It will take a car, 2.59 s to accelerate from 15.2 to 23.5 m/s.
speed is described as. the pace at which an object's location changes in any direction. Speed is defined as the distance traveled divided by the travel time. Speed is a scalar quantity because it just has a direction and no magnitude.
Given, the car has an average acceleration of 3.2 m/s².
To solve this problem, we can use the following kinematic equation:
v = u +at
where:
v is the final velocity (23.5 m/s)
u is the initial velocity (15.2 m/s)
a is the acceleration (3.2 m/s^2)
t is the time
We can rearrange this equation to solve for t:
t = (v -u)/a
substituting the values we have:
t = (23.5 - 15.2 ) / 3.2
t = 2.59375 seconds
Therefore, it will take approximately 2.59 seconds for the car to accelerate from 15.2 m/s to 23.5 m/s with an average acceleration of 3.2 m/s².
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Hello!
How long will it take a car to accelerate from 15.2 m/s to 23.5 m/s if the car has an average acceleration of 3.2 m/s² ?
We have the following data:
Vf (final velocity) = 23.5 m/s
Vi (initial velocity) = 15.2 m/s
ΔV (speed interval) = Vf - Vi → ΔV = 23.5 - 15.2 → ΔV = 8.3 m/s
ΔT (time interval) = ? (in s)
a (average acceleration) = 3.2 m/s²
Formula:
Solving:
Answer:
The car will take approximately 2.6 seconds to accelerate
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9 answer hai brown
Data;
The is the rate of energy used to time. It is the measure of expedience of energy.
a). How many minutes is the dryer used in a month.
Assuming there 30 days in a month;
This shows that the dryer is used 300 minutes in a month.
b). How many hours is the dryer used in a month.
To solve this problem, we simply need to convert the value of (a) from minutes to hours.
The dryer was used for a total of 5 hours in a month.
c). The power of the dryer in kilowatt.
To convert the power in watt to kilowatt, we divide by 1000.
The power in kilowatt is 1.2kw
d). How many kilowatt/hr of electricity used in a month.
The dryer consumes 6kw/h in a month.
e). If the town charges $0.15/kwh, the cost in a month
The cost of the dryer in a month is $0.9.
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By utilizing principles of projectile motion, it is found that the football clears the crossbar by approximately 10.75 meters.
To determine by how much the ball clears or falls short of clearing the crossbar, we need to use the physics principles of projectile motion. The maximum height 'h' of the football can be given by equation of motion: h = (v²sin²θ) / (2g), where 'v' is the initial velocity, 'g' is the acceleration due to gravity and 'θ' is the angle of projection.
Substituting the given values: h = [(20)²sin²53°] / (2*9.8) ≈ 13.8 m above the ground when it was kicked. However, the football was kicked from ground level, so we need to subtract the height of the crossbar from this value, which is 3.05 m. Thus, the ball clears the crossbar by approximately: 13.8 - 3.05 = 10.75 m.
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Answer:
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Explanation:
The speed of the electron before reaching the positive plate is
Explanation:
As per Gauss law of electro statistics, the electric field generated by a capacitor is directly proportional to the surface charge density of the plate and inversely proportional to the dielectric constant. In simple words, the electric field is proportional to the surface charge density. So,
And then from the second law of motion,
So acceleration exerted by the electrons will be directly proportional to the force exerted on them and inversely proportional to the mass of the electron.
Since force is also calculated as product of charge with electric field in electrostatic force,
So, the charge of electron
m is the mass of electron which is equal to
Then,
So the acceleration of the electron in the capacitor will be
Then, the velocity can be observed from the third equation of motion.
As u = 0 and s is the distance of separation between two plates.
Thus,
So, the speed of the electron before reaching the positive plate is .