Write an equation of the line that is:a) parallel to the line y=4x+1, and that passes through point (2,3)
b) parallel to the line 2y-6x=9, and that passes through point (-2,1)
c) parallel to the line y=4x+3, and that has the same y-intercept as the line y=5x-3
d) parallel to the line -1/2x, and that has the same y-intercept as the line 2y=7x+6
e) perpendiclar to the line 2y-4x=8, and that passes through point (6,-6)
f) perpendicular to the line 2y-5x=15, and has an x-intercept of 3

please help me with all the questions it would mean alot

Answers

Answer 1

Answer: $a)\ny=4x+1\na=4\nnew\ y=bx+c\nif\ parallel a=b\ny=4x+c\nsubstituting\point\ (2,3)\n3=4*2+c\nc=-5\ny=4x-5\nb)\n2y-6x=9\n2y=6x+9\ny=3x+4,5\na=3\nnew\ y=bx+c\nif\ parallel a=b\ny=3x+c\nsubstituting\ point\ (-2,1)\n1=4*(-2)+c\nc=9\ny=3x+9\n c)\ny=4x+3\na=4\nnew\ y=bx+c\nif\ parallel a=b\ny=4x+c\nc=-3\ny=4x-3\ne)\n2y-4x=8\n2y=4x+8\ny=2x+4\na= 2 \nnew\y=bx+c\nif\ perpendicular b=-1/a\ny=- (1)/(2) x+c\npoint(6,-6)\n-6=-1/2*6+c\nc=-3\ny=-1/2x-3\nf)\n2y-5x=15\n2y=5x+15\ny=(5)/(2)x+(15)/(2)$

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Answers

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Answers

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Answers

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