Simplify the expressiona)square root of 45
b)square root of 54
c)square root of 16/25

Answers

Answer 1

Answer: $a)\n\n \sqrt {45}=√(9\cdot 5)=√(9)\cdot √(5)=3√(5)\n\nb)\n\n √(54)=√(9\cdot 6)=√(9)\cdot √(6)=3√(6)\n\nc)\n\n\sqrt{(16)/(25 ) }=(√(16))/(√(25))=(4)/(5)$

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An account earns simple interest. $1800 at 6.5% for 30 months find the interest earne. find the balance of the account.

Answers

Interest earned: $292.50
Balance: $2092.50

How many cups of sugar is needed for 5 gallons

Answers

Try doing 16 times 5. Since there are 16 US customary cups in a gallon.

Mr. Griffin wants to help his students maintain complete concentration throughout their long calculus exam. To achieve this goal, he should structure the first few questions to: A) Gradually increase in difficulty. B) Cover a wide range of topics. C) Be concise and to the point. D) Include interesting real-life applications.

Answers

Answer:

A. Gradually increase in difficulty

Step-by-step explanation:

Option A is the most effective choice because structuring the first few questions of a long calculus exam to gradually increase in difficulty can help students ease into the exam, build confidence, and maintain their concentration. Starting with easier questions allows students to warm up and gain momentum, which can reduce anxiety and increase their focus. This approach aligns with best practices in assessment and educational psychology, as it promotes a smoother transition into more challenging material, ultimately supporting better concentration and performance throughout the exam.

Final answer:

To maintain student concentration during a long exam, the first few questions should gradually increase in difficulty. This approach builds student confidence and eases them into the problem-solving process, potentially reducing test anxiety and encouraging perseverance through harder problems.

Explanation:

To help his students maintain complete concentration throughout their long calculus exam, Mr. Griffin should structure the first few questions to be gradually increase in difficulty. This approach helps students to gain confidence as they successfully solve the initial questions which is likely to carry them through the rest of the exam and maintain their concentration.

Beginning with easier questions allows the students to 'warm up' and transition their mind into the calculus mode. Then, as the questions become increasingly difficult, students are better prepared to tackle them because they've eased into the problem-solving process instead of being hit with the most challenging problems right off the bat. This approach can reduce test anxiety and encourage perseverance through the more difficult problems towards the end of the test.

Learn more about Gradual Increase in Difficulty here:

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Find the upper quartile of this data set: 593, 588, 540, 434, 420, 398, 390, 375A. 427

B. 394

C. 420

D. 564

Answers

The answer is D. 564
When you put all the numbers in order from least to greatest and find the median which is between 420 and 434, you can then find your upper quartile which would be between 540 and 588 making it D

Answer:

564.

Step-by-step explanation:

What is the area of the trapezoid?

Answers

I hope this helps you

How do I go about solving (27x^3/8y^9)^5/3? And what is the role of the numerator and denominator?

Answers

$\left( (27x^3)/(8y^9)\right)^ (5)/(3) \n\n\n =\left( ((3x)^3)/((2y^3)^3)\right)^ (5)/(3) \n\n\n = \frac{(3x)^{3 * (5)/(3) }}{(2y^3)^{3 * (5)/(3) }} \n\n\n =((3x)^5)/((2y^3)^(5 )) \n\n\n =(243x^5)/(32y^(15))$

Now, If the exponent was negative like you asked....

$\left( (27x^3)/(8y^9)\right)^ {-(5)/(3)} \n\n\n =\left( (8y^9)/(27x^3)\right)^ {(5)/(3)}\n\n\n =\left( ((2y^3)^3)/((3x)^3)\right)^ (5)/(3) \n\n\n = \frac{(2y^3)^{3 * (5)/(3) }}{(3x)^{3 * (5)/(3) }} \n\n\n =((2y^3)^(5 ))/((3x)^5) \n\n\n =(32y^(15))/(243x^5)$

Other Questions

Knowing the points A(−5, 2), B(3, 4), C(−4, −3), and D(4, −1), and that segment AB parallel to segment CD, what is the length of segment AB and segment CD, and do points A, B, C, and D form a parallelogram?A) AB=8 and CD=8; therefore, ABCD is a parallelogram B) AB=2sqrt17 and CD=2sqrt17; therefore, ABCD is a paralleogram C) AB=4sqrt5 and CD=4sqrt5; therefore, ABCD is a parallelogram D) AB = 2sqrt17 and CD=4sqrt5; therefore, ABCD is a parallelogram

Bob climbed down a ladder from his roof, while roy climbed up another ladder next to him. Each ladder had 30 rungs. Bob went down 2 rungs every second. Roy went up 1 rung every second. A- let statementB- system of equationsC-At some points , Bob and Roy were at the same height. which rung were they on ?

If g(x) is the inverse of f(x)=4x+12 and f(x)=, what is g(x)

A six-foot person walks from the base of a broadcasting tower directly toward the tip of the shadow cast by the tower. When the person is 124 feet from the tower and 3 feet from the tip of the shadow, the person's shadow starts to appear beyond the tower's shadow. (a) Draw a right triangle that gives a visual representation of the problem. Label the known quantities of the triangle and use a variable to represent the height of the tower.