What is the acceleration due to gravity at a location where a 15 kilogram mass weighs 45 newtons?

Answers

Answer 1

Answer:
   Weight = (mass) x (acceleration of gravity) .

   45 N = (15 kg) x (acceleration of gravity) .

Divide each side by (15 kg):

   Acceleration of gravity = (45 N) / (15 kg)

   = 3 m/s² .

Answer 2

Answer:

The acceleration due to gravity at the place where the weight of the body is $45\,{\text{N}}$ is $\boxed{3\,{{\text{m}}\mathord{\left/{\vphantom{{\text{m}}{{{\text{s}}^{\text{2}}}}}}\right.\kern-\nulldelimiterspace}{{{\text{s}}^{\text{2}}}}}}$ .

Further Explanation:

Given:

The mass of the body is $15\,{\text{kg}}$ .

The weight of the body is $45\,{\text{N}}$ .

Concept:

The weight of an object or a body is the measure of the force of the gravity or the Earth’s gravitational force acting on the body. It is the amount of force with which the body is being pulled towards the center of the Earth.

The weight of the body is expressed as the product of the mass and the acceleration due to gravity on the surface.

The expression for the Weight of any body is written as:

$\boxed{W=mg}$

Here, $W$ is the weight of the body, $m$ is the mass and $g$ is the acceleration due to gravity.

Substitute the values of mass and the weight in above expression.

$\begin{aligned}45&=15*g\ng&=\frac{{45}}{{15}}\,{{\text{m}}\mathord{\left/{\vphantom{{\text{m}}{{{\text{s}}^{\text{2}}}}}}\right.\kern-\nulldelimiterspace}{{{\text{s}}^{\text{2}}}}}\n&=3\,{{\text{m}}\mathord{\left/{\vphantom{{\text{m}}{{{\text{s}}^{\text{2}}}}}}\right.\kern-\nulldelimiterspace}{{{\text{s}}^{\text{2}}}}}\n\end{aligned}$

Thus, the acceleration due to gravity at the place where the weight of the body is $45\,{\text{N}}$ is $\boxed{3\,{{\text{m}}\mathord{\left/{\vphantom{{\text{m}}{{{\text{s}}^{\text{2}}}}}}\right.\kern-\nulldelimiterspace} {{{\text{s}}^{\text{2}}}}}}$ .

Learn More:

1. A 30.0-kg box is being pulled across a carpeted floor by a horizontal force of 230 N brainly.com/question/7031524

2. A horizontal rope is tied to a 50 kg box brainly.com/question/2416204

3. Why is it important to define a frame of reference brainly.com/question/526888

Answer Details:

Grade: High School

Subject: Physics

Chapter: Newton’s law of Motion

Keywords:

Weight, mass, acceleration due to gravity, gravity at the location, weighs 45 newtons, 15 kilogram, w=mg, g=3m/s^2, weight of the object.

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A race car is moving with a velocity of 144 kilometers/hour. The driver applies the brakes, and the car comes to a halt in 12.0 seconds. What is the acceleration of the car after 12.0 seconds?

Answers

The problem gives us the value for the initial velocity of the race car, and the time it takes for the race car to come to a complete stop. The question however, proves to be tricky. The question states as follow: "what is the acceleration of the car after 12.0 seconds?" Since it was already established that the car has come to a halt in 12.0 seconds, therefore, the acceleration would have to be 0, as the car would not be moving at all.

Final answer:

The acceleration of the race car after 12.0 seconds is -3.33 m/s^2.

Explanation:

To find the acceleration of the race car after 12.0 seconds, we need to use the formula for acceleration: acceleration = change in velocity / time. The initial velocity of the race car is 144 km/h, and it comes to a halt, so the final velocity is 0 km/h. We need to convert these velocities to meters per second (m/s) before using the formula.

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Plugging these values into the formula, we get: acceleration = (0 m/s - 40 m/s) / 12.0 s = -3.33 m/s^2.

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Answers

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What is it a graph of ?

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With acceleration and mass, you could calculate the force.

-- Impulse is also the change in momentum.
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I just had the coolest idea: What if you took a picture of the Physics gragh
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Answers

The force which acts on the elevator while it starts its motion are described as follows :

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3. When the elevator stops, the upward force and downward force are equal but opposite in magnitude.

Final answer:

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Explanation:

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While the lift is still or moving at a constant speed, the tension in the cable (T or I) and the weight of the elevator are equal but opposite, so they cancel out. But, as the elevator begins to ascend, the tension in the cable must overcome the weight hence it's larger causing the elevator to accelerate upwards. When the elevator approaches the destined floor and begins to decelerate, the tension eases and becomes lesser than the weight.

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Answers

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