a triangular shape has an area of 70 square inches the height is 8 and three fourths what is an equation for this answer
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So if you have a triangular shap and the area is 70 for the triangle shape you will moltiply 70 times 8 times 3/4 = The awnser. I hop i helped.
It would be 70=8 3/4 (1/2)
How to write 50/9 in equivalent mixed numbers
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Should be 5 5/9 I believe.
You would divide 50 by 9 and you would end up with a result of 5 and 5/9th's. Good luck on the rest of your homework ;)
The measure of the supplement angle is fourteen times greater than its supplement
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Let's assume you have supplement angle
Now when you talk about multiplication you can simply say...
And that will give you the answer.
A rectangular pool is 20 feet wide and 50 feet long. A deck used for sunning surrounds the pool. The deck is the same width all the way around the pool. The total area of the deck is 456 square feet. How wide is the walkway?A. 2 feet B. 3 feet C. 4 feet D. 5 feet
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Ahh, this question goes all the way back to my year 9 test a couple years ago; which I got wrong back then - I now know how Firstly we find the expression for the area (using x as the walk way): >50x * 2 (the left and right) >20x * 2 (the top and bottom) >4 * x^2 (the corners) Add them all together , Area = 140x + 4x^2 Now we place the deck's area, 456 into the expression
456 = 140x + 4x^2
Solve for x I'm a bit rusty on this i'm afraid, but I believe the only way to solve this is to factorise it 0 = 4x^2 + 140x - 456 0 = 4(x+38)(x-3) < x must = -38 or = +3 (the numbers inside the brackets inverted) x must = +3 as it's logical, you can't have a negative width The walkway is 3 feet wide, we can put this into our expression to double check this, 456 = 140*(3) + 4(3)^2 456 = 420 + 4*9 456 = 420 + 36 456 = 456 Yes, 3 feet wide is correct.
*Note, I tried to keep this simple, please let me know if I didn't go into enough detail anywhere
The answer is b. 3 ft
the lengths of two sides of a triangle are 3 centimeters and five centimeters write an inequality to represent the range of values for the third side
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There exists one simple and interesting conclusion for triangle, that is the sum of any two sides's length are longer than the other side and the difference between the length of any two sides is smaller than the other side, If, we use L to denote the length of the third side, we can conclude that: 5-3<L<5+3