Fireworks exploding in the sky and giving off light are an example of a(n) _____. a. exothermic change
b. change in mass
c. physical change
d. endothermic change

Answers

Answer 1
Answer: Exothermic change. Because the firework when it exploded, released energy in the form of light. In exothermic changes energy is released, and in endothermic changes energy is absorbed.

- This wouldn't be a physical change, but instead a chemical change. A clue that it is a chemical change is that energy was given off.
Answer 2
Answer:

the answer is A exothermic change




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a. Atomic #= 3 b. Mass #=7 c. # of Protons = d. # of Neutrons = e. # of Electrons = E in Ist energy level = E in 2nd energy level = E in 3rd energy level = 0 # of Valence E = Li​

Answers

I hope you can understand my writing :)

Consider the equation: S + 3O2 and SO3. Is this equation balanced? why or why not​

Answers

The equation is not balanced because the number of atoms of Oxygen present in the reactants and product sides are not equal

The equation being referred to in the question can be written properly as

S + 3O₂ → SO₃

To determine whether the equation is balanced or not

We will check if the coefficient in the equation gives equal numbers of atoms for each element in the reactants and product

  • For the reactants side

S = 1

O = 6

  • For the product side

S = 1

O = 3

We can observe that, the coefficient does not give equal number of atoms for the element, Oxygen (O), in the reactants and product sides

∴ The equation is NOT balanced

Hence, the equation is not balanced because the number of atoms of Oxygen present in the reactants and product sides are not equal

Learn more here: brainly.com/question/24943155

Answer:

This equation is not balanced because you don't have the same amount of each element on each side of the chemical reaction. The balanced equation is:

2 S + 3 O_(2) ⇒ 2 SO_(3)

Explanation:

The law of conservation of matter states that since no atom can be created or destroyed in a chemical reaction, the number of atoms that are present in the reagents has to be equal to the number of atoms present in the products.

Then, you must balance the chemical equation. For that, you must first look at the subscripts next to each atom to find the number of atoms in the equation. If the same atom appears in more than one molecule, you must add its amounts.  

The coefficients located in front of each molecule indicate the amount of each molecule for the reaction. This coefficient can be modified to balance the equation, just as you should never alter the subscripts.

By multiplying the coefficient mentioned by the subscript, you get the amount of each element present in the reaction.

Then, taking into account all of the above, you can determine the amount of elements on each side of the equation:

Left side: 1 sulfur S and 6 oxygen O (coefficient 3 multiplied by sub-index 2)

Right side: 1 sulfur S and 3 oxygen O (subindice value)

As you can see, you have the same amount of sulfur on both sides of the equation but the amount of oxygen is different. This indicates that the chemical equation is not balanced. To balance it, as the amount of sulfur is the same, the amount of oxygen must be balanced, which is different on each side of the reaction.

A simple way is to balance the equation is to multiply the product by 2, that is, add a coefficient 2 in front of the SO3 molecule, the reaction being as follows:

S + 3 O_(2) ⇒ 2 SO_(3)

Now the amount of elements on each side of the equation is:

Left side: 1 sulfur S and 6 oxygen O (coefficient 3 multiplied by subindice 2)

Right side: 2 sulfur S and 6 oxygen O (coefficient 2 multiplied by subindice 3)

The oxygen is now balanced, but the amount of sulfur on both sides of the reaction varies. To balance the quantities of sulfur, as now on the right side you have an amount of 2, you can add the coefficient to sulfur. The chemical equation is as follows:

2 S + 3 O_(2) ⇒ 2 SO_(3)

Now the amount of elements on each side of the equation is:

Left side: 2 sulfur S and 6 oxygen O (coefficient 3 multiplied by subindice 2)

Right side: 2 sulfur S and 6 oxygen O (coefficient 2 multiplied by subindice 3)

Finally you have the same amount of sulfur and oxygen on both sides of the reaction. So the chemical equation is finally balanced.

Physical and chemical properties

what is density when mass is 5.2 and volume is 0.117

Answers

Density = mass / volume

D = 5.2 / 0.117

D = 44.44

Hydrogen does not occur in free state on the earth. Why?​

Answers

Answer:

ExplanatioHydrogen cannot exist in free state as hydrogen needs an electron to attain stability. If an element does not attain stability it cannot exist on its own. In Sun there are large number hydrogen atoms and helium atoms present this creates a lot of energy and nuclear fusions are occured. Gases that attain stability can normally exist on their own. E.g. Argon, Neon, Helium, Krypton and Xenon. Gases that cannot exist on their own are:

H2

O2

N2

Hope it helped a little......

Please select the word from the list that best fits the definition Occurs when all forces acting on an object cancel out, and there is no movement

Answers

It's balanced force. When two or more forces are exerted on an object, and their effects cancel one another out, and no movement occurs, it has a net force of 0. When an object has a net force of 0, it has balanced force.

Explanation:

When two or more forces act in opposite directions and are equal then the object does not move as the forces cancel out each other.

This type of force is known as balanced force. Balanced force does not cause change in motion.

Thus, we can conclude that balanced force occurs when all forces acting on an object cancel out, and there is no movement.

Which of the following is true about mixtures?A) Mixtures consist of two or more substances chemically combined.
B) Mixtures cannot be separated by physical means.
C) Mixtures consist of only one kind of atom.
D) Mixtures have to or more substances mixed together, but are not chemically combined.

Answers

The correct answer is D. Mixtures can be easily separated solutions cannot.