A bicycle is on sale at $12 more than half of the regular price. If the sale price is $75, find the regular price.
Answers
The regular price of the bicycle will be $126.
What is an expression?
Expression in maths is defined as the collection of numbers variables and functions by using signs like addition, subtraction, multiplication, and division.
Numbers (constants), variables, operations, functions, brackets, punctuation, and grouping can all be represented by mathematical symbols, which can also be used to indicate the logical syntax's order of operations and other features.
Given that a bicycle is on sale at $12 more than half of the regular price and the selling price is $75.
The regular price of the bicycle will be calculated as below:-
( P / 2 ) + 12 = 75
P + 24 = 150
P = 150 - 24
P = 126
Therefore, the regular price of the bicycle will be $126.
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let's let
right?
Now you just have to solve from there.
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In Vancouver, the high temperature for the day was 6° C. On the same day, the high temperature in Calgary was −3° C. What was the difference in high temperatures between the two cities?
Answers
Apply the formula for the points M(6, 16) and Z(-1, 14):
which rounded to the nearest tenth is 7.3 (units)
Answer: 7.3 units
Answer 7.3 Units
use the order of operations
first do
16-14
then 6-(-1)
answers
2^2
7^2
then you will do the ebonites on both of them
giving you
4
49
then you add them
4+49
square root 53
square root that and get 7.28
round and get
7.3 units
Answers
Answer: C
Step-by-step explanation:
Answer:c
Step-by-step explanation:
Answers
a(n) = a(1)*r^(n-1), where a(1) is the first term, n is the counter and r is the common ratio.
I first noted that 243 is a power of 3; specifically, 243=3^5, or 243=3(3)^4, or 243=(3^2)(3)^(4-1). Notice that I'm trying here to rewrite 243=3^5 in the form a(n) = a(1)*r^(n-1): a(4) = a(1)(3)^(4-1), or a(4) = a(1)(3)^3 = 243. Then by division we find that a(1) = 243/27 = 9. Is it possible that a(1)=9?
Let's try out our formula a(n)=9(3)^(n-1). Steal n=9 and see whether this formula gives u s 59049:
n(9) = 59049 = 9(3)^(9-1), or 9(3)^8. True or false? 3^8= 6561, and 9(3)^8 = 59049.
YES! That's correct.
Therefore, the desired formula is
a(n) = 9(3)^(n-1). The first term, a(1) is 9(3)^(1-1) = 9(3)^0 = 9*1 = 9.
Final answer:
The first term of the geometric sequence is 3. Calculation is done using the formula for the nth term of a geometric sequence and substituting the given values.
Explanation:
To find the first term of the geometric sequence, one can use the formula for the nth term of a geometric sequence, which is a = arn-1. Here, 'a' is the first term, 'r' is the common ratio and 'n' is the term position. As provided in the table, when n=4, an=243 and when n=9, an=59049. We can setup the equation 243 = a*r3 and 59049 = a*r8. Dividing the second equation by the first we get r5 = 243, leading to r=3. Substitute r=3 into the first equation to find 'a' and we get a= 3.
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Answers
6/10 + 7/12
Not sure how to do?
Answers
Answers
the answer is 8x+12z
your welcome