What are the main agents of change in the rock cycle?

HELP PLEASE.

Answer:

1- waxing gibbous

2- third quarter

3- waxing crescent

4- full moon

5- waning crescent

6- new moon

7- first quarter

8- waning gibbous

Explanation:

hope that helps

Answer:

Explanation:

a )

4Na(s) + O₂(g) - - 2Na₂O(s)

4 x 23g    32g           2x62

92 g of Na produces 124 g of Na₂O(s)

57.5 g of Na produces (124 / 92) x 57.5

= 77.5 g of Na₂O(s)

b )

92 g of Na requires 32 g of O₂

18 g of Na requires ( 32 / 92 ) x 18

= 6.26 g of O₂

c )

128 g of Na₂O(s) requires 32 g of O₂

75 g of Na₂O(s) requires ( 32 / 128 ) x 75

= 18.75 g of O₂

Answer:

Explanation:

The formula of water is H₂O.

1. Calculate the molar mass of water

2 H = 2 × 1.008 =   2.016 u

1 O = 1 × 16.00  = 16.00   u

                  MM = 18.02    u

2. Mass of hydrogen

\text{Mass of H} = \text{92.0 g water} \times \dfrac{\text{2.016 g H}}{\text{18.02 g water }} = \textbf{10.29 g H}

3. Mass of 0xygen

Final answer:

A 92 gram sample of water will consist of approximately 10.22 grams of hydrogen and 81.78 grams of oxygen.

Explanation:

Water

consists of two hydrogen atoms and one oxygen atom. Therefore, it has a

molecular formula of H2O

. To find the mass of each element in a 92 gram sample, we need to know the molar mass of the elements and the compound. The molar mass of hydrogen (H) is about 1 gram per mole, and oxygen (O) has a molar mass of 16 grams per mole. So, the molar mass of water (H2O) is approximately 18 grams per mole (2*1 + 16). This means that in one mole of water, 2 grams are hydrogen and 16 grams are oxygen. If we scale this up to 92 grams, we find that there are approximately 10.22 grams of hydrogen and 81.78 grams of oxygen.

Learn more about Molar Mass here:

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Answer:

The list of answer choices is wrong.

The correct list is:

A) The element is most likely from Group 1A or 2A and in period 1 or 2.

B) The element is most likely from Group 2A or 3A and in period 6 or 7.

C) The element is most likely from Group 4A or 5A and in period 4 or 5.

D) The element is most likely from Group 6A or 7A and in period 2 or 3.

The correct answer is:

• Option D) The element is most likely from Group 6A or 7A and in period 2 or 3.

Explanation:

The ionization energy increases from left to right on the periodic table. So the elements with higer ionization energies are in the right end of the table. The right most columns are 6A (16) and 7A(17). The column 8A (18) which is that of the noble gases is not normally taken into acccount for this predictions because noble gases are nearly inert.

Hence, the fact that the statement indicates high ionization energy suggests that the element is most likely from group 6A or 7A.

The atomic radius increases from top to bottom, so the smallest elements are in the top rows, which is the periods 1, 2, or 3. The period 1 only has two elements, hydrogen in group 1 and helium in group 8A, so they are not considered in the choices. Thus, that leaves you with the periods 2 or 3.

Adding the two considerations, the conclusion is that the element is most likely from group 6A or 7A and in period 2 or 3.

Answer:

Explanation:

The answer is A) The element is most likely from Group 1A or 2A and in period 1 or 2

Answer:

In materials of molecular structure, the nature of intermolecular and intramolecular bonds has a decisive influence on their characteristics and properties. Characteristics such as melting and boiling points, mechanical strength and hardness depend on the type of such bonds.