Find the equation of the line that passes through the point (7,5) and is perpendicular to the line 2x - 3y=6

Answers

Answer 1

Answer: $(7,5);\ \ \ \ 2x - 3y=6 \ \ / subtract \ 2x \ from \ each \ side \n \n-3y = -2x + 6\ \ / divide \ each \term \ by \ (-3) \n \n y = \frac{2} {3}x -2\n \n The \ slope \ is :m _(1) = ( 2)/(3) \n \n If \ m_(1) \ and \ m _(2) \ are \ the \ gradients \ of \ two \ perpendicular \n \n lines \ we \ have \n\n\ m _(1)*m _(2) = -1$

$(2)/(3)\cdot m_(2)=-1\ \ / \cdot ((3)/(2))\n\nm_(2)=-(3)/(2)\n\nNow \ your \ equation \ of \ line \ passing \ through \ (7,5) would \ be: \n \n y=m_(2)x+b \n \n5=-(3)/(2)\cdot 7 + b \n \n 5= -(21)/(2)+b\n \nb=5+(21)/(2) \n \nb= (10)/(2)+(21)/(2)\n \nb= (31)/(2)\n\nb=15.5 \n \n y = -(3)/(2)x +15.5$

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Can someone please help me and look over this and answer this?I have a huge E.A and this make up my whole grade please help.

Answers

1. $(Species\ A)/(Species\ B) = ((3x^(2)y)^(2))/(6(xy)^(3)) = (3x^(4)y^(2))/(6x^(3)y^(3)) = (x)/(2y)$

2. $(Species\ C)/(Species\ D) = \frac{20√(xy)}{4\sqrt{x^(2)y}} = (5)/(√(x)) = (5)/(√(x)) * (√(x))/(√(x)) = \frac{5√(x)}{\sqrt{x^(2)}} = (5√(x))/(x)$

What is the square root of 300 rounded to the nearest tenth?

Answers

$17 < √(300) < 18\ becouse\ 17^2=289 < 300 < 324=18^2$

$17.3^2= 299.29 < 300\n\n17.4^2=302.76 > 300$

$17.3 < √(300) < 17.4$

$√(300)\ \text{is closer to 17.3. Therefore}\ √(300)\approx17.3$

Given AD || GJ. Refer to the figure and provide an appropriate name for BCF and GHF.A. alternate interior angles
B. same-side interior angles
C. corresponding angles
D. alternate exterior angles

Answers

Answer:

C. Corresponding angles

Step-by-step explanation:

Corresponding angles are angles formed by a transversal on the same side of the transversal and on the same side of each parallel lines.

Yoko paid $10.70 for stamps. She bought three times as many 25 cent stamps as 14 cent stamps, twice as many 2 cent stamps
as 25 cent stamps and the same number of one-cent stamps as
2 cent stamps. How many stamps of each type did Yoko buy?

Answers

Answer:

30 of 25 cent, 10 of 14 cent, 60 of 2 cent

Step-by-step explanation:

Note: it must be typo 10.70, changed to 10.10

Number of 25 cent stamps = x

Number of 14 cent stamps = y

Number of 2 sent stamps = z

Total = $10.10 = 1010 ¢
x = 3y
z = 2x ⇒ z = 6y

Solving equation

25x + 14y + 2z = 1010
25(3y) + 14y + 12y = 1010
75y + 26y = 1010
101y = 1010
y = 1010/101
y = 10

The finding x and z

x = 3*10 = 30
z = 6*10 = 60

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Which equation shows the substitution method being used to solve the system of linear equations? x – y = 7

x = y + 3

A) x = (7 – x) + 3

B) x – (y + 3) = 7

C) (y + 3) – y = 7

D) x – y = y + 3

Answers

I think it is answer C
Hope I helped

Find Each Product Simplify
( x ^ 2 + 9 ) ( x + 3 ) ( x - 3)HELP ME PLEASE!

Answers

(x^2+9)(x+3)(x-3)=(x^2+9)(x^2-9)=x^4-81
Have a nice day!!! ^^

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