Suppose the population of a town is 15,200 and is growing 2% each year. Write an equation to model the population growth. Predict the population after 10 years
Answer:
The equation model is P = Po * e^rt
The population after 10 years = 18, 559 (most approximately)
Step-by-step explanation:
We use formula to find the population growth.
P = Po * e^rt
Where P is the total population after t years
Po is the initial population
r = rate of growth
t = time
e = 2.71 [Euler number]
The equation model is P = Po * e^rt
Now to find the population after 10 years, we have to plug in the given values in the formula.
Given:
Po = 15, 200, r = 2% = 2/100 = 0.02, and t = 10 years
P = 15,200*e^0.02(10)
P = 15,200*2.71^0.2
P = 15,200 *1.221
P = 18, 559
Therefore, the population after 10 years = 18, 559 (most approximately)
Answer: 10 minutes.
Step-by-step explanation: Since the cells get double in every 5 minutes, so the number of bottles that will be filled in 5 minutes= 2. After another 5 minutes, these 2 bottles of cells will fill another two bottles. Now, out of these 4 bottles, one is old which was already filled with cells. So, no. of new bottles filled=3 in 10 minutes.
So, it will take 10 minutes to fill another 3 bottles of the same size.
The answer is 10 minutes
(1/2, 1)
(0, 1)
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Answer:
(1/2,1) is on the graph of
B is correct.
Step-by-step explanation:
Given:
We are given a log function whose base 1/2.
Log property:
If base and mantissa is same then their value is 1
We need to choose correct point from the options.
Option 1: (1,1/2)
False
Option 2: (1/2,1)
True
Option 3:
Log is not defined for x=0.
Hence, (1/2,1) is on the graph of
(1/2,1) is the points is on the graph of y = log1/2x?
For (1, 1/2):
So, By Substituting x = 1 and y = 1/2 into the equation, we get:
1/2 = log₁/₂(1)
Since log of 1 to any base is always 0, the equation becomes:
1/2 is not equal to 1
In terms of Option 3: Log is not defined for x=0.
Therefore , (1/2,1) is on the graph of y = log1/2x?
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