PHYSICS HIGH SCHOOL

A research paper isA. creative, unstructured, first-person writing.
B. casual, third-person, entertaining writing.
C. thoughtful, analytical, academic writing.
D. bullet-pointed, technical, factual writing.

Answers

Answer 1
Answer: A research paper is considered to be the work that is a culmination of hundreds of hours of work put into one technical writeup which serves as the groundwork for what was done in that particular research. For that reason, the asnwer to your question would be C - thoughtful, analytical and academic writing.

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The control group in an experimental study will __________.

Answers

Answer:

receive no treatment during the experiment

Explanation:
Give you something to compare your results with. It's always nice to be able to see what changes have been made to the original, even if it's not technically the original (I know that was worded weird, I just don't know how else to explain it.) Hope this helped!

What does the process skill measuring mean?

Answers

Answer:

Process Skills: Observing - using your senses to gather information about an object or event. It is description of what was actually perceived. using standard measures or estimations to describe specific dimensions of an object or event

Explanation:

i hope this isnt confusing
This is the most basic skill in science. Observations are made by using the 5 senses. Good observations are essential in learning the other science process skills.

Examples:

The learner will be blind folded and make observations using the sense of touch.

The learner will create observations about a coin using the 5 senses.

The learner will mix primary colors to create more colors.

A 2.5 kg mass starts from rest at point A and moves along the x-axis subject to the potential energy shine in the figure below (a) Determine the speed (in m/s) of the mass at point B,C,D (For each answer, enter a number)

(b) Determine the turning point of the mass. (Select all that apply.)
Point A
Point B
Point C
Point D
Point E​

Answers

Final answer:

The speed at different points and the turning point of the mass can be determined using the principle of conservation of energy. However, concrete figures cannot be calculated without specified potential energy values or initial kinetic energy.

Explanation:

To compute the speed at points B, C, and D, we will use the principle of conservation of energy, which states that the total mechanical energy in a closed system—kinetic and potential energy—is conserved. In other words, energy cannot be created or destroyed, only transformed. Here, total energy = kinetic energy + potential energy. If the total mechanical energy decreases then that decrease in energy must go into another form of energy, such as heat from friction.

As for the turning point of the mass, it will occur when the kinetic energy is at a minimum, and the potential energy is at a maximum. This will happen when the velocity of the object is zero.

Without additional data points or numerical figures for instance the actual potential energy or initial kinetic energy, we cannot exactly compute the speed at points B, C, and D or determine the turning point of the mass.

Learn more about Conservation of Energy here:

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Final answer:

This question pertains to an exercise in physics, particularly related to the conservation of mechanical energy. The speed of the mass at different points can be calculated by considering changes in potential energy and applying the formula for kinetic energy. The turning point is when the mechanical energy equals the potential energy and the kinetic energy is zero.

Explanation:

The question is asking for the speed of a 2.5 kg mass at different points as it moves along the x-axis, as well as for the turning point of the mass. Without an illustration or explicit potential energy values, it's impossible to provide exact values. However, I can explain how to approach such a problem theoretically.

Firstly, the concept you need to apply here is the conservation of mechanical energy. This principle states that if there are no non-conservative forces doing work on the system, the total mechanical energy of the system (which is the sum of the kinetic and potential energy) remains constant.

To find the speed at different points, you'd need to know the potential energy at those points. The difference in potential energy between point A and any other point on the x-axis represents the change in kinetic energy (since the sum of potential and kinetic energy must remain constant if only conservative forces are acting). The speed at each point can be found using the formula for kinetic energy: KE = 1/2 * m * v^2.

Furthermore, the turning point of the mass will occur where the mechanical energy of the mass equals the potential energy of the system. This is because at the turning point, the mass stops momentarily before turning around, meaning its speed, and therefore its kinetic energy, will be zero. Therefore, the potential energy equals the total mechanical energy at the turning points.

Learn more about Conservation of Mechanical Energy here:

brainly.com/question/28928306

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Dirty windshields __________.a. reflect light into your eyes, causing glare
b. reflect light away from the vehicle, making the road appear dim
c. will not become fogged
d. none of the above

Answers

The answer : Dirty windshields reflect light into your eyes, causing glare.  Dirty glass reflects light, obscuring your view when sunlight or other bright light shines through it.  So, it is better to keep your windshield clean, both inside and out. 

Determine the conversion factor between (a) km/h and mi/h, (b) m/s and ft/s, and (c) km/h and m/s.

Answers

(a) km/h and mi/h,
1 km/hr (km hr-1) =  0.278 m/s (m s-1) = 0.621mi/hr (mi hr-1)  = 0.912 ft/s (ft s-1)
 (b) m/s and ft/s,
Speed of sound in air at 0 oC (32 oF)=  331 m/s  (m s-1) =  1090 ft/s (ft s-1)  =41 mi/hr (mi hr-1)
 (c) km/h and m/s. 1km/hr (km hr-1) =  0.278 m/s (m s-1) 

(a) 1 mi/h = 1.60934 km/h

(b) 1 ft/s = 0.3048 m/s

(c) 1 m/s = 3.6 km/h

Further explanation

Acceleration is rate of change of velocity.

\large {\boxed {a = (v - u)/(t) } }

\large {\boxed {d = (v + u)/(2)~t } }

a = acceleration ( m/s² )

v = final velocity ( m/s )

u = initial velocity ( m/s )

t = time taken ( s )

d = distance ( m )

Let us now tackle the problem !

1 ~ foot = 30.48 ~ cm

1 ~ inch = 2.54 ~ cm

1 ~ foot = 12 ~ inches

1 ~ mile = 1609.34 ~ metres

Question (a):

1 ~ mi/h = (1 ~ miles)/(1 ~ hour)

1 ~ mi/h = (1.60934 ~ km)/(1 ~ hour)

\large {\boxed {1 ~ mi/h = 1.60934 ~ km/h} }

Question (b):

1 ~ ft/s = (1 ~ foot)/(1 ~ s)

1 ~ ft/s = (0.3048 ~ m)/(1 ~ s)

\large {\boxed {1 ~ ft/s = 0.3048 ~ m/s} }

Question (c):

1 ~ m/s = (1 ~ m)/(1 ~ s)

1 ~ m/s = (1/1000 ~ km)/(1/3600 ~ h)

1 ~ m/s = (3600)/(1000) ~ km/h

\large {\boxed {1 ~ m/s = 3.6 ~ km/h} }

Learn more

Answer details

Grade: High School

Subject: Physics

Chapter: Kinematics

Keywords: Velocity , Driver , Car , Deceleration , Acceleration , Obstacle , Speed , Time , Rate

Practical examples of radition​

Answers

Basically anything thats hot like the sun,microwave,fire,ect.
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