Determine the equation of a circle having a diameter with endpoints at (12,-14) and (2,4)
Answers
Answer 1
Answer:
%20%5C%20and%20%5C%20radius%20%5C%20%22r%22%20%5C%20is%20%3A%20%5C%5C%20%5C%5C(x-a)%5E2%2B(y-b)%5E2%3Dr%5E2)
%20%2C%20%5C%20%5C%20%5C%20(2%2C4)%5C%5CSince%20%5C%20the%20%5C%20center%20%5C%20of%20%5C%20the%20%5C%20circle%20%5C%20is%20%5C%20the%20%5C%20midpoint%20%5C%20of%20%5C%20the%20%5C%20line%20%5C%20segment%20%5C%5C%20connecting%20%5C%20two%20%5C%20endpoints%20%5C%20of%20%5C%20a%20%5C%20diameter%20%5C%5C%5C%5CMidpoint%20%5C%20Formula%20%5C%5C%5C%5C(a%2Cb)%3D(%5Cfrac%7Bx_%7B1%7D%2Bx_%7B2%7D%7D%7B2%7D%2C%5Cfrac%7By_%7B1%7D%2By_%7B2%7D%7D%7B2%7D)%3D(%5Cfrac%7B12%2B2%7D%7B2%7D%2C%5Cfrac%7B-14%2B4%7D%7B2%7D)%3D(%5Cfrac%7B14%7D%7B2%7D%2C%5Cfrac%7B-10%7D%7B2%7D)%3D(7%2C-5))
%20%5C%20to%20%5C%20(12%2C%20-14)%20%5C%20is%3A%20%5C%5C%20%5C%5C%20r%3D%20%5Csqrt%7B(x_%7B2%7D-x_%7B1%7D)%5E2%20%2B(y_%7B2%7D-y_%7B1%7D)%5E2%7D%5C%5C%5C%5Cr%3D%20%5Csqrt%7B(12-7)%5E2%20%2B(-14%2B5)%5E2%7D%3D%5Csqrt%7B5%5E2%2B(-9)%5E2%7D%3D%5Csqrt%7B25%2B81%7D%3D%5Csqrt%7B106%7D%5C%5C%5C%5C(x-7)%5E2%2B(y-(-5))%5E2%3D%20(%5Csqrt%7B106%7D)%5E2%20%5C%5C%20%5C%5C(x-7)%5E2%2B(y%2B5)%5E2%3D106)
Related Questions
What is true concerning the lines graphed by the system of equations shown below 8x+6=2y 12x-3=3y
Help please! answer correctly for brainliest . ( look at picture for problem )
I needs it the question asap
Round 44.8 to the nearest whole number
Which of the following functions has the largest value when x = 3?c(x) = 3x2 + 5x + 22j(x) = 12xa(x) = 9xAll the functions are equal at x = 3.c(x)j(x)a(x)
Help please! answer correctly for brainliest . ( look at picture for problem )
I needs it the question asap
Round 44.8 to the nearest whole number
Which of the following functions has the largest value when x = 3?c(x) = 3x2 + 5x + 22j(x) = 12xa(x) = 9xAll the functions are equal at x = 3.c(x)j(x)a(x)
Answers
with a parabola that faces left or right it is
(y-k)²=4p(x-h)
p is distance from directix to vertex which is also the distance from vertex to focus
if it opens to the right, then p is positive
if it opens to the left, then p is negative
so we know that directix is-8 and focus is (8,0)
directix is behind the parabola
so therfor the parabola opens to the right
distance from x=-8 to (8,0) is 16 units
16/2=8
p=8
vertex is 8 units to right of directix or 8 units to the left of focus
(8,0) is focus so vertex is (0,0)
(h,k) is vertex
(y-k)²=4p(x-h)
(y-0)²=4(16)(x-0)
y²=64x
(y-k)²=4p(x-h)
p is distance from directix to vertex which is also the distance from vertex to focus
if it opens to the right, then p is positive
if it opens to the left, then p is negative
so we know that directix is-8 and focus is (8,0)
directix is behind the parabola
so therfor the parabola opens to the right
distance from x=-8 to (8,0) is 16 units
16/2=8
p=8
vertex is 8 units to right of directix or 8 units to the left of focus
(8,0) is focus so vertex is (0,0)
(h,k) is vertex
(y-k)²=4p(x-h)
(y-0)²=4(16)(x-0)
y²=64x
Answer:
If your on e2020, its C
Step-by-step explanation:
y^2=32x, the work above is correct but they forgot to take the square away in the final answer. hope this helps!
Answers
Answer:
1:2
Step-by-step explanation:
1:2 I believe, maybe 1/2 or 1 and 2.
x/5+ 1 = 7
Answers
Subtract 1 from each side and you get:
x/5 = 6
now multiply by 5:
x = 30
x/5 = 6
now multiply by 5:
x = 30
Answers
Try to relax. Your desperation has surely progressed to the point where
you're unable to think clearly, and to agonize over it any further would only
cause you more pain and frustration.
I've never seen this kind of problem before. But I arrived here in a calm state,
having just finished my dinner and spent a few minutes rubbing my dogs, and
I believe I've been able to crack the case.
Consider this: (2)^a negative power = (1/2)^the same power but positive.
So:
Whatever power (2) must be raised to, in order to reach some number 'N',
the same number 'N' can be reached by raising (1/2) to the same power
but negative.
