If f(x)=2x-9, find f(p) and f(x+h)

Answers

Answer 1

Answer: $f(x)=2x-9\n\nf(p)\to substitute\ x=p\n\nf(p)=2p-9\n\nf(x+h)\to substitute\ x=x+h\n\nf(x+h)=2(x+h)-9=2x+2h-9$

Answer 2

Answer: $f(p)=2p-9\n f(x+h)=2(x+h)-9=2x+2h-9$

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What is the exact value of x in the exponential equation 2^8x − 3 = 7?x = log4/8log2
x = 1/8log2
x= 5/8
x =log5/8

Answers

Hello,

2^(8x)-3=7
==>2^(8x)=10
==>8x log (2)=log(10)
==>8x log(2)=1

==>x=1/(8*log(2))
With parenthesis on the denominator, the answer is B.

10 x 4 ones = how many ones

Answers

The product will be 40 I believe?

What is 5-(n-4)=3(n+2)?

Answers

Answer:

-3n-6

Step-by-step explanation:

multiply each term by 3

-3(n+2)

-3n-3*2

-3n-6

What is (4x-2)*6(2x+7) in quadratic expression

Answers

48x^2+144x-84 is your answer :)

Which three-dimensional figures have lateral faces that are polygons? Check all that apply

Answers

Question:

Which three-dimensional figures have lateral faces that are polygons? check all that apply.

- cones

- cylinders

- hemispheres

- prisms

- pyramids

- spheres

Answer:

The correct choices are;

- prisms and

- pyramids

Step-by-step explanation:

A polygon is a figure closed or bounded with several straight line segments and polygons are named based on how many sides, side size and sizes of angles that they have present.

A three sided polygon for example is called a triangle

A lateral face are the faces of a prism except the base

Based on the definitions, we note that out of the options, only prisms, and pyramids have lateral faces that are made up entirely of straight line segments, hence polygons. Therefore, the correct choices are prisms and pyramids.

Answer:

Actually the correct is Cylinders, Prisms, and Pyramids. I just did it

Step-by-step explanation:

What is the cross section created when a vertical slice is made perpendicular to the 2 bases of a triangular prism?A.
a triangle

B.
ellipse trapezoid

C.
a square

D.
a rectangle

Answers

Imagine slicing a triangular prism, perpendicular to the two bases.
You would basically just be lopping off some congruent triangle from each base.
The now-exposed inside of the prism would be a rectangle.

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