Write the sum of numbers as a product of their gcf and another sum 36+45

Answers

Answer 1
Answer: So, the sum of numbers will be the result of 36+45, that is 81.

Let's find the GCF: it's at least 9, since both numbers are divisible by 9 (36/9=4; 45/9=5)

so 81 (the sum of the numbers) equals 9*9 (where 9 is the gfc)

and the answer is 81=(4+5)*9, where 4+5 is the "another sum".


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Eighteen increased by x

Answers

Answer:

Answer is 18x

Answer:

18 + x

Step-by-step explanation:

Eighteen increased by x

18 increased by x means

that  x is added to 18

= 18 + x

What is the rate for 4 pounds in 20 years what is the unit rate for 1 year

Answers

4 pounds in 20 years

Divide to find how much per year. 

4/20 = 1/5

1/5 pounds per year

Answer: 1/5 pounds per year
4 pounds/ 20 years= 0.2 pounds/year.

The unit rate is 0.2 pounds per year.

What is the simplified value of the expression below?
-8*(-3)
-24

Answers

Answer:

24

Step-by-step explanation:

Multiply −8 by −3 =24

two negatives = a positive answer

a negative and a positive = a negative answer

two positive = positive answer

435 L = ______ KL

So what do i put in the blank spot ?? i dont know how to do this

Answers

1000\ L-1KL\n 435\ L-x\n \n1000\cdot x=435\cdot1\cdot \ KL\ /:1000\n \nx=0.435\ KL
1 KL = 1000 L

Thus, 435 L = 435/1000  KL

435/1000 = 0.435

Thus, 435 L = 0.435 KL

What is the solution to the proportion?  8/4=11/M Answers: A. M=3 B. M=5.5 C. M=7 D. M=22

Answers

find their lcm  which is 4m then multiply
8m=44
m=44/8 or 5.5

Urgent!!!??In an experiment the colours of 50 cars passing was recorded. 17 silver cars were recorded. What is the relative frequency of a silver car passing?

40 is rounded to the nearest whole. write down the maximum possible length it could have been?

Solve 4x≤10

Thanks for your help!

Answers

Okay, I stink at math. But I do know the last one, which is something. 

You have to divide the 4 by 4 and then get the x alone, but what is done to one side you have to do to the next so, 10/4 = 2.5 

So x ≤ 2.5 

I hopes this helps somewhat.