Answer: N and O
Explanation:
An ionic bond is formed when a metal completely transfers its valence electron to a non metal.
Covalent bond is formed by sharing of electrons between two non metals.
A. N and O both are non metals and thus form a covalent bond.
B. K is a metal and Cl is a non metal and thus form an ionic bond.
C. Li is a metal and F is a non metal and thus form an ionic bond.
D. Na and Sr both are metals
decay rate is r= ln2/h. Radium-221 has a half-life of 30 seconds. How long will it take for 90% of a sample to decay = o-rt
C) Ba(ClO4)2. D) Ba(NO3)2
is insoluble in water.
Further Explanation:
Solubility rules
These help in predicting whether the given compound is soluble or insoluble in nature. Some of the solubility rules are as follows:
1. Group 1A compounds are soluble in nature.
2. All the common compounds of ammonium ion and all acetates, chlorides, nitrates, bromides, iodides, and perchlorates are soluble in nature. But the ions whose chlorides, bromides, and iodides are not soluble are , , and .
3. All common fluorides, except for and group 2A fluorides are soluble. Also, all sulfates except , , , and are soluble.
4. All common metal hydroxides except , , and hydroxides of group 1A and that of transition metals are insoluble in nature.
5. All carbonates are insoluble in nature, except for sodium, potassium and ammonium.
6. Salts having ions like , or are generally soluble except those of , and .
7. Group 1A and group 2A perchlorates are soluble in nature.
8. All sulfates of metals are soluble, except for lead, mercury (I), barium, and calcium sulfates.
9. The salts having nitrate ions are soluble in nature.
According to the solubility rules, only carbonates of sodium, potassium and ammonium are soluble in nature. So barium carbonate is insoluble in nature. But chlorides, nitrates and perchlorates of barium are soluble in water. Therefore option A is the correct answer.
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Answer details:
Grade: Senior School
Chapter: Chemical reaction and equation
Subject: Chemistry
Keywords: barium, water, insoluble, solubility rules, soluble, insoluble, water, BaCO3.
BaCO₃ is generally considered insoluble in water. Carbonates are often insoluble, except for some alkali metals and ammonium carbonates. Therefore, option A is correct.
The solubility of salt depends on its nature and the interactions between its ions and water molecules. In this case, determine the solubility of each salt by considering the common solubility rules.
BaCl₂ is soluble in water. Chlorides (Cl-) are mostly soluble except for a few exceptions, such as silver chloride, lead chloride, and mercury(I) chloride.
Ba(ClO₄)₂ is soluble in water. Perchlorates (ClO4-) are typically soluble.
Ba(NO₃)₂ is soluble in water. Nitrates (NO3-) are mostly soluble.
Based on the solubility rules, the salt that is insoluble in water is BaCO₃ (barium carbonate).
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The correct student is Student D, who says that Fluorine (F) has the highest ionization energy because the smaller the atom, the stronger the attraction between protons and valence electrons.
The stronger the attraction, the more energy is needed to remove a valence electron.
Ionization energy refers to the energy required to remove an electron from an atom. Smaller atoms have a stronger attraction between the positively charged protons in the nucleus and the negatively charged electrons in the outermost energy level. As a result, it takes more energy to remove an electron from a smaller atom like fluorine. This is because the electrons are held more tightly due to the stronger attraction.
So, the reasoning provided by Student D correctly explains why Fluorine has the highest ionization energy among Selenium (Se) and Fluorine (F).
Learn more about ionization energy from the link given below.
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I think the Answer is C because Flourine is stronger in electron attraction and is smaller so it has a stronger electronic pull. Hope this helps :)