) B) If there is a reflection across line y axis, the new coordinate is at A'(-x, y).
If a reflection across the line x axis is then done, the new coordinate is at
A"(-x, -y)
Since only option C has a different result from the remaining options, hence option C would not five triangle A'B'C'
B) yes, by SAS criterion
C) yes, by SSA criterion
D) no, not possible to tell.
Answer:
ΔABE ~ ΔCDE by AA criterion .
Option (A) is correct .
Step-by-step explanation:
As given
∠BAE = 45° and ∠CED = 70°
Now in the ΔABE .
By apply angle sum property of a triangles .
∠ABE + ∠BEA + ∠BAE = 180 °
(As ∠BAE = 45° , ∠ABE = 65°)
65 + ∠BEA + 45 = 180 °
∠BEA = 180° - (65+45)°
∠BEA = 180° - 110°
∠BEA = 70°
As in ΔCED .
∠CDE + ∠DEC + ∠ECD = 180°
(As ∠CED = 70° , ∠CDE = 65°)
65 + 70+ ∠ECD = 180°
∠ECD = 180° - (65+70)°
∠ECD = 180° - 135°
∠ECD = 45°
Now in the ΔABE and ΔCDE .
(1) ∠BAE =∠ECD = 45°
(2) ∠BEA=∠CED = 70°
(3) ∠ABE = ∠CDE = 65°
Thus ΔABE ~ ΔCDE by AA criterion .
Option (A) is correct .
Answer:
equilateral right triangle
Step-by-step explanation:
7^2+7^2=c^2
49+49=c^2
c^2=98
c=10
Therefore, equilateral right triangle
Answer:
SHHESSHHH
Step-by-step explanation:
sorry... for putting deez nu...
Answer:
i cant like give you the answer off the top of my head but when i did this the video helped me a lot
Step-by-step explanation:
its How to Graph the line y = x by Cowan Academy