Who was the man who lived from 460B.C.–370B.C. and was among the first to suggest the idea of atoms?a. Atomos
c. Democritus
b. Dalton
d. Thomson Please select the best answer from the choices provided A B C D

Answers

Answer 1
Answer: c. Democritus was a Greek philosopher who defined the concept of atoms and is the only one of the answer choices who lived during that time period.

Related Questions

If the pressure in a gas container that is connected to an open-end U-tube manometer is 116 kPa and the pressure of the atmosphere at the open end of the tube is 752 mm Hg, the level of mercury in the tube will a. be 870 mm higher in the arm open to the atmosphere. b. be 870 mm higher in the arm connected to the gas cylinder. c. be 118 mm higher in the arm connected to the gas cylinder. d. be 118 mm higher in the arm open to the atmosphere.
Matter behaving like a wave rather than like a particle is best illustrated by which phenomenon?
A 20 kg crate of books is at rest on a table. what is the normal force on the books?
if a gas has a gage pressure of 156 kpa its absolute pressure is approximately .....A... 56 kPa ....B....100 kPa.......C......256 kPa....D...300 kPa.....
An object placed in water will float if the weight of the object is MORE THAN the buoyant force of the water.TrueFalse

If only a green light shown on a bunny that has black and white fur, what would the bunny look like?

Answers

The white fur reflects all colors, so would appear green.
The black fur reflects no colors, so would still appear black.

Answer:

Green and Black.

Explanation:

The white fur reflects all colors, so would appear green.

The black fur reflects no colors, so would still appear black.

What is the percent by mass of 5.0 g of iron (II) sulfate dissolved in 75.0 grams of water?

Answers

Considering the definition of percentage by mass, the percent by mass of 5.0 g of iron (II) sulfate dissolved in 75.0 grams of water is 6.25 %.

The percentage by mass expresses the concentration and indicates the amount of mass of solute present in 100 grams of solution.

In other words, the percentage by mass of a component of the solution is defined as the ratio of the mass of the solute to the mass of the solution, expressed as a percentage.

The percentage by mass is calculated as the mass of the solute divided by the mass of the solution, the result of which is multiplied by 100 to give a percentage. This is:

percent by mass= (mass of solute)/(mass of solution)x100

In this case, you know:

  • mass of solute= 5 g
  • mass of water= 75 g
  • mass of solution= mass of solute + mass of water= 5 + 75 g= 80 g

Replacing:

percent by mass= (5 g)/(80 g)x100

Solving:

percent by mass= 6.25 %

Finally, the percent by mass of 5.0 g of iron (II) sulfate dissolved in 75.0 grams of water is 6.25 %.

Learn more:

Hello!

What the percent by mass of 5.0 g of iron (II) sulfate dissolved in 75.0 g of water?

We have the following data:

m1 (solute mass - iron II sulfate) = 5.0 g

m2 (solvent mass - water) = 75.0 g

m (solution mass) = m1 + m2 = 5.0 + 75.0 = 80.0 g

%m/m (percent mass by mass) = ?

We apply the data to the formula

\%\:m/m = (m_1)/(m)*100

\%\:m/m = (5)/(80)*100

\%\:m/m = 0.0625*100

\boxed{\boxed{\%\:m/m = 6.25}}\Longleftarrow(solute\:in\:percent)\:\:\:\:\:\:\bf\blue{\checkmark}

Answer:  

The percent by mass of solute and mass solution of Iron II Sulfate is 6.25%  

_______________________  

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A object of mass 33 is dropped from a height of 85 meters. Calculate the average power developed by the object in falling through this distance.Take g as 9.81 m/s^2

give the answer in watts to three significant figures

Answers

Power  =  Work done  /  Time taken.

Work done =  mgh
Mass, m = 33kg    ( Am presuming it is 33 kg).
h =  85 m.
Work done =  33 * 9.81* 85 =  27517.05  J.

Time taken.
Since object was dropped from height, it fell under gravity.
Using    H =  ut  +  (1/2) * gt^2.              u = 0.
               H =  1/2 gt^2.
               t  =   (2H/g) ^ (1/2)
               t  =  (2*85/9.81) ^ 0.5 =  4.1628 s.

Power  =    27517.05 / 4.1628 = 6610.23 Watts.
             =  6610 W  to  3 S. f.

A _______ is a repeating disturbance or vibration that transfers or moves energy from place to place without transporting mass.force
wave
vacuum
medium
PLZ help me!

Answers

Answer: wave

Explanation:

These are the basic definitions and characteristic of the terms given, which show tha the only rigth answer is the second option: wave.

1) Force is an interaction. There are four natural forces: electrostatic, gravity, strong nuclear force and weak nuclear force.

2) Wave: is a sequence of pulses or vibrations that cause the continuous transportation of energy (propagation). There is not transport of mass, only energy.

Some examples of waves are sound waves, electromagnetic waves (light, radio waves, micro waves, infrarred waves, ultraviolet waves).

3) Vacuum: is the absence of matter; empty space. Only electromagnetic waves can travel through vacuum; other waves need a medium to travel.

4) Medium: any matter is a medium: a solid, the air, a liquid, all of them are media through which waves can transport its energy, depending of the wavelength.

A wave, waves transport energy rather than matter from one area to another.
An example of this is conduction of thermal energy, for instance when you heat up a saucepan the metal areas of the pan not touching the heat source still heat up due to waves of thermal energy (conduction)

Draw the Lewis dot Structure for the molecule C2H6​

Answers

Answer:

This means that the Lewis dot structure for C2H6 must account for 14 valence electrons, either through bonding between atoms, or through lone pairs. So, the two C atoms are placed in the center of the molecule.

Specific data such as age, income, family size, and occupation, used for marketing purposes, is called A. a secondary market.
B. demographics.
C. survey statistics.
D. the target market.

Answers

Answer;

B. demographics.

Specific data such as age, income, family size, and occupation, used for marketing purposes, is called  demographics.

Explanation;

  • Demographics are features of a particular population. It involves the study of a population based on factors such as age, sex, race, family size and occupation, etc.
  • For marketing purposes firms or companies use specific data such as age, income, family size, religion, race, nationality and occupation. This may be referred to as demographic segmentation, which is used by the companies to get the right population using their products.
B. demographics.

Specific data such as age, income, family size, and occupation, used for marketing purposes, is called demographics.
NOT:
A. a secondary market.
C. survey statistics.
D. the target market.