MATHEMATICS HIGH SCHOOL

A physical fitness association is including the mile run in its secondary- school fitness test. The time for this event for boys in secondary school is known to possess a normal distribution with a mean of 440 seconds and a standard deviation of 50 seconds. Find the probability that a randomly selected boy in secondary school can run the mile in less than 325 seconds.

Answers

Answer 1

Answer:

Answer:

0.0107 is the probability that a randomly selected boy in secondary school can run the mile in less than 325 seconds.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 440 seconds

Standard Deviation, σ = 50 seconds

We are given that the distribution of time is a bell shaped distribution that is a normal distribution.

Formula:

$z_(score) = \displaystyle(x-\mu)/(\sigma)$

P(run the mile in less than 325 seconds)

P(x < 325)

$P( x < 325) = P( z < \displaystyle(325 - 440)/(50)) = P(z < -2.3)$

Calculation the value from standard normal z table, we have,

$P(x < 325) = 0.0107 = 1.07\%$

0.0107 is the probability that a randomly selected boy in secondary school can run the mile in less than 325 seconds.

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.51 as a fraction in simplest form

Answers

51/100

Not sure if correct but I think you mean this as it could also be 51% but you can't simplify 51/100 any lower.

.51 = 0.51 = 51/100 and it is not divisible.

For the functions f(x) = 2x − 6 and g(x) = 5x + 1, which composition produces the greatest output? A. Both compositions produce the same output B. Neither composition produces an output. C. f(g(x)) produces the greatest output. D. g(f(x)) produces the greatest output.

Answers

f(g(x)) = 2(5x+1)-6 = 10x+2-6 = 10x-4

g(f(x)) = 5(2x-6)+1 = 10x-30+1 = 10-29

10x-4>10-29 because from f(g(x)) you subtract less quantity.
The answer to your question is C. I hope that this is the answer that you were looking for and it has helped you.

Answer:

-24

Step-by-step explanation:

Need help in this question please show work along with answer

Answers

      (x² - y²)² + (2xy)² = (x² + y²)²
   (x² - y²)(x² - y²) + 2x²y² = (x² + y²)(x² + y²)
      x²(x² - y²) - y²(x² - y²) + 2x²y² = x²(x² + y²) + y²(x² + y²)
x²(x²) - x²(y²) - y²(x²) + y²(y²) + 2x²y² = x²(x²) + x²(y²) + y²(x²) + y²(y²)
      x⁴ - x²y² - x²y² + y⁴ + 2x²y² = x⁴ + x²y² + x²y² + y⁴
         x⁴ - 2x²y² + y⁴ + 2x²y² = x⁴ + 2x²y² + y⁴
   x⁴ - 2x²y² + 2x²y² + y⁴ = x⁴ + 2x²y² + y⁴
      x⁴ + y⁴ = x⁴ + 2x²y² + y⁴
      - x⁴    - x⁴
   y⁴ = 2x²y² + y⁴
       - y⁴ - y⁴
      0 = 2x²y²
      2    2
      0 = x²y²
      0 = xy

I didn't find the answer to the problem.

A garden snail traveled 1⁄40 of a mile in 1⁄2 an hour. What was the speed of the snail?

Answers

There are several information's of immense importance already given in the question. Based on those information's the answer to the question can be easily deduced.
The total distance that has been traveled by the garden snail in question = 1/40 mile
Time taken by the garden snail to travel the distance given in question = 1/2 hour.
Then
Speed of the snail = Distance traveled/ Time taken
   = (1/40)/(1/2) miles per hour
   = 2/40 miles per hour
   = 1/20 miles per hour
So the speed of the garden snail as can be seen from the above deduction is 1/20 miles per hour. I hope the procedure is simple enough for you to understand.

B) Write 1.74 x 10^4 as an ordinary number.

Answers

Answer:

17400

Step-by-step explanation: i might get this wrong but just do 1.74*10^4 and it should equal 17400

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