An object placed in water will float if the weight of the object is MORE THAN the buoyant force of the water.True
False

Answers

Answer 1
Answer:

False


If the object weighs more than the buoyant force then the object will sink.

This is because the buoyant force "pushes" the object upwards and the weight of the object "pushes" the object downwards.  Since the force downwards is greater than the force upwards the item will sink, so this statement is False.

~~~Brainliest would be appreciated~~~

Answer 2
Answer: I think the answer is true

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A high pressure center is generally characterized by

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A high pressure center is generally characterized by cool, dry weather. The movement is cause by the addition of forces due to gravity because their higher pressure compresses the column of air near the center of the area nto greater density and so greater weight compared to lower pressure, lower density and lower weight of the air outside the center.

The second law of thermodynamics states that whenever energy changes occur, __________ always increases.

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The second law of thermodynamics states that whenever energy changes occur, DISORDER always increases.

Final answer:

The Second Law of Thermodynamics states that entropy, which represents the disorder or randomness in a system, always increases when energy changes occur. An example would be heat dispersing from a hot drink into the environment.

Explanation:

The Second Law of Thermodynamics states that whenever energy changes occur, entropy always increases. Entropy refers to the degree of disorder or randomness in a system. Thus, the law is essentially asserting that natural processes tend towards chaos or disorder. For example, if we consider a cup of hot coffee left on a table, with time, the heat (energy) from the coffee disperses into the surrounding environment, leading to an increase in entropy. This concept applies universally in closed systems, where energy cannot enter or leave.

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Assume that you have 0.480 mol of N2 in a volume of 0.700 L at 300 K . 1. Calculate the pressure in atmospheres using the ideal gas law.
2. Calculate the pressure in atmospheres using the van der Waals equation. For N2 , a=1.35 (L2⋅atm)/mol2 , and b=0.0387 L/mol

Answers

Answer:

1) 16.88 atm

2) 34.47 atm

Explanation:

Data:

Volume=0.700L

Temperature = 300K

Number of moles=0.480 mol

Ideal gas constant=0.082057 L*atm/K·mol

1) The ideal gas law is:

PV=nRT (1)

with P the pressure, T the temperature, n the number of moles, V the volume and R the ideal gas constant , so solvig (1) for P:

P=(nRT)/(V)

P=((0.480)(0.082057)(300))/(0.700)=16.88 atm

2) The vander Walls equation is:

(P+(a)/(V^(2)))(V-b)=RT

solving for P

P=(RT)/(V-b)-(a)/(V^2)=((0.082057)(300))/(0.700-0.0387)-(1.35)/(0.700^2)=34.47 atm

The pressure in atmospheres is 0.974 atm using the ideal gas law and 0.962 atm using the van der Waals equation for N2.

1. To calculate the pressure in atmosphere using the ideal gas law, we can use the equation PV = nRT, where P is pressure, V is volume, n is the number of moles, R is the ideal gas constant (0.0821 L·atm/mol·K), and T is the temperature in Kelvin.

Rearranging the equation, we have P = (nRT)/V. Plugging in the given values, we get P = (0.480 mol * 0.0821 L·atm/mol·K * 300 K) / 0.700 L = 0.974 atm.

2. To calculate the pressure in atmosphere using the van der Waals equation, we can use the equation (P + an^2/V^2)(V - nb) = nRT, where a and b are constants specific to the gas being used. Rearranging the equation, we have P = (nRT/(V - nb)) - an^2/V^2.

Plugging in the given values and the constants for N2, we get P = (0.480 mol * 0.0821 L·atm/mol·K * 300 K/(0.700 L - 0.0387 L/mol * 0.480 mol))^2 - 1.35 (L^2·atm)/mol^2 * (0.480 mol)^2/(0.700 L)^2 = 0.962 atm.

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Scientific question must be

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Are there any choices with the question?

A block weighing 35 N is resting on a steel table (us = 0.40).The minimum force to start this block moving is ___ N.

Answers

The static friction force is a force that prevents motion of an object kept on a surface, due to the interaction of the surface of the object and the surface on which it is kept

  • The minimum force required to start the block moving is 14 N

Reason:

The known parameter are;

The weight of the block, W = 35 N

The static friction of the surface of the table surface, \mu_s = 0.40

Required:

To find the minimum force to start the block moving

Solution:

The force required to start the block moving is given by the frictional force that needs to be surpassed

Force required, F = Force of friction

Force of friction = Normal reaction × Coefficient of static friction

On a flat surface, the normal reaction = The weight of the object

Force of friction, F_f = Weight of the object × Coefficient of static friction

Which gives;

F_f = W * \mu_s

F_f = 35 \, N * 0.40 = 14 \, N

Force required, F = Force of friction, F_f = 14 N

The minimum force required to start the block moving, F = 14 N

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Answer: 14

Explanation:

Force(normal)*coefficient

The Earth's crustal plates move due to _____ currents.convention
condensation
convection
collaboration

Answers

Answer is C. Convection