5. Which quantities must be conserved in all chemical reactions?

Answers

Answer 1
Answer:

In every chemical reaction, the number of atoms of each component reactant, mass, and energy must be conserved.

Law of conservation in chemical reactions

The law of conservation in chemistry states that atoms, matter, mass, and or energy in chemical reactions can neither be created nor destroyed but may be converted from one form to another.

Following this law, the quantities that must be conserved in chemical reactions are:

  • atoms
  • mass/matter
  • energy

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Answer 2
Answer: In a chemical reaction, the quantities that must be conserved is Matter ( The law of conservation states matter cannot be created nor destroyed.) If the matter is conserved that means the reactants mass is the same as the product. So if matter is conserved, mass is conserved. Another quantity that must be conserved is the number of particles.
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What experimental evidence did Thomson have for each statement? A. Electrons have a negative charge.
B. Atoms of all elements contain electrons.

Answers

Thomson studied electric discharge in a vacuum and found that the deflection of rays was evidence of atoms containing much smaller particles. He calculated that these particles would have a large charge in relation to their mass. While he did not name electrons, he knew they existed.

Answer : In the experiment of Cathode Ray, Scientist J.J. Thomson found that a stream of electricity was attracted to the positive portion of an electrical plate, which helped him to conclude that there must be a negative aspect to matter. He called this discovery as the electron.

He was the one who suggested that these small, negatively charged particles were actually subatomic particles. Which are now called as "electrons".

Since atoms are found to be neutral, when it contain negatively charged electrons it must also contain some positively charged material.

The compound C3H6 can react with bromine. Write an equation for this reaction and name the product formed. State the visible change which accompanies the reaction.

Answers

Answer:

C3H6 + Br2 = C3H6Br2

The product formed is 1,2-dibromopropane.

The red-brown color of the bromine disappears, leaving a colorless liquid

Explanation:

C3H6 + Br2 = C3H6Br2

The product formed is 1,2-dibromopropane.

This is a direct addition reaction.  The one molecule of bromine (Br2) joins the organic compound C3H6 to form one molecule of C3H6Br2.

This seemed unlikely at first, but one must look more closely at the C3H6.  This is not a straight alkane (e.g., propane).  Propane has the formula C3H8:

  H3-C-C2-CH3

The molecule C3H6 is propylene (or propene).  It has a double bond between two carbons.

H3-CH-CH=CH2

The compound in the question is propylene.  When exposed to bromine, the carbon double bond breaks and a bromine atom is attached to each carbon:

   H3-CH-CH=CH2 + Br2 = H3-CH-CHBr-CHBr

When propene reacts with bromine, the red-brown color of the bromine is lost and the product is a colorless liquid.

What is the median of the following set: 2, 4, 6, 8, and 10?

Answers

  • Final answer:

The median of the set of numbers 2, 4, 6, 8, and 10 is 6 because the median is the middle number in a sorted, ascending or descending, sequence of numbers.

Explanation:

In the field of statistics, the median is the middle value in a set of data that has been arranged in ascending order. If the total number of data values is odd, the median is the middle value. When the count of data values is even, the median is computed as the average of the two middle values. The given data set is 2, 4, 6, 8, 10. Since this is an odd set of numbers, we set the number in the middle as the median. Thus, the median value here is 6.

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Metals experience plastic deformation when _____.

Answers

Metals experience plastic deformation when a specific amount of pressure and temperature is applied to them. Most metals have low specific heat. Because of their low specific heat, they easily get hot when heat is applied to them.

A major function of your nose is cleaning the air you breathe.
True
False

Answers

Answer:

It's true I got it wrong.

Explanation:

An aqueous solution was prepared containing 1.0mol of AgNO3 and 1.0mol of FeSO4 in 1.00 dm^3. of water. When equilibrium was established, there was 0.44mol of Ag+(aq) in the mixture. Ag + (aq) + Fe2 + (aq) <==> Ag(s) + Fe3+ (aq) . What is the numerical value of Kc? . A 0.35 B 0.62 C 1.62 D 2.89

Answers

Kc = [Fe3+]/ ([Ag+] [Fe2+]) 
Initial concentrations [Ag+]= [Fe2+]= 1.0 mol/ dm^3 [Fe3+] =0.0 mol/dm^3 
change: Ag+: (1.0 - .44) mol/dm^3 = 0.56 mol/ dm^3 = change of Fe2+. Change of Fe3+ is 0.56 mol/dm^3. 
Equilibrium concentrations [Ag+] = [Fe2+] = 0.44 mol/dm^3 [Fe3+] = 0.56 mol/dm^3 

Kc = 0.56/0.44^2 dm^3/mol = 2.89 dm^3 /mol

Final answer:

The equilibrium constant Kc for the given reaction is calculated as [Fe3+]/[Ag+][ Fe2+] = 1.76, which is not among the provided answer choices.

Explanation:

To calculate the equilibrium constant, Kc, for the reaction Ag + (aq) + Fe2+ (aq) <==> Ag(s) + Fe3+ (aq), you need to know the concentrations of the ions at equilibrium. According to the question, the concentration of Ag+ is 0.44 mol/1.00 dm^3. Because AgNO3 completely dissociates into Ag+ and NO3- ions, the initial concentration of Fe2+ would also be 1.00 mol/dm^3. Given that the reaction has gone to completion, the concentration of Fe2+ at equilibrium would be 0.56 mol/dm^3 (1.00 - 0.44).

Furthermore, the reaction creates an equivalent amount of Fe3+, so its concentration at equilibrium would also be 0.44 mol/dm^3.  Therefore, the equilibrium constant, Kc, is calculated as [Fe3+]/[Ag+][ Fe2+] = (0.44)/(0.44 * 0.56) = 1.76. Looking at the answer choices given, none of them matches with the calculated value. So, the correct value might be an option not mentioned here.

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