The sum of two consecutive integers is 183. What is the smaller integer?

Answers

Answer 1
Answer: 91

Explanation: Since the ones digit ends in a 3, that means the the ones digits of the two consecutive integers must be 1 and 2 or 6 and 7. However, you see 18 in the number 183. 9 + 9 = 18. When you add 6 and 7, you have to carry over one. However, when you add 1 and 2, you do not. Therefore, the two consecutive numbers are 91 and 92. 91 is the smaller integer, so that is the answer.
Answer 2
Answer:

Answer:

yes the answer is 91

Step-by-step explanation:

i took the test and i got that one correct


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Which set of integers is in the right order from least to greatest?-8,8,6,|-7|,5
|-7|,-8,8,6,5
-8,5,6,|-7|,8
5,6,8,-8,|-7|​

Answers

Answer:

-8, 5, 6 , |-7|, 8

Step-by-step explanation:

We can solve the absolute functions to make it easier to determine which set is from least to greatest

-8, 8, 6, 7, 5 x

7, -8, 8, 6, 5

-8, 5, 6, 7, 8

5, 6, 8, -8, 7

Therefore the group of order integers from least to greatest is -8, 5, 6 , |-7|, 8

Multiple Response: Please select all correct answers and click "submitWhich expressions are equivalent to the one below? Check all that applyA- 125.5B- 53 xC. 253x

Answers

The correct answers are A and B.

3+3×3-3+3=
What's the answer
How do you get the answer

Answers

Do each equation in an algebraic way:

3+3×3-3+3=Use PEMDAS:
Multiplication First
Addition Second
Subtraction Third

3+(3·3)-3+3:
(3+9)-3+3:
12-(3+3):
12-6:
Answer: 6

Your answer will NOT be 18.

So final answer is: 6

Hope this helps!

3+(3x3)-3+3
= 3 + 9 - 3 + 3
= 12 - 3 + 3
= 9 + 3
= 12

Do you get it?

What needs to be corrected in the following construction for copying ∠ABC with point D as the vertex?

Answers

To construct an angle bisector for ∠ABC, use a compass and straightedge to create intersecting arcs, connecting the vertex with the intersection point to form the bisector. Avoid changing compass width or inaccurate arc intersections.

Constructing an angle bisector for ∠ABC using only a compass and a straightedge involves a series of precise steps. Here are the instructions along with common mistakes to avoid:

Step-by-Step Instructions:

Draw ∠ABC: Begin by drawing the angle ∠ABC with the given vertex at point B.

Place Compass at Point B: Use your compass and place its needle point (the sharp end) at point B, the vertex of the angle.

Adjust Compass Width: Open the compass to a width that allows you to draw two arcs that intersect both rays of the angle. Ensure the compass width remains fixed during the construction.

Draw Arcs: With the compass set, draw an arc that intersects the first ray, AB. Keep the compass needle fixed at B, and draw another arc that intersects the second ray, BC. Label the points of intersection with the rays as D and E.

Connect B and E: Using your straightedge, draw a straight line that connects point B and point E.

Bisect the Angle: The line BE bisects angle ∠ABC, creating two equal angles, ∠ABE and ∠EBC. Angle ∠ABE is the bisector of ∠ABC.

Common Mistakes to Avoid:

Changing Compass Width: Keeping the compass width consistent is crucial. Changing it during the construction will result in an inaccurate angle bisector.

Inaccurate Arc Intersection: Ensure that the arcs drawn from points B intersect the rays AB and BC accurately at points D and E. Inaccurate intersection points will lead to an incorrect angle bisector.

Not Labeling the Bisector: It's essential to label the constructed angle bisector (∠ABE) to distinguish it from the original angles.

By following these steps carefully and avoiding common mistakes, you can accurately construct an angle bisector for ∠ABC using only a compass and a straightedge.

For more such information on:angle bisector

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The question probable may be:

How do you construct an angle bisector for ∠ABC using only a compass and a straightedge? Provide step-by-step instructions, and highlight any common mistakes to avoid in the construction.

From looking at both the pictures shown for the problems which can be found in the attachment below. I concluded that what needs to be corrected in the following construction for copying ∠ABC with point D as the vertex is answer choice:


C) The third arc should cross the second arc.


I hope this helps, Regards.

If h=2f/m+1 , solve the equation for F. Plz SHOW WORK!!!!

Answers

h=2f/m+1
subtract one from both sides
h-1=2f/m
multiply m to both sides
m*h-1=2f
divide 2 both sides
mh-1/2=F
(the whole left side of the equation is divided by 2 i just cant do it on the computer)
h = (2f)/(m) + 1 \n \n mh = 2f + 1 (re-arranged) \n \n mh - 1 = 2f \n \n f = ((mh - 1))/(2)

He shaded 1/3 of one rectangle and 1/4 of other rectangle. What is the least number of parts into which both rectangles could be divided?

Answers


Rectangle 1: 1/3 shaded

Rectangle 2: 1/4 shaded

First you have to look through each denominators multiples to find the lowest common denominator (LCD).

Multiples of 3: 3, 6, 9, 12, 15

Multiples of 4: 4, 8, 12, 16, 20

As you can see, both numbers are multiples of 12.

Rectangle 1: 1/3 shaded= 4/12 shaded

Rectangle 2: 1/4 shaded= 3/12 shaded

I made equivalent fractions by multiplying both the numerator and the denominator by the same number.

The least number of parts which both rectangles can be divided is 12.

Hope this helped :)