Which of the following describes gamma rays?short wavelength, high frequency
short wavelength, low frequency
long wavelength, high frequency
long wavelength, low frequency

Answers

Answer 1
Answer:

Answer: short wavelength, high frequency

Explanation:

Gamma rays are highly energetic electromagnetic waves. High energy implies high frequency.

E = h ν

h is the Planck's constant, ν is the frequency.

For electromagnetic radiation, frequency is inversely proportional to wavelength. Thus, gamma rays have high frequency but short wavelength.

The frequency of gamma rays is greater than 10¹⁹ Hz and wavelength is less 10⁻¹² m.


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A frictionless, massless pulley is attached to the ceiling, in a gravity field of 9.81 m/s2. Mass M2 is greater than mass m1. The quantities Tn and g are magnitudes.a.The center of mass accelerates.
b.T1 is ..... M1g.
c. T3 is ..... m1g + M2g
d.T1 is ..... T2
e.The magnitude of the acceleration of M2 is ..... the magnitude of the acceleration on m1.
f. T1 + T2 is ..... T3

Answers

Answer:

a. center of mass acceleration supposed to be acceleration due to gravity, 9.81 m/s^2,

b. T1 = 9.81m1 N; c. T3 =9.81(M1+M2) N; d. T3-T1, e. (T3-T1)/M2; f. (M1+M2)T3/M3

Explanation:

Final answer:

In this frictionless, massless pulley system, the center of mass accelerates downward with an acceleration equal to the acceleration due to gravity. The tension in the string connected to mass M1 is equal to M1g, and the tension in the string connected to mass M2 is equal to m1g + M2g. The magnitudes of the accelerations of M1 and M2 are equal, and the sum of the tensions T1 and T2 is equal to the tension T3.

Explanation:

a. The center of mass accelerates: When considering the system as a whole, the acceleration of the center of mass is determined by the net external force acting on the system. In this case, the only external force is the force due to gravity. Therefore, the center of mass accelerates downward with an acceleration equal to g, the acceleration due to gravity.

b. T1 is equal to M1g: The tension in the string connected to mass M1 is equal to the weight of M1, which is given by the formula T1 = M1g.

c. T3 is equal to m1g + M2g: The tension in the string connected to mass M2 is equal to the sum of the weights of M1 and M2, which is given by the formula T3 = m1g + M2g.

d. T1 is equal to T2: Since the pulley is assumed to be frictionless and massless, the tension in the string connected to mass M1 is the same as the tension in the string connected to mass M2.

e. The magnitude of the acceleration of M2 is equal to the magnitude of the acceleration on M1: This is due to the constraint imposed by the tension in the string. Since the tension in the string connecting M1 and M2 is the same, their accelerations must also be the same.

f. T1 + T2 is equal to T3: The sum of the tensions T1 and T2 is equal to the tension T3, as the total force acting on mass M2 is equal to the sum of the individual tensions.

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A bicyclist bikes the 56 mi to a city averaging a certain speed. The return trip is made at a speed that is 6 mph slower. Total time for the round trip is 11 hr. Find the​ bicyclist's average speed on each part of the trip.

Answers

Answer:

Speed of the bicyclist when going to city =  14 miles per hour.

Speed while return trip = 8 miles per hour.

Explanation:

Let the speed of the bicyclist when going to city = x miles per hour.

Speed while return trip =  x - 6 miles per hour.

Total time taken = 11 hrs = Time for the trip to city + time taken for return trip.

Also, Time = Distance / Time.

So,

56 / x + 56 / ( x -6) = 11

11x² -178x + 336 = 0

Solving for x we get:

Acceptable x = 14 miles per hour.

Speed while return trip =  x - 6 miles per hour = 8 miles per hour.

Final answer:

To find the average speed on each part of the trip, use the formula Average speed = Total distance/Total time and set up an equation to solve for the unknown speeds.

Explanation:

To find the average speed on each part of the trip, we can use the formula Average speed = Total distance/Total time. Let's assume the average speed on the first part of the trip (56 miles) is x mph. Since the return trip is made at a speed that is 6 mph slower, the average speed on the second part of the trip is (x - 6) mph. We know that the total time for the round trip is 11 hours. So, we can set up the equation:

56/x + 56/(x - 6) = 11

Now, we can solve this equation to find the value of x, which represents the average speed on the first part of the trip. Once we have x, we can find the average speed on the second part of the trip by subtracting 6 from x.

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HELP FAST!!!!!!!Four beakers have water at 27 °C. A piece of metal is dropped into the water in each beaker. The table below shows the initial temperature of the four metals.
A - 30 degrees C
B - 42 degrees C
C - 25 degrees C
D - 16 degrees C
which metals will transfer heat to the water?
A. Metals A and metals B
B. Metals B and metals C
C. Metals C and metals D
D. Metals B and metals D

Answers

Answer

A. Metals A and metals B



Explanation

Heat transfer takes place whenever there is temperature difference. When two bodies of different temperatures are brought together, heat energy will move from one body to the other until equilibrium temperature is reached.

In our case, heat transfer will take place in all four metals.

Metal A will transfer heat to the water since it's temperature is higher than that of water.

Metal B will also transfer heat to the water since it's temperature is higher than that of water.

Metal C will get heat from the water since it's colder than the water.

Metal D will also get heat from the water since it is colder than water.

Answer: a: metals a and metals b :)

Explanation:

Two or more atoms join together to form a ?

Answers

two atoms of the same element can join together to form a molecule

atoms of two or more elements joined together form compounds.

with what minimum speed must you toss a 160 g ball straight up to just touch the 13-m-high roof of the gymnasium if you release the ball 1.4 m above the ground? solve this problem using energy.

Answers

energy at top = m*g*height at top from release point
=0.16*9.81*11.6
=18.21J
At release kinetic energy= Gravtiational energy at top
1/2*0.16*v^2=18.21J
v^2=227.625
v=15.10m/s

When the mass of an object increases, the force of gravityincreases.

decreases.

remains the same.

becomes irregular.

Answers

According to the second law of motion, force is equal to the product of mass and acceleration. This means force is proportional to mass. Hence when mass increases, it is understood that force should increase as well. In this case,the answer to this problem is A. 
Increases. The more mass an object has, the more gravity it has