What I just said in that paragraph was: log₂ of(N) = - log(base 1/2) of (N) .
I think that's the big breakthrough here.
The rest is just turning the crank.
Now let's look at the problem:
log₂(x-1) + log(base 1/2) (x-2) = log₂(x)
Subtract log₂(x) from each side:
log₂(x-1) - log₂(x) + log(base 1/2) (x-2) = 0
Subtract log(base 1/2) (x-2) from each side:
log₂(x-1) - log₂(x) = - log(base 1/2) (x-2) Notice the negative on the right.
The left side is the same as log₂[ (x-1)/x ]
==> The right side is the same as +log₂(x-2)
Now you have: log₂[ (x-1)/x ] = +log₂(x-2)
And that ugly [ log to the base of 1/2 ] is gone.
Take the antilog of each side:
(x-1)/x = x-2
Multiply each side by 'x' : x - 1 = x² - 2x
Subtract (x-1) from each side:
x² - 2x - (x-1) = 0
x² - 3x + 1 = 0
Using the quadratic equation, the solutions to that are
x = 2.618
and
x = 0.382 .
I think you have to say that x=2.618 is the solution to the original
log problem, and 0.382 has to be discarded, because there's an
(x-2) in the original problem, and (0.382 - 2) is negative, and
there's no such thing as the log of a negative number.
There,now. Doesn't that feel better.
you're unable to think clearly, and to agonize over it any further would only
cause you more pain and frustration.
I've never seen this kind of problem before. But I arrived here in a calm state,
having just finished my dinner and spent a few minutes rubbing my dogs, and
I believe I've been able to crack the case.
Consider this: (2)^a negative power = (1/2)^the same power but positive.
So:
Whatever power (2) must be raised to, in order to reach some number 'N',
the same number 'N' can be reached by raising (1/2) to the same power
but negative.
What I just said in that paragraph was: log₂ of(N) = - log(base 1/2) of (N) .
I think that's the big breakthrough here.
The rest is just turning the crank.
Now let's look at the problem:
log₂(x-1) + log(base 1/2) (x-2) = log₂(x)
Subtract log₂(x) from each side:
log₂(x-1) - log₂(x) + log(base 1/2) (x-2) = 0
Subtract log(base 1/2) (x-2) from each side:
log₂(x-1) - log₂(x) = - log(base 1/2) (x-2) Notice the negative on the right.
The left side is the same as log₂[ (x-1)/x ]
==> The right side is the same as +log₂(x-2)
Now you have: log₂[ (x-1)/x ] = +log₂(x-2)
And that ugly [ log to the base of 1/2 ] is gone.
Take the antilog of each side:
(x-1)/x = x-2
Multiply each side by 'x' : x - 1 = x² - 2x
Subtract (x-1) from each side:
x² - 2x - (x-1) = 0
x² - 3x + 1 = 0
Using the quadratic equation, the solutions to that are
x = 2.618
and
x = 0.382 .
I think you have to say that x=2.618 is the solution to the original
log problem, and 0.382 has to be discarded, because there's an
(x-2) in the original problem, and (0.382 - 2) is negative, and
there's no such thing as the log of a negative number.
There,now. Doesn't that feel better.
25%
33.3%
75%
Answers
Given:
36,000 season ticket holders (base number)
9,000 increase in season ticket holders.
9,000 / 36,000 = 0.25
0.25 * 100% = 25%
The percentage change is an increase of 25%.
36,000 + 9,000 = 45,000 new number of season ticket holders.
36,000 season ticket holders (base number)
9,000 increase in season ticket holders.
9,000 / 36,000 = 0.25
0.25 * 100% = 25%
The percentage change is an increase of 25%.
36,000 + 9,000 = 45,000 new number of season ticket holders.
688÷7=
Answers
okay so if your dividing long division this is how you do it first you would divide 7 into 68 since it can't divide into just 6, and 7 divides into 68, 9 times so you would put 9 on top, and 9 x 7 is 63, so 68 minus 63 is 5 then you would carry down the eight which would make the next number 58 and 7 divides into 58, 8 times, and 7 x 8 is 56, and 58 minus 56 is 2 so the 2 qoes down and the remainder is 2 but if you need multiple remainders the you need to keep on dividing so you need to put a 0 at the end of 688 and you can do this because 688 is the same as 688.0 its the same so you just keep on dividing so you bring the 0 down and that makes 20, 7 goes into 20 2 times so now you would put a .2 on top and 2 x 7 is 14 so 14 goes under the 20 and 20 minus 14 is 6 then you need more than one remainder you just keep going so you add another 0 at the end, so it should look like this 688.00 now and you drop the 0 and that makes the 6 a 60 and 7 goes into 60, 8 times so put a 8 on top and 8 x 7 is 56 and 60 minus 56 is 4 so your answer would be 98.28 but you can keep going this is what i have gotten so far 98.285714, also this is a problem where you aren't going to get an answer where you don't have a remainder
also the numbers .285714 all keep on repeating forever and there's a mathematical sign that you put over decimals like that (that just keep on repeating themselves) but i forgot what its called i know this is long but i hope it helped you:)
also the numbers .285714 all keep on repeating forever and there's a mathematical sign that you put over decimals like that (that just keep on repeating themselves) but i forgot what its called i know this is long but i hope it helped you:)
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