During his tennis career in singles play, John won 3 fewer tournament A titles than tournament B titles, and 2 more tournament C titles than tournament B titles. If he won 17 of these titles total, how many times did he win each one? How many A titles
How many B titles
How many C titles

Answers

Answer 1
Answer: ok use why they told you.

17=A+B+C & A=B-3 &C=2+B
we only what to work with one variable at a time. 
lucky for us we have an idea of what "A" & "C" are. we can plug those into our first equation respectively. 

SOLVE FOR B

17= (B-3)+B+(2+B)
17=B-3+B+2+B
17=3B-1
17+1=3B
18=3B
18/3=B
6=B  (this means he won 6 B titles)

SOLVE FOR A

A=B-3
A=6-3
A=3

SOLVE FOR C

C=2+B
C=2+6
C=8

CHECK

17=A+B+C
17=3+6+8
17=17

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Solve for x pls help me

Answers

Answer:

90

Step-by-step explanation:

circumference of total circle = 16 pi

16 pi / 4 pi = 4

1 / 4 =25%

1/4 * 360 = 90

3/10 off the normal price 400

Answers

Answer: 120

Step-by-step explanation: 3/10=0.3

0.3*400=120

Please help , i dont understand this at all

Answers

It’s cccccccccccccccccccccc

The difference of two numbers is 18. The sum of the two numbers is 62. Let x be the greater number,and let y be the lesser number

Answers

Answer:

  • x = 40
  • y = 22

Step-by-step explanation:

We know that:

  • x - y = 18
  • x + y = 62

Work:

  • x - y = 18

       x + y = 62

  • => (x + x) + (y - y) = (18 + 62)
  • => 2x + 0 = 80
  • => 2x = 80
  • => x = 40

To find y, let's use any equation in the "we know that" section.

  • => 40 - y = 18
  • => 40 - 18 = y
  • => 22 = y

Now, let's check our work by using the second equation.

Check:

  • x + y = 62
  • => 40 + 22 = 62
  • => 62 = 62 (Proved correct)

Hoped this helped.

BrainiacUser1357

74 3/5 + 19 2/3 = Please Explain

Answers

Ok 74(3)/(5)
So 19(2)/(3)


= 373/5 + 59/3

= ((373 × 3) + (59 × 5)) / (5 × 3) 

= (1119 + 295) / 15

= 1414/15

= 1414/15

= 94 4/15
74 3/5 + 19 2/3
74+19= 93
for 3/5+2/3 we need a common denominator which in this case would be 15 (the product of the two already existing denominators)
3x3=9 (the 3s are first numerator and the second denominator) so the first fraction is 9/15
5x2=10 (the first denominator and the second numerator) so the second fraction would be 10/15
9+10=19 (the numerators in both fractions) so it's 19/15 which we convert to a mixed numeral which is 1 4/15
93+1 4/15=94 4/15

hope this helps :)

How many solutions are there to the equation below? 6x + 30 + 4x=10(x + 3) a. 0 b. infinetely many c. 1

Answers

Answer:

b

Step-by-step explanation:

given

6x + 30 + 4x = 10(x + 3) ← collect like terms on left side

10x + 30 = 10(x + 3) ← distribute parenthesis by 10

10x + 30 = 10x + 30

since both sides are the same , then any value of x will make the equation true.

The equation has infinitely many solutions