A 1.0 µC test charge travels along an equipotential line a distance of 0.20 cm between two parallel charged plates with a field strength of 500.0 N/C. What is the change in voltage? (µC = 1.0 × 10^-6 C)

Answers

Answer 1

Answer:
This question is written by a master of deception and distraction.
It's full of so many red herrings that it's tough to walk past it too closely.

In order to answer this question correctly, you don't need to know
the magnitude of the test charge, the distance it travels, or the field
strength between the plates. The whole question lies in that magic
word "equipotential".

An 'equipotential' line is a path along which the electrical potential
is the same at every point. It's analogous to a 'contour line' on a
topographic map, or an isobar on a weather map.

A charge moving along such a line uses no energy to travel that path,
and it encounters no change in voltage anywhere in its travels.

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A positive charge is placed in an electric field that points west. What direction is the force on the positive particle?

Answers

A positive charge is placed in an electric field that points west. the direction of the force on the positive particle point toward the west.

What is an electric charge?

Due to the physical characteristic of electric charge, charged material experiences a force when it is exposed to an electromagnetic field. Electric charges can be positive or negative (commonly carried by protons and electrons respectively). While like charges repel one another, opposite charges attract. If an object has no net charge, we refer to it as neutral.

The charge on one electron is -1.6 ×10⁻¹⁹ coulomb.

As given in the problem statement when a positive charge is placed in an electric field that points west. the direction of the force on the positive particle will also point toward the west because for a positively charged

particle the direction of the electric field is the same as the force.

Thus, a positive charge is introduced into a westward-pointing electric field. the force acting on the positive particle points westward

Learn more about an electric charge from here

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The direction of the electric field is defined as the direction of the force on a
positive charge immersed in the field. The force on the particle points west.

Which of the following questions best highlights a shortcoming of the big bang theory? A. How could energy become the matter present today?
B. What makes people think that the universe started from a single point?
C. How can all galaxies be moving away from Earth?
D. What was the cause of the big bang?

Answers

A. How could energy become the matter present today?

Answer:

What was the cause of the big bang theory?

Explanation:

What is the acceleration due to gravity at a location where a 15 kilogram mass weighs 45 newtons?

Answers

   Weight = (mass) x (acceleration of gravity) .

   45 N = (15 kg) x (acceleration of gravity) .

Divide each side by (15 kg):

   Acceleration of gravity = (45 N) / (15 kg)

   = 3 m/s² .

The acceleration due to gravity at the place where the weight of the body is $45\,{\text{N}}$ is $\boxed{3\,{{\text{m}}\mathord{\left/{\vphantom{{\text{m}}{{{\text{s}}^{\text{2}}}}}}\right.\kern-\nulldelimiterspace}{{{\text{s}}^{\text{2}}}}}}$ .

Further Explanation:

Given:

The mass of the body is $15\,{\text{kg}}$ .

The weight of the body is $45\,{\text{N}}$ .

Concept:

The weight of an object or a body is the measure of the force of the gravity or the Earth’s gravitational force acting on the body. It is the amount of force with which the body is being pulled towards the center of the Earth.

The weight of the body is expressed as the product of the mass and the acceleration due to gravity on the surface.

The expression for the Weight of any body is written as:

$\boxed{W=mg}$

Here, $W$ is the weight of the body, $m$ is the mass and $g$ is the acceleration due to gravity.

Substitute the values of mass and the weight in above expression.

$\begin{aligned}45&=15*g\ng&=\frac{{45}}{{15}}\,{{\text{m}}\mathord{\left/{\vphantom{{\text{m}}{{{\text{s}}^{\text{2}}}}}}\right.\kern-\nulldelimiterspace}{{{\text{s}}^{\text{2}}}}}\n&=3\,{{\text{m}}\mathord{\left/{\vphantom{{\text{m}}{{{\text{s}}^{\text{2}}}}}}\right.\kern-\nulldelimiterspace}{{{\text{s}}^{\text{2}}}}}\n\end{aligned}$

Thus, the acceleration due to gravity at the place where the weight of the body is $45\,{\text{N}}$ is $\boxed{3\,{{\text{m}}\mathord{\left/{\vphantom{{\text{m}}{{{\text{s}}^{\text{2}}}}}}\right.\kern-\nulldelimiterspace} {{{\text{s}}^{\text{2}}}}}}$ .

Learn More:

1. A 30.0-kg box is being pulled across a carpeted floor by a horizontal force of 230 N brainly.com/question/7031524

2. A horizontal rope is tied to a 50 kg box brainly.com/question/2416204

3. Why is it important to define a frame of reference brainly.com/question/526888

Answer Details:

Grade: High School

Subject: Physics

Chapter: Newton’s law of Motion

Keywords:

Weight, mass, acceleration due to gravity, gravity at the location, weighs 45 newtons, 15 kilogram, w=mg, g=3m/s^2, weight of the object.

What is the advantage of a gold leaf electroscope ?

Answers

It's to determine if there is a charge on an object/body or not and what kind of charge as well. Hope this can help!

N a nuclear reaction, mass must be lost to produce energy. true or false

Answers

The answer is true. Nuclear reactions, unlike chemical reactions, do not explicitly follow the law of conservation of mass in the sense that part of the mass is lost in nuclear reactions. In nuclear reactions, some of the mass is actually converted to energy. This is made possible due to Einstein's equation: E = mc^2. Also, nuclear reactions make use of nucleons which give off greater energies than chemical reactions.

Michelle melted a compound in the lab and performed the same procedure five times. The chart below shows the time it took for the compound to melt during the five trials.Trial Time (min:sec)
1 3:14
2 3:10
3 4:05
4 3:12
5 3:09

After reviewing her data, she realized that trial 3 was vastly different from the other four trial times. Which of the following reasons could explain the radical difference in melting time for trial 3?

A larger quantity of compound was used in trial 3.
The compound started at a lower temperature in trial 3.
The burner was not directly under the compound during trial 3.
all of these

Answers

Answer:

It is actually all of these

Explanation:

Final answer:

Several factors could account for the variance seen in the third trial's melting time. This could be due to using a larger quantity of compound, starting at a lower temperature, or the burner not being directly under the compound.

Explanation:

The radical difference in melting time for trial 3 in Michelle's experiment could be explained by several variables. Given the information present, Michelle could have used a larger quantity of compound in trial 3, thus taking longer to melt. Secondly, the compound may have started at a lower temperature, requiring additional time to reach its melting point. Finally, if the burner was not directly under the compound, this could also explain the longer time as the heat wouldn't be as concentrated on the compound. In other words, the answer could be 'all of these' as they are all potential reasons as to why the third trial had a heavier melting time.

Learn more about Melting Time here:

